Bird
Raised Fist0

What is the time complexity of the bottom-up dynamic programming solution for the integer break problem shown below?

medium🪤 Complexity Trap Q13 of Q15
Dynamic Programming: Knapsack - Integer Break
What is the time complexity of the bottom-up dynamic programming solution for the integer break problem shown below?
def integer_break(n):
    dp = [0] * (n + 1)
    dp[1] = 1
    for i in range(2, n + 1):
        max_product = 0
        for j in range(1, i):
            max_product = max(max_product, max(j, dp[j]) * max(i - j, dp[i - j]))
        dp[i] = max_product
    return dp[n]
AO(n log n) time
BO(n) time
CO(2^n) time
DO(n^2) time
Step-by-Step Solution
  1. Step 1: Identify loops

    Outer loop runs from 2 to n (≈ n iterations). Inner loop runs from 1 to i (up to n iterations).
  2. Step 2: Calculate total operations

    Nested loops yield roughly 1 + 2 + ... + n ≈ n(n+1)/2 = O(n^2) operations.
  3. Final Answer:

    Option D -> Option D
  4. Quick Check:

    Double nested loops with linear bounds -> quadratic time [OK]
Quick Trick: Nested loops with linear bounds usually mean O(n²) [OK]
Common Mistakes:
MISTAKES
  • Confusing with O(n) by ignoring inner loop
  • Thinking recursion stack adds exponential time here
Trap Explanation:
PITFALL
  • Some candidates mistake the problem for linear due to single dp array or confuse with brute force exponential time.
Interviewer Note:
CONTEXT
  • Checks understanding of DP time complexity vs brute force recursion
Master "Integer Break" in Dynamic Programming: Knapsack

3 interactive learning modes - each teaches the same concept differently

Want More Practice?

15+ quiz questions · All difficulty levels · Free

Free Signup - Practice All Questions
More Dynamic Programming: Knapsack Quizzes