Dynamic Programming: Knapsack - Last Stone Weight IIGiven the following code for lastStoneWeightII, what is the returned value when stones = [1, 2, 3]?A1B0C2D3Check Answer
Step-by-Step SolutionStep 1: Calculate total and halfTotal = 6, half = 3. dp array size = 4, dp[0] = true initially.Step 2: Update dp for each stoneFor weight=1: dp[1]=true; for weight=2: dp[3]=true (since dp[1] was true), dp[2]=true; for weight=3: dp[3]=true remains.Step 3: Find largest w ≤ half with dp[w] = truedp[3] is true, so minimal difference = total - 2*3 = 6 - 6 = 0.Final Answer:Option B -> Option BQuick Check:Subset {1,2,3} sums to 6; partition into {3} and {1,2} sums 3 and 3 -> difference 0 [OK]Quick Trick: Check dp array for sums up to half total [OK]Common Mistakes:MISTAKESReturning total instead of minimal differenceOff-by-one error in dp indexingNot iterating backwards in dp updateTrap Explanation:PITFALLCandidates often confuse dp indexing or final sum calculation, leading to off-by-one or wrong difference.Interviewer Note:CONTEXTTests ability to trace DP updates and final result calculation.
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