Reasoning Ability - Calendar ProblemsWhich year will have the same calendar as 2020 (a leap year)?A2048B2040C2032D2052Check Answer
Step-by-Step SolutionStep 1: Base year type2020 is a leap year.Step 2: Use 28-year cycleLeap-year calendars typically repeat after 28 years because the total odd days over 28 years = 35, which is divisible by 7. So check 2020 + 28 = 2048.Step 3: Verify odd days (2020 → 2048)In 28 years there are 7 leap years and 21 ordinary years → odd days = (21 × 1) + (7 × 2) = 21 + 14 = 35 → 35 mod 7 = 0, so the calendars align.Final Answer:2048 → Option AQuick Check:Both 2020 and 2048 are leap years and the 28-year odd-day total is 35 ≡ 0 (mod 7) ✅Quick Trick: For leap years, check +28 years first and confirm the odd-day sum is a multiple of 7.Common Mistakes:MISTAKESPicking 2032 or 2040 (shorter gaps) without verifying odd-day remainder equals 0.
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