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Geometric Progression (G.P.) – nth Term

Introduction

A Geometric Progression (G.P.) is a sequence of numbers where each term after the first is obtained by multiplying the previous term by a fixed non-zero number called the common ratio (r). Understanding the nth term formula of a G.P. helps in finding any specific term in the sequence without listing all preceding ones.

Pattern: Geometric Progression (G.P.) – nth Term

Pattern

The nth term (Tₙ) of a geometric progression is given by:

Tₙ = a × rⁿ⁻¹

Here, a = first term, r = common ratio, and n = number of the term.

Step-by-Step Example

Question

Find the 7th term of the G.P. 2, 6, 18, 54, …

Solution

  1. Step 1: Identify a, r, and n

    First term a = 2. Common ratio r = 6 ÷ 2 = 3. Required term n = 7.

  2. Step 2: Apply the nth term formula

    Tₙ = a × rⁿ⁻¹ = 2 × 3⁶ = 2 × 729 = 1458.

  3. Final Answer:

    The 7th term of the G.P. is 1458.

  4. Quick Check:

    6th term = 486, multiplying by r = 3 → 486 × 3 = 1458 ✅

Quick Variations

1. Common ratio r can be a fraction (decreasing G.P.).

2. When terms alternate in sign, r is negative.

3. If any two terms are known, you can find r using r = (T₂ / T₁) or r = (Tₙ / Tₘ)^(1/(n-m)).

Trick to Always Use

  • Step 1: Always find r first using any two consecutive terms.
  • Step 2: Substitute in Tₙ = a × rⁿ⁻¹ carefully - exponent mistakes are common.

Summary

Summary

In a Geometric Progression (G.P.):

  • The ratio between consecutive terms is constant.
  • The nth term formula is Tₙ = a × rⁿ⁻¹.
  • If r > 1 → sequence increases rapidly; if 0 < r < 1 → sequence decreases.
  • For alternating sign series, r is negative.

Practice

(1/5)
1. Find the 6th term of the G.P.: 3, 6, 12, 24, …
easy
A. 72
B. 96
C. 192
D. 384

Solution

  1. Step 1: Identify a, r and n

    First term a = 3, common ratio r = 6 ÷ 3 = 2, and term number n = 6.

  2. Step 2: Apply the formula Tₙ = a × rⁿ⁻¹

    T₆ = 3 × 2⁵ = 3 × 32 = 96.

  3. Final Answer:

    The 6th term is 96 → Option B.

  4. Quick Check:

    5th term = 48 → 48 × 2 = 96 ✅

Hint: Multiply the first term by rⁿ⁻¹ directly.
Common Mistakes: Using n instead of (n-1) in the exponent.
2. Find the 5th term of the G.P.: 2, 10, 50, 250, …
easy
A. 1250
B. 2500
C. 6250
D. 3125

Solution

  1. Step 1: Identify a, r and n

    First term a = 2, common ratio r = 10 ÷ 2 = 5, and n = 5.

  2. Step 2: Use Tₙ = a × rⁿ⁻¹

    T₅ = 2 × 5⁴ = 2 × 625 = 1250.

  3. Final Answer:

    The 5th term is 1250 → Option A.

  4. Quick Check:

    4th term = 250 → 250 × 5 = 1250 ✅

Hint: Compute powers of r first for large ratios to avoid mistakes.
Common Mistakes: Raising r to n instead of (n-1).
3. Find the 8th term of the G.P.: 81, 27, 9, 3, …
easy
A. 1
B. 1/3
C. 1/9
D. 1/27

Solution

  1. Step 1: Identify a, r and n

    First term a = 81, common ratio r = 27 ÷ 81 = 1/3, and n = 8.

  2. Step 2: Apply the nth term formula

    T₈ = 81 × (1/3)⁷ = 81 ÷ 3⁷ = 81 ÷ 2187 = 1/27.

  3. Final Answer:

    The 8th term is 1/27 → Option D.

  4. Quick Check:

    Each term divides by 3; continuing the pattern gives 1/27 ✅

Hint: When r < 1, think in terms of division by the denominator of r.
Common Mistakes: Multiplying instead of dividing when r is a fraction.
4. If the 3rd term of a G.P. is 24 and the 5th term is 216, find the common ratio.
medium
A. 2
B. 4
C. 3
D. 5

Solution

  1. Step 1: Express the given terms in terms of a and r

    T₃ = ar² = 24 and T₅ = ar⁴ = 216.

  2. Step 2: Divide T₅ by T₃ to eliminate a

    (ar⁴) / (ar²) = r² = 216 / 24 = 9.

  3. Step 3: Take square root to find r

    r = √9 = 3.

  4. Final Answer:

    The common ratio is 3 → Option C.

  5. Quick Check:

    If r = 3, then multiplying 24 by 9 gives 216 ✅

Hint: Divide non-consecutive terms to get r^(difference in indices), then root accordingly.
Common Mistakes: Forgetting to take the appropriate root when powers appear.
5. If the 2nd term of a G.P. is 6 and the 5th term is 162, find the 1st term.
medium
A. 2
B. 3
C. 4
D. 5

Solution

  1. Step 1: Write the given terms using a and r

    T₂ = ar = 6 and T₅ = ar⁴ = 162.

  2. Step 2: Divide to find r³

    (ar⁴) / (ar) = r³ = 162 / 6 = 27 ⇒ r = 3.

  3. Step 3: Back-substitute to find a

    a = T₂ / r = 6 / 3 = 2.

  4. Final Answer:

    The first term is 2 → Option A.

  5. Quick Check:

    Check T₅ = 2 × 3⁴ = 2 × 81 = 162 ✅

Hint: Use division of terms to find powers of r, then compute a from one term.
Common Mistakes: Mistakes when isolating r³ or when dividing to find a.

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