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Difference Series (Finding Common Difference or Missing Terms)

Introduction

A Difference Series is a sequence where each term differs from the previous one by a (usually) consistent amount. Identifying the common difference or the missing terms is a frequent exam skill - it helps decode patterns quickly in number series, sequences and reasoning problems.

This pattern is important because it trains you to spot linear patterns, recover missing information, and check consistency in series questions.

Pattern: Difference Series (Finding Common Difference or Missing Terms)

Pattern

Key idea: If the difference between consecutive terms is constant, the sequence is an Arithmetic Progression (A.P.) with common difference d.

nth term formula (when a is first term and d is common difference):
Tₙ = a + (n - 1)·d

To find d: subtract any term from the next one: d = T₂ - T₁ = T₃ - T₂ = ….
To find a missing term: use the nth-term formula or fill sequentially using d.

Step-by-Step Example

Question

Find the missing term in the series: 7, __, 15, 19, 23.

Solution

  1. Step 1: Inspect consecutive differences

    Compute differences where possible: 15 - ? and 19 - 15 = 4, 23 - 19 = 4. The last two differences are 4, so the common difference is likely d = 4.

  2. Step 2: Backfill missing term using d

    Since 15 - d = missing term → 15 - 4 = 11. Check with first term: 7 → 7 + 4 = 11 (consistent).

  3. Step 3: Write the completed series

    7, 11, 15, 19, 23.

  4. Final Answer:

    Missing term = 11.

  5. Quick Check:

    All consecutive differences: 11 - 7 = 4, 15 - 11 = 4, 19 - 15 = 4, 23 - 19 = 4 ✅

Quick Variations

1. Forward fill: Given a and d, produce terms using Tₙ = a + (n-1)d.

2. Backward fill: Given later terms, subtract d repeatedly to find earlier missing terms.

3. Multiple missing slots: Use index positions (e.g., if positions 2 and 4 missing) and the nth-term formula to set equations and solve.

4. Non-constant apparent differences: If differences vary, check second differences - constant second differences indicate a quadratic pattern (not A.P.).

Trick to Always Use

  • Step 1 → Compute simple differences: subtract adjacent known terms to guess d.
  • Step 2 → Confirm consistency: check at least two gaps to ensure d is constant.
  • Step 3 → Use nth-term formula for non-adjacent misses: Tₙ = a + (n-1)d and solve for unknowns.

Summary

Summary

Key takeaways for Difference Series:

  • Difference Series are usually A.P.s - identify the common difference d by subtracting consecutive terms.
  • Use Tₙ = a + (n - 1)d to compute any term or solve for missing ones using positions.
  • When differences are not constant, check second differences to detect non-linear patterns (quadratic sequences).
  • Always perform a quick check by recomputing consecutive differences after filling missing values.

Practice

(1/5)
1. Find the common difference in the series: 3, 7, 11, 15, 19.
easy
A. 4
B. 3
C. 5
D. 6

Solution

  1. Step 1: Compute consecutive differences

    7 - 3 = 4, 11 - 7 = 4, 15 - 11 = 4, 19 - 15 = 4.

  2. Step 2: Confirm constant difference

    All differences equal 4, so common difference d = 4.

  3. Final Answer:

    Common difference = 4 → Option A.

  4. Quick Check:

    Adding 4 repeatedly: 3 → 7 → 11 → 15 → 19 ✅

Hint: Subtract any term from the next to find d.
Common Mistakes: Doing differences in reverse order and getting negative values.
2. Find the missing term in the series: 5, __, 13, 17, 21.
easy
A. 9
B. 7
C. 8
D. 11

Solution

  1. Step 1: Observe known consecutive differences

    17 - 13 = 4 and 21 - 17 = 4, so likely common difference d = 4.

  2. Step 2: Back-calculate the missing term

    13 - d = 13 - 4 = 9. Also check: 5 + 4 = 9 (consistent).

  3. Final Answer:

    Missing term = 9 → Option A.

  4. Quick Check:

    Sequence becomes 5, 9, 13, 17, 21 - all steps +4 ✅

Hint: If later gaps are equal, use that d to backfill earlier blanks.
Common Mistakes: Assuming varying differences without checking adjacent gaps.
3. Find the 6th term of the series: 2, 5, 8, 11, 14, …
easy
A. 16
B. 17
C. 15
D. 18

Solution

  1. Step 1: Identify first term and common difference

    First term a = 2, common difference d = 3 (5 - 2 = 3).

  2. Step 2: Use nth-term formula

    Tₙ = a + (n - 1)d ⇒ T₆ = 2 + (6 - 1)×3 = 2 + 15 = 17.

  3. Final Answer:

    6th term = 17 → Option B.

  4. Quick Check:

    Sequence: 2, 5, 8, 11, 14, 17 - confirms ✅

Hint: Use Tₙ = a + (n-1)d to jump to any term quickly.
Common Mistakes: Using n×d instead of (n-1)d when applying the formula.
4. The 1st term of an A.P. is 10, and its 6th term is 25. Find the common difference.
medium
A. 2.5
B. 3.5
C. 3
D. 4

Solution

  1. Step 1: Use nth-term formula

    Tₙ = a + (n - 1)d. Substitute T₆ = 25, a = 10: 25 = 10 + (6 - 1)d.

  2. Step 2: Solve for d

    25 - 10 = 5d ⇒ 15 = 5d ⇒ d = 3.

  3. Final Answer:

    Common difference = 3 → Option C.

  4. Quick Check:

    Sequence: 10, 13, 16, 19, 22, 25 - differences = 3 ✅

Hint: d = (Tₙ - a)/(n - 1) when a and Tₙ are known.
Common Mistakes: Dividing by n instead of (n - 1).
5. In a series, the 4th term is 20 and the 8th term is 36. Find the common difference.
medium
A. 3
B. 5
C. 6
D. 4

Solution

  1. Step 1: Use difference of nth terms

    T₈ - T₄ = (a + 7d) - (a + 3d) = 4d.

  2. Step 2: Substitute values and solve

    36 - 20 = 4d ⇒ 16 = 4d ⇒ d = 4.

  3. Final Answer:

    Common difference = 4 → Option D.

  4. Quick Check:

    Four-term gap × 4 = 16 matches 36 - 20 ✅

Hint: When indices differ by k, d = (T_{i+k} - T_i)/k.
Common Mistakes: Dividing the term gap by the total number of terms instead of the interval k.

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