Raised Fist0

Successive Profit & Loss

Start learning this pattern below

Jump into concepts and practice - no test required

or
Recommended
Test this pattern10 questions across easy, medium, and hard to know if this pattern is strong

Introduction

In aptitude exams, sometimes articles are sold through successive transactions, where a profit or loss is made more than once on the same item. For example: a shopkeeper first sells an article to another trader at a profit, and that trader sells it again at another profit/loss.

These problems cannot be solved by directly adding/subtracting percentages. Instead, we apply a specific formula for successive percentages.

Pattern: Successive Profit & Loss

Pattern: Successive Profit & Loss

If a profit/loss of x% is followed by a profit/loss of y%, the net effect is:

Net % = x + y + (x × y) / 100

Here, treat profit as positive (+) and loss as negative (-). Final result > 0 → Net profit. Final result < 0 → Net loss.

Step-by-Step Example

Question

A trader sells an article at a profit of 20%, and the next buyer sells it again at a loss of 10%. Find the overall profit or loss percentage.

Options:

  • A. 8% overall profit
  • B. 10% overall profit
  • C. 6% overall profit
  • D. No profit, no loss

Solution

  1. Step 1: Identify the successive changes.

    Successive changes are +20% (profit) and -10% (loss).
  2. Step 2: Apply the successive-percentage formula.

    Net % = 20 + (-10) + (20 × -10) / 100 = 20 - 10 - 2 = +8%.
  3. Step 3: Interpret the result.

    Positive result → 8% overall profit.
  4. Final Answer:

    8% overall profit → Option A
  5. Step 4: Quick Check (verify with CP = 100).

    Assume CP = 100 → after +20% = 120 → after -10% = 120 - 12 = 108 → Net = 108 - 100 = 8 → 8% profit ✅

Quick Variations

Case 1: Two successive profits (say +10% and +20%). Net % = 10 + 20 + (10×20)/100 = 32% profit.

Case 2: Two successive losses (say -10% and -20%). Net % = -10 - 20 + (-10×-20)/100 = -28% (net loss).

Case 3: One profit, one loss (say +25%, -20%). Net % = 25 - 20 + (25×-20)/100 = 25 - 20 - 5 = 0 → No overall gain/loss.

Trick to Always Use

  • Use formula: Net % = x + y + (x×y)/100.
  • Assign positive for profit, negative for loss.
  • If unsure, assume CP = 100 and calculate step by step.
  • Quickly identify: Positive = Profit, Negative = Loss.

Summary

  • Use the successive-percentage formula: Net % = x + y + (x×y)/100.
  • Assign + for profits and - for losses before applying the formula.
  • Verify results by assuming CP = 100 and computing successive SP values.
  • Interpret sign: positive → overall profit; negative → overall loss.

Example to remember:
+20% followed by -10% → Net % = 20 - 10 + (20×-10)/100 = 8% profit

Practice

(1/5)
1. A shopkeeper gains 10% on one article and again 20% on reselling it. Find the overall gain percentage.
easy
A. 30%
B. 32%
C. 28%
D. 25%

Solution

  1. Step 1: Identify both profit percentages.

    Gains = +10% and +20%.
  2. Step 2: Apply successive percentage formula.

    Net % = 10 + 20 + (10 × 20)/100 = 30 + 2 = 32%.
  3. Final Answer:

    32% profit → Option B
  4. Quick Check:

    Assume CP = 100 → After +10% = 110 → After +20% = 132 → Profit = 32% ✅
Hint: Use Net % = x + y + (x×y)/100.
Common Mistakes: Simply adding 10% + 20% = 30% without the product term.
2. An article is sold at a loss of 15% and then again at a loss of 10%. Find the overall loss percentage.
easy
A. 25%
B. 26.5%
C. 23.5%
D. 24%

Solution

  1. Step 1: Identify both losses.

    Losses = -15% and -10%.
  2. Step 2: Apply successive percentage formula.

    Net % = -15 - 10 + (-15 × -10)/100 = -25 + 1.5 = -23.5%.
  3. Final Answer:

    23.5% loss → Option C
  4. Quick Check:

    CP = 100 → After -15% = 85 → After -10% = 76.5 → Loss = 23.5% ✅
Hint: Take loss as negative in the formula.
Common Mistakes: Adding -15% and -10% directly = -25% without correction.
3. A trader sells at a profit of 25% and then at a loss of 20%. Find the overall result.
easy
A. 5% profit
B. 2% loss
C. 0% (no gain, no loss)
D. 6% profit

Solution

  1. Step 1: Identify profit and loss.

    Profit = +25%, Loss = -20%.
  2. Step 2: Apply successive change formula.

    Net % = 25 - 20 + (25 × -20)/100 = 5 - 5 = 0%.
  3. Final Answer:

    No profit, no loss → Option C
  4. Quick Check:

    CP = 100 → After +25% = 125 → After -20% = 100 → back to CP ✅
Hint: If net % = 0, then it’s no profit/loss.
Common Mistakes: Forgetting the product term and wrongly concluding profit or loss.
4. An article is first sold at 30% profit, then at 40% profit. Find the overall profit percentage.
medium
A. 70%
B. 82%
C. 60%
D. 72%

Solution

  1. Step 1: Identify profit percentages.

    Profits = +30% and +40%.
  2. Step 2: Apply successive percentage formula.

    Net % = 30 + 40 + (30 × 40)/100 = 70 + 12 = 82%.
  3. Final Answer:

    82% profit → Option B
  4. Quick Check:

    CP = 100 → After +30% = 130 → After +40% = 182 → Profit = 82% ✅
Hint: Always add x, y and their product/100.
Common Mistakes: Stopping at 30 + 40 = 70%, missing the product term.
5. A man sells a good at 12% profit and then again at 15% loss. Find the net result.
medium
A. 5% loss
B. 3% profit
C. 4.8% loss
D. 2% loss

Solution

  1. Step 1: Identify profit and loss.

    Profit = +12%, Loss = -15%.
  2. Step 2: Apply successive percentage formula.

    Net % = 12 - 15 + (12 × -15)/100 = -3 - 1.8 = -4.8%.
  3. Final Answer:

    4.8% loss → Option C
  4. Quick Check:

    CP = 100 → After +12% = 112 → After -15% = 95.2 → Loss = 4.8% ✅
Hint: Use Net % = x + y + (x×y)/100 with signs.
Common Mistakes: Adding +12 and -15 only = -3%, missing the correction factor.