Component degrees of freedom in Solidworks - Interactive Code Practice

Practice - 5 Tasks

1fill in blank

easy

Complete the code to define the number of degrees of freedom for a free component in 3D space.

Solidworks

degrees_of_freedom = [1]

Drag options to blanks, or click blank then click option'

A6

B3

C9

D12

Attempts:

3 left

💡 Hint

Common Mistakes

Confusing 3D movement with 2D, which has only 3 degrees of freedom.

Counting only translations and forgetting rotations.

A free component in 3D space has 6 degrees of freedom: 3 translations and 3 rotations.

2fill in blank

medium

Complete the code to calculate the remaining degrees of freedom after applying one fixed constraint.

Solidworks

remaining_dof = 6 - [1]

Drag options to blanks, or click blank then click option'

A1

B2

C4

D3

Attempts:

3 left

💡 Hint

Common Mistakes

Assuming a fixed constraint removes only 1 degree of freedom.

Subtracting the wrong number from total degrees of freedom.

Each fixed constraint typically removes 4 degrees of freedom from the component.

3fill in blank

hard

Fix the error in the code to correctly calculate degrees of freedom after applying two constraints.

Solidworks

remaining_dof = 6 - [1]

Drag options to blanks, or click blank then click option'

A1

B2

C3

D4

Attempts:

3 left

💡 Hint

Common Mistakes

Subtracting only 1 degree of freedom for two constraints.

Using incorrect subtraction values.

Two constraints remove 2 degrees of freedom, so subtract 2 from 6.

4fill in blank

hard

Fill both blanks to calculate the degrees of freedom after applying a fixed and a hinge constraint.

Solidworks

remaining_dof = 6 - [1] - [2]

Drag options to blanks, or click blank then click option'

A1

B2

C3

D4

Attempts:

3 left

💡 Hint

Common Mistakes

Mixing up the degrees of freedom removed by hinge and fixed constraints.

Subtracting incorrect values.

A fixed constraint removes 4 degrees of freedom, and a hinge constraint removes 2 degrees of freedom.

5fill in blank

hard

Fill all three blanks to calculate the degrees of freedom after applying fixed, hinge, and slider constraints.

Solidworks

remaining_dof = 6 - [1] - [2] - [3]

Drag options to blanks, or click blank then click option'

A1

B2

C3

D4

Attempts:

3 left

💡 Hint

Common Mistakes

Confusing the degrees of freedom removed by each constraint type.

Adding instead of subtracting.

A fixed constraint removes 4 degrees of freedom, a hinge removes 2, and a slider removes 1 degree of freedom.

Practice

1. In SolidWorks, how many degrees of freedom does a new component have before applying any mates?

easy

A. 6 degrees of freedom

B. 3 degrees of freedom

C. 0 degrees of freedom

D. 9 degrees of freedom

Solution

1. Step 1: Understand degrees of freedom in 3D space

   A component in 3D space can move along 3 axes and rotate about 3 axes, totaling 6 degrees of freedom.

2. Step 2: Recall initial state of a new component

   Before any mates are applied, the component is free to move and rotate in all 6 ways.

3. Final Answer:

   6 degrees of freedom -> Option A

4. Quick Check:

   Initial freedom = 6 [OK]

Hint: Remember 3 translations + 3 rotations = 6 freedoms [OK]

Common Mistakes:

• Confusing degrees of freedom with number of mates
• Thinking zero means free movement
• Assuming 3D space has only 3 freedoms

2. Which of the following is the correct way to describe a component with zero degrees of freedom in SolidWorks?

easy

A. The component is fully fixed and cannot move or rotate

B. The component can move freely in all directions

C. The component can only rotate but not translate

D. The component has unlimited degrees of freedom

Solution

1. Step 1: Define zero degrees of freedom

   Zero degrees of freedom means no movement or rotation is possible.

2. Step 2: Interpret what fully fixed means

   A fully fixed component cannot translate or rotate in any direction.

3. Final Answer:

   The component is fully fixed and cannot move or rotate -> Option A

4. Quick Check:

   Zero freedom = fully fixed [OK]

Hint: Zero freedom means no movement at all [OK]

Common Mistakes:

• Thinking zero freedom means free movement
• Confusing rotation freedom with translation freedom
• Assuming partial movement is allowed

3. If a component initially has 6 degrees of freedom and you apply 3 mates that each restrict one degree of freedom, how many degrees of freedom remain?

medium

A. 9 degrees of freedom

B. 3 degrees of freedom

C. 0 degrees of freedom

D. 6 degrees of freedom

Solution

1. Step 1: Start with initial degrees of freedom

   The component starts with 6 degrees of freedom.

2. Step 2: Subtract degrees restricted by mates

   Each mate restricts one degree, so 3 mates restrict 3 freedoms.

3. Step 3: Calculate remaining degrees of freedom

   6 - 3 = 3 degrees of freedom remain.

4. Final Answer:

   3 degrees of freedom -> Option B

5. Quick Check:

   6 - 3 = 3 [OK]

Hint: Subtract mates from 6 freedoms to find remaining [OK]

Common Mistakes:

• Adding mates instead of subtracting
• Assuming each mate restricts multiple freedoms
• Confusing total freedoms with mates count

4. You applied 6 mates to a component, but it still moves. What is the most likely reason?

medium

A. The component has infinite degrees of freedom

B. You need to apply more mates to fix the component

C. Some mates are redundant and do not reduce degrees of freedom

D. SolidWorks does not support fixing components

Solution

1. Step 1: Understand mate redundancy

   Some mates may overlap in restricting the same freedom, causing redundancy.

2. Step 2: Recognize effect of redundant mates

   Redundant mates do not reduce additional degrees of freedom, so movement remains.

3. Final Answer:

   Some mates are redundant and do not reduce degrees of freedom -> Option C

4. Quick Check:

   Redundant mates don't fix movement [OK]

Hint: Check for redundant mates if component still moves [OK]

Common Mistakes:

• Assuming more mates always fix movement
• Ignoring mate redundancy
• Believing SolidWorks cannot fix components

5. You have a component with 2 degrees of freedom left. You want to fully fix it by applying mates. Which combination of mates will correctly reduce the remaining freedoms?

hard

A. Apply 3 mates that restrict only one degree of freedom each

B. Apply 1 mate that restricts 2 degrees of freedom simultaneously

C. Apply 2 mates that restrict the same degree of freedom twice

D. Apply 2 mates that each restrict one unique degree of freedom

Solution

1. Step 1: Identify remaining freedoms

   The component has 2 freedoms left to restrict.

2. Step 2: Choose mates that restrict unique freedoms

   Each mate must restrict a different freedom to reduce total freedoms correctly.

3. Step 3: Avoid redundant mates

   Applying mates that restrict the same freedom twice does not reduce freedoms further.

4. Final Answer:

   Apply 2 mates that each restrict one unique degree of freedom -> Option D

5. Quick Check:

   Unique mates reduce freedoms correctly [OK]

Hint: Use mates targeting different freedoms to fully fix [OK]

Common Mistakes:

• Applying redundant mates on same freedom
• Assuming one mate can restrict multiple freedoms
• Applying more mates than needed without effect