Introduction
False-weights (cheat) problems appear frequently in aptitude tests. A seller (or buyer) gives less (or takes more) quantity than claimed while charging the price for the claimed quantity. The trick is to convert the weight cheat into an effective price-per-unit change and then compute profit or loss.
Two common setups:
- Seller gives less quantity than claimed but charges full price → implicit gain.
- Buyer takes more quantity than paid for → implicit loss to the seller.
Pattern: False Weights / Cheat Problems
Pattern
Key idea: Treat the declared quantity (e.g. 1 kg) as the unit of sale. Find the actual quantity given for that unit. Convert that to an effective price per true unit, then compare with cost price per true unit.
Formula (declared = 1 unit):
- Actual quantity given = r unit (where r < 1 if cheating).
- Effective SP per true unit = Price charged ÷ actual quantity given.
- Profit% = ((Effective SP per unit - CP per unit) ÷ CP per unit) × 100.
- If selling at cost price (SP = CP) but giving r < 1, then Gain% = (1/r - 1) × 100.
Step-by-Step Example
Question
A shopkeeper sells sugar at the price of ₹40 per kg but uses a weight such that a buyer receives only 900 g when paying for 1 kg. If his cost price is ₹30 per kg, find his profit percentage.
Options:
- A. 48.15%
- B. 45.00%
- C. 40.00%
- D. 50.00%
Solution
-
Step 1: Convert units to true kg
900 g = 900 ÷ 1000 = 0.9 kg. -
Step 2: Compute effective selling price per true kg
Customer pays ₹40 for 0.9 kg. Effective SP per kg = 40 ÷ 0.9 = 44.44. -
Step 3: Calculate profit per kg
CP per kg = ₹30. Profit per kg = 44.44 - 30 = 14.44. -
Step 4: Compute profit percentage
Profit% = (14.44 ÷ 30) × 100 ≈ 48.15%. -
Final Answer:
48.15% → Option A -
Quick Check:
CP for 0.9 kg = 30 × 0.9 = ₹27. SP for 0.9 kg = ₹40. Profit = 40 - 27 = ₹13. Profit% = (13 ÷ 27) × 100 = 48.15% ✅
Question
A merchant claims to sell 1 kg of rice at ₹50. He actually gives 950 g for each "1 kg". If his cost price is ₹40 per kg, find his profit percentage.
Options:
- A. 30.00%
- B. 31.58%
- C. 32.00%
- D. 28.00%
Solution
-
Step 1: Convert actual quantity to kg
950 g = 950 ÷ 1000 = 0.95 kg. -
Step 2: Compute effective selling price per true kg
Customer pays ₹50 for 0.95 kg. Effective SP per kg = 50 ÷ 0.95 = 52.63. -
Step 3: Compute profit per kg
CP per kg = ₹40. Profit per kg = 52.63 - 40 = 12.63. -
Step 4: Compute profit percentage
Profit% = (12.63 ÷ 40) × 100 ≈ 31.58%. -
Final Answer:
31.58% → Option B -
Quick Check:
CP for 0.95 kg = 40 × 0.95 = ₹38. SP for 0.95 kg = ₹50. Profit = 12. Profit% = (12 ÷ 38) × 100 = 31.58% ✅
Question
A shopkeeper sells at the listed price but gives only 95% of the quantity. He also marks up price by 10% on CP. If CP = ₹200 per unit, find overall profit%.
Options:
- A. 15.00%
- B. 15.79%
- C. 16.00%
- D. 14.50%
Solution
-
Step 1: Compute marked price after markup
CP = ₹200. Marked price = 200 × (1 + 10/100) = 220. -
Step 2: Account for false weight
Actual given = 95% = 0.95 unit. -
Step 3: Compute effective SP per true unit
SP per true unit = 220 ÷ 0.95 = 231.58. -
Step 4: Compute profit and percentage
Profit per unit = 231.58 - 200 = 31.58. Profit% = (31.58 ÷ 200) × 100 = 15.79%. -
Final Answer:
15.79% → Option B -
Quick Check:
CP for 0.95 unit = 200 × 0.95 = ₹190. SP charged = 220. Profit = 30. Profit% = (30 ÷ 190) × 100 = 15.79% ✅
Quick Variations
- 1. If seller gives x% less, Gain% = x / (100 - x) × 100.
- 2. If buyer cheats (takes more), Loss% = (Extra taken ÷ actual given) × 100.
- 3. If both markup and false weight exist, compute effective SP/unit first, then compare with CP.
Trick to Always Use
- Convert everything to per true unit.
- Effective SP/unit = Price charged ÷ Actual quantity given.
- Compare SP vs CP per unit → find profit or loss percentage.
Summary
Summary
- Focus on declared vs actual quantity.
- Effective SP per unit = SP ÷ actual_given.
- Profit% = ((SP_effective - CP) ÷ CP) × 100.
- Shortcut (selling at CP): Gain% = (1/r - 1) × 100.
