Dynamic Programming: Knapsack - Integer BreakGiven the following bottom-up DP code for integer break, what is the value of dp[4] after all iterations?A[0, 1, 1, 2, 4]B[0, 1, 1, 3, 6]C[0, 1, 2, 3, 5]D[0, 1, 1, 2, 3]Check Answer
Step-by-Step SolutionSolution:Step 1: Trace dp[2] and dp[3]dp[2] = max(1*1) = 1, dp[3] = max(1*2, 2*1) = 2Step 2: Calculate dp[4]Check splits: j=1 -> max(1,dp[1]) * max(3,dp[3]) = 1*3=3; j=2 -> max(2,dp[2]) * max(2,dp[2])=2*2=4; j=3 -> max(3,dp[3]) * max(1,dp[1])=3*1=3; max is 4, so dp[4]=4Final Answer:Option A -> Option AQuick Check:dp array matches [0,1,1,2,4] [OK]Quick Trick: Trace dp array stepwise for small n [OK]Common Mistakes:MISTAKESOff-by-one in loopsConfusing dp[i] with iTrap Explanation:PITFALLCandidates often miscalculate dp[4] by missing max(j, dp[j]) usage.Interviewer Note:CONTEXTTests ability to mentally execute DP code and understand state transitions
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