Reasoning Ability - Calendar ProblemsWhich year will have the same calendar as 1999?A2010B2011C2012D2013Check Answer
Step-by-Step SolutionStep 1: Identify type1999 is ordinary.Step 2: Count odd days for 1999→2010 (years 1999–2009)Leap years: 2000, 2004, 2008 → 3 leaps; ordinary = 8.Odd days = (8×1)+(3×2)=8+6=14 → 14 mod 7 = 0.Final Answer:2010 → Option AQuick Check:Odd days 14 ≡ 0 and both ordinary → calendars match ✅Quick Trick: Ordinary year +11 is a common repeat when three leaps occur inside the interval.Common Mistakes:MISTAKESConfusing 11- vs 12-year gaps for century-adjacent years.
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