Reasoning Ability - Calendar Problems
How many odd days are there in 180 years?
How many odd days are there in 180 years?
easy Q4 of 15
Step-by-Step Solution
Step 1: Break 180 = 100 + 80
100 years = 5 odd days.Step 2: Compute for 80 years
Leap years = 20, Ordinary = 60 → odd days = (20×2)+(60×1)=100.Step 3: Combine and reduce
Total = 5 + 100 = 105 → 105 mod 7 = 0.Final Answer:
0 odd days → Option CQuick Check:
105 mod 7 = 0 → verified.
Quick Trick: Break into century + remainder, convert remainder to odd days.
Common Mistakes:
MISTAKES- Skipping mod 7 reduction.
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