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Same Calendar Year Pair

Introduction

Some years share exactly the same calendar - meaning every date falls on the same weekday in both years. This pattern is useful for quickly finding matching years without recalculating every date, and it appears often in competitive reasoning questions.

Pattern: Same Calendar Year Pair

Pattern

Two years have identical calendars when the total odd days between them ≡ 0 (mod 7), and both years are the same type (both leap or both ordinary).

Key rules:

  • Ordinary year → adds 1 odd day to the next year's same date.
  • Leap year → adds 2 odd days to the next year's same date.
  • Try common gaps: non-leap years often repeat after 6 or 11 years; leap years commonly repeat after 28 years (verify around centuries).

Step-by-Step Example

Question

Which year will have the same calendar as 2017?

Solution

  1. Step 1: Identify base year type

    2017 is a non-leap year (ordinary). The repeating year must also be an ordinary year.
  2. Step 2: Accumulate odd days until the sum ≡ 0 (mod 7)

    We count odd days for the years following 2017 up to the candidate year:
    Years 2017-2022: 2017(1) + 2018(1) + 2019(1) + 2020(2) + 2021(1) + 2022(1) = 7 odd days.
  3. Step 3: Check odd day sum and year type

    Total odd days = 7 → 7 ≡ 0 (mod 7). The next year is 2023, which is also a non-leap year. This confirms the match.
  4. Final Answer:

    2023
  5. Quick Check:

    2017 → 2023 is a 6-year gap which works when only one leap year (2020) is included. ✅

Quick Variations

1. Find previous year with same calendar (count backwards using -1 for ordinary, -2 for leap).

2. For leap-year pairs, verify 29 Feb presence; leap-year calendars must both be leap.

3. Near century boundaries, test 6/11/12-year gaps explicitly rather than relying on heuristics.

Trick to Always Use

  • Step 1 → Determine base year type (leap or ordinary).
  • Step 2 → Add odd days year-by-year (ordinary = +1, leap = +2) until sum ≡ 0 (mod 7).
  • Step 3 → Confirm the candidate year has same leap status; if yes, calendars match.

Summary

Summary

  • Two years have the same calendar if total odd days between them ≡ 0 (mod 7).
  • Leap years repeat after 28 years; non-leap years usually after 6 or 11 years.
  • Always check that both are the same type (leap or ordinary).
  • Use odd day summation for precise verification instead of relying on memory-based shortcuts.

Example to remember:
2017 and 2023 → both non-leap → same calendar ✅

Practice

(1/5)
1. Which year will have the same calendar as 2010?
easy
A. 2021
B. 2022
C. 2023
D. 2024

Solution

  1. Step 1: Identify base year type

    2010 is an ordinary (non-leap) year.
  2. Step 2: Count years until total odd days ≡ 0 (mod 7)

    Between 2010-2020: Leap years = 2012, 2016, 2020 (3), Ordinary years = 8.
    Odd days = (8×1) + (3×2) = 14 → 14 ≡ 0 (mod 7).
  3. Step 3: Verify type match

    2010 and 2021 are both ordinary years → calendars match.
  4. Final Answer:

    2021 → Option A
  5. Quick Check:

    Total odd days = 0 mod 7, both non-leap ✅
Hint: Add 1 for each ordinary year and 2 for each leap year until total ≡ 0 (mod 7).
Common Mistakes: Choosing a nearby year without verifying odd-day remainder.
2. The calendar for 2003 will be the same as for which year?
easy
A. 2008
B. 2014
C. 2009
D. 2011

Solution

  1. Step 1: Identify base year type

    2003 is a non-leap year.
  2. Step 2: Count until total odd days ≡ 0 (mod 7)

    2003-2013: Leap years = 2004, 2008, 2012 (3), Ordinary = 8.
    Odd days = (8×1) + (3×2) = 14 → 14 ≡ 0 (mod 7).
  3. Step 3: Verify next year

    Next year is 2014, which is also ordinary → calendars match.
  4. Final Answer:

    2014 → Option B
  5. Quick Check:

    Odd day sum = 14 ≡ 0 → calendars align ✅
Hint: Non-leap cycles often repeat after 11 years; always include leap counts.
Common Mistakes: Forgetting to check the candidate year's leap status.
3. Which year will have the same calendar as 2000 (a leap year)?
easy
A. 2024
B. 2020
C. 2028
D. 2032

Solution

  1. Step 1: Identify year type

    2000 is a leap year (divisible by 400).
  2. Step 2: Use 28-year leap repetition rule

    Leap years commonly repeat every 28 years → 2000 + 28 = 2028.
  3. Step 3: Verify type match

    2028 is also a leap year → calendars match.
  4. Final Answer:

    2028 → Option C
  5. Quick Check:

    Leap → 28-year cycle → 2028 ✅
Hint: Leap years usually repeat after 28 years unless a century exception intervenes.
Common Mistakes: Choosing a 24-year gap (2024) without checking full-cycle alignment.
4. Which year’s calendar will be the same as that of 2015?
medium
A. 2025
B. 2024
C. 2023
D. 2026

Solution

  1. Step 1: Identify type

    2015 is a non-leap year.
  2. Step 2: Check 11-year rule

    From 2015 to 2026: Leap years = 2016, 2020, 2024 (3), Ordinary = 8.
    Odd days = (8×1) + (3×2) = 14 → 14 ≡ 0 (mod 7).
  3. Final Answer:

    2026 → Option D
  4. Quick Check:

    2015 → 2026 = 11 years; both non-leap ✅
Hint: Non-leap years often repeat after 6 or 11 years depending on intervening leap years.
Common Mistakes: Assuming the nearest 6-year gap always works without checking leap counts.
5. Find the next year after 2004 that will have the same calendar as 2004 (a leap year).
medium
A. 2028
B. 2032
C. 2036
D. 2040

Solution

  1. Step 1: Identify base year type

    2004 is a leap year (divisible by 4 and not a century exception).
  2. Step 2: Use the 28-year leap-cycle heuristic

    Leap-year calendars typically repeat after 28 years because the odd-day total over 28 years equals a multiple of 7.
  3. Step 3: Verify odd days (2004 → 2032)

    Count the 28 years from 2004 up to 2031: leap years = 2004, 2008, 2012, 2016, 2020, 2024, 2028 → 7 leaps; ordinary = 21.
    Odd days = (21 × 1) + (7 × 2) = 21 + 14 = 35 → 35 mod 7 = 0.
  4. Final Answer:

    2032 → Option B
  5. Quick Check:

    Odd days total 35 ≡ 0 (mod 7) and both years are leap years → calendars match ✅
Hint: For leap-year repeats, check +28 years first; verify by counting 7 leap years in the 28-year block to get 35 odd days → 0 mod 7.
Common Mistakes: Choosing 24-year or 20-year gaps without verifying that the odd-day sum ≡ 0 (mod 7).

Mock Test

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