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Rank in Subset (Gender/Category)

Introduction

Many ranking problems give an overall rank plus a rank within a subgroup (for example, boys/girls, division A/division B, or class-section). These questions test your ability to separate subgroup counts from overall counts and convert between them quickly.

Mastering this pattern helps you answer how many people of the other group are ahead/behind, and to place subgroup ranks in the context of the whole class.

Pattern: Rank in Subset (Gender/Category)

Pattern

Key concept: Use overall rank to find total people ahead (overall - 1). Subtract subgroup-ahead to get other-group-ahead.

Core relations:

  • People ahead overall = Overall rank - 1.
  • People ahead in same subgroup = Subgroup rank - 1.
  • People from the other group ahead = (Overall people-ahead) - (Same-group people-ahead).
  • If needed, convert counts back to ranks by adding 1 (Rank = people-ahead + 1).

Step-by-Step Example

Question

Riya is 10th overall in a class and 4th among girls. How many boys are ahead of her?

Solution

  1. Step 1: Find overall people ahead

    Overall rank = 10 → people ahead overall = 10 - 1 = 9.
  2. Step 2: Find girls ahead

    Riya is 4th among girls → girls ahead = 4 - 1 = 3.
  3. Step 3: Compute boys ahead

    Boys ahead = overall people-ahead - girls ahead = 9 - 3 = 6.
  4. Final Answer:

    6 boys are ahead of Riya.
  5. Quick Check:

    3 girls + 6 boys = 9 people ahead → Riya is 10th overall ✅

Quick Variations

1. If given subgroup rank and number of people in subgroup, you can find subgroup-ahead and subgroup-behind.

2. If asked how many from other group are behind, compute total-other-group = total - subgroup-size (if total known), then subtract other-group-ahead.

3. When two subgroup ranks are given for different people, convert both to overall positions (people-ahead + 1) before comparing.

4. If overall rank refers to top and subgroup rank refers to bottom (or vice versa), convert one reference to the other first (use people-ahead/people-behind).

Trick to Always Use

  • Step 1 → Convert ranks to "people ahead" form (rank - 1) for both overall and subgroup.
  • Step 2 → Subtract same-group ahead from overall ahead to get other-group ahead.
  • Step 3 → Convert counts back to rank if the question asks for a rank (add 1).

Summary

Summary

  • Convert all ranks to "people ahead" (rank - 1) to compare across groups easily.
  • Other-group-ahead = (Overall people-ahead) - (Same-group people-ahead).
  • To get a rank from a people-count, add 1 (Rank = people-ahead + 1).
  • When totals are known, subgroup sizes allow you to compute how many of the other group are behind or ahead.

Example to remember:
If someone is 12th overall and 5th in subgroup → people-ahead overall = 11, subgroup-ahead = 4 → 11 - 4 = 7 from the other group are ahead.

Practice

(1/5)
1. In a class, Sita ranks 12th overall and 5th among girls. How many boys are ahead of her?
easy
A. 7
B. 6
C. 8
D. 9

Solution

  1. Step 1: Find overall people ahead

    Overall rank = 12 → 12 - 1 = 11 people ahead.
  2. Step 2: Find girls ahead

    5th among girls → 5 - 1 = 4 girls ahead.
  3. Step 3: Compute boys ahead

    11 - 4 = 7 boys ahead.
  4. Final Answer:

    7 boys → Option A
  5. Quick Check:

    4 girls + 7 boys = 11 people ahead ✅
Hint: Boys ahead = (Overall rank - 1) - (Girl rank - 1).
Common Mistakes: Forgetting to subtract 1 from both ranks before comparing.
2. Ravi is 15th in a class and 7th among boys. How many girls are ahead of him?
easy
A. 7
B. 8
C. 9
D. 10

Solution

  1. Step 1: People ahead overall

    15 - 1 = 14.
  2. Step 2: Boys ahead

    7 - 1 = 6.
  3. Step 3: Girls ahead

    14 - 6 = 8 girls ahead.
  4. Final Answer:

    8 girls → Option B
  5. Quick Check:

    6 boys + 8 girls = 14 people ahead ✅
Hint: Other group ahead = (Overall rank - 1) - (Same group rank - 1).
Common Mistakes: Mixing up subgroup and overall ranks.
3. In a test, Arjun is 18th overall and 10th among boys. How many girls are ahead of him?
easy
A. 7
B. 9
C. 8
D. 10

Solution

  1. Step 1: Overall people ahead

    18 - 1 = 17.
  2. Step 2: Boys ahead

    10 - 1 = 9.
  3. Step 3: Girls ahead

    17 - 9 = 8 girls ahead.
  4. Final Answer:

    8 girls → Option C
  5. Quick Check:

    9 boys + 8 girls = 17 people ahead ✅
Hint: Subtract boys ahead from total people ahead to get girls ahead.
Common Mistakes: Using ranks directly instead of people-ahead counts.
4. Neha ranks 9th overall and 3rd among girls. How many boys are ahead of her?
medium
A. 6
B. 5
C. 7
D. 8

Solution

  1. Step 1: People ahead overall

    9 - 1 = 8.
  2. Step 2: Girls ahead

    3 - 1 = 2.
  3. Step 3: Boys ahead

    8 - 2 = 6.
  4. Final Answer:

    6 boys → Option A
  5. Quick Check:

    2 girls + 6 boys = 8 ahead ✅
Hint: Subtract subgroup-ahead from total-ahead to find other-group-ahead.
Common Mistakes: Subtracting ranks instead of people-ahead counts.
5. In a merit list, Priya is 14th overall and 8th among girls. How many boys are ahead of her?
medium
A. 5
B. 8
C. 7
D. 6

Solution

  1. Step 1: People ahead overall

    14 - 1 = 13.
  2. Step 2: Girls ahead

    8 - 1 = 7.
  3. Step 3: Boys ahead

    13 - 7 = 6.
  4. Final Answer:

    6 boys → Option D
  5. Quick Check:

    7 girls + 6 boys = 13 ahead ✅
Hint: Other group ahead = (Overall rank - 1) - (Subgroup rank - 1).
Common Mistakes: Using given ranks instead of converting to people-ahead.

Mock Test

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