Bilinear transformation method in Signal Processing - Time & Space Complexity

Time Complexity: Bilinear transformation method

O(n^2)

Understanding Time Complexity

We want to understand how the time needed to perform the bilinear transformation changes as the input size grows.

Specifically, how does the processing time scale when converting analog filter coefficients to digital ones?

Scenario Under Consideration

Analyze the time complexity of the following bilinear transformation code snippet.

// Given analog filter coefficients b, a and sampling frequency fs
function bilinearTransform(b, a, fs) {
  let degree = a.length - 1;
  let T = 1 / fs;
  let digitalB = new Array(degree + 1).fill(0);
  let digitalA = new Array(degree + 1).fill(0);

  for (let i = 0; i <= degree; i++) {
    for (let j = 0; j <= i; j++) {
      digitalB[i] += b[j] * combination(i, j) * Math.pow(2 / T, i - j);
      digitalA[i] += a[j] * combination(i, j) * Math.pow(2 / T, i - j);
    }
  }
  return { digitalB, digitalA };
}

// Helper function for combinations
function combination(n, k) {
  if (k === 0 || k === n) return 1;
  return combination(n - 1, k - 1) + combination(n - 1, k);
}

This code converts analog filter coefficients to digital ones using the bilinear transform method by calculating weighted sums with combinations.

Identify Repeating Operations

Look at the loops and repeated calculations:

• Primary operation: Nested loops over filter order (degree) for coefficient calculation.
• How many times: Outer loop runs (degree + 1) times, inner loop runs up to (degree + 1) times for each outer loop.
• Combination function: Called many times recursively inside loops.

How Execution Grows With Input

As the filter order (degree) increases, the number of operations grows roughly with the square of the degree because of nested loops.

Input Size (degree)	Approx. Operations
10	~100
100	~10,000
1000	~1,000,000

Pattern observation: Doubling the filter order roughly quadruples the number of operations.

Final Time Complexity

Time Complexity: O(n^2)

This means the time to compute the digital coefficients grows roughly with the square of the filter order.

Common Mistake

[X] Wrong: "The bilinear transform runs in linear time because it just loops once over coefficients."

[OK] Correct: There are nested loops and recursive calls inside, so the work grows faster than just one loop.

Interview Connect

Understanding how nested loops affect time helps you explain performance clearly and shows you can analyze real signal processing code efficiently.

Self-Check

"What if we replaced the recursive combination function with a precomputed lookup table? How would the time complexity change?"

Practice

1. What is the main purpose of the bilinear transformation method in signal processing?

easy

A. To convert analog filter designs into digital filter designs

B. To convert digital signals into analog signals

C. To increase the sampling rate of a digital signal

D. To reduce noise in digital signals

Solution

1. Step 1: Understand the bilinear transformation concept

   The bilinear transformation substitutes the analog frequency variable s with a function of the digital variable z, enabling analog filter designs to be converted to digital filters.

2. Step 2: Identify the main use

   This method is primarily used to convert analog filter designs into digital filter designs for digital signal processing.

3. Final Answer:

   To convert analog filter designs into digital filter designs -> Option A

4. Quick Check:

   Bilinear transformation = analog to digital filter conversion [OK]

Hint: Bilinear transforms analog filters to digital filters [OK]

Common Mistakes:

• Confusing bilinear transform with sampling rate conversion
• Thinking it converts digital signals back to analog
• Assuming it reduces noise directly

2. Which of the following is the correct substitution for s in the bilinear transformation?

easy

A. s = (1 - z^{-1}) / (1 + z^{-1})

B. s = (1 + z^{-1}) / (1 - z^{-1})

C. s = (2/T) * (1 - z^{-1}) / (1 + z^{-1})

D. s = (z - 1) / (z + 1)

Solution

1. Step 1: Recall the bilinear transformation formula

   The bilinear transformation substitutes s with (2/T) * (1 - z^{-1}) / (1 + z^{-1}), where T is the sampling period.

2. Step 2: Match the correct formula

   Among the options, only s = (2/T) * (1 - z^{-1}) / (1 + z^{-1}) correctly includes the factor 2/T and the fraction form.

3. Final Answer:

   s = (2/T) * (1 - z^{-1}) / (1 + z^{-1}) -> Option C

4. Quick Check:

   Bilinear substitution = (2/T)(1 - z^{-1})/(1 + z^{-1}) [OK]

Hint: Remember the 2/T factor in bilinear substitution [OK]

Common Mistakes:

• Omitting the 2/T factor
• Swapping numerator and denominator
• Using incorrect signs in numerator or denominator

3. Given an analog low-pass filter transfer function H(s) = 1 / (s + 1) and sampling period T = 1, what is the digital filter transfer function H(z) after applying the bilinear transformation?

medium

A. H(z) = (1 + z^{-1}) / (3 + z^{-1})

B. H(z) = (1 + z^{-1}) / (3 - z^{-1})

C. H(z) = (1 - z^{-1}) / (3 + z^{-1})

D. H(z) = (1 - z^{-1}) / (3 - z^{-1})

Solution

1. Step 1: Substitute s using bilinear transform

   With T=1, substitute s = 2 * (1 - z^{-1}) / (1 + z^{-1}) into H(s) = 1 / (s + 1).
   So, H(z) = 1 / (2 * (1 - z^{-1}) / (1 + z^{-1}) + 1).

2. Step 2: Simplify the expression

   Rewrite denominator:
   2 * (1 - z^{-1}) / (1 + z^{-1}) + 1 = (2(1 - z^{-1}) + (1 + z^{-1})) / (1 + z^{-1}) = (2 - 2z^{-1} + 1 + z^{-1}) / (1 + z^{-1}) = (3 - z^{-1}) / (1 + z^{-1}).
   Therefore, H(z) = 1 / ((3 - z^{-1}) / (1 + z^{-1})) = (1 + z^{-1}) / (3 - z^{-1}).

3. Final Answer:

   H(z) = (1 + z^{-1}) / (3 - z^{-1}) -> Option B

4. Quick Check:

   Substitution and simplification give (1 + z^{-1})/(3 - z^{-1}) [OK]

Hint: Substitute s, then simplify fractions carefully [OK]

Common Mistakes:

• Forgetting to add 1 in denominator
• Incorrect algebraic simplification
• Mixing signs in numerator or denominator

4. A student tries to apply the bilinear transformation but writes s = (1 - z) / (1 + z) without the 2/T factor. What is the main issue with this approach?

medium

A. The digital filter will be unstable

B. The transformation will cause a syntax error

C. The analog filter cannot be converted

D. The frequency scaling is incorrect, causing distortion

Solution

1. Step 1: Identify missing factor impact

   The bilinear transformation requires the factor 2/T to correctly scale frequencies from analog to digital domain.

2. Step 2: Consequence of missing factor

   Without 2/T, the frequency mapping is incorrect, leading to frequency distortion or warping in the digital filter.

3. Final Answer:

   The frequency scaling is incorrect, causing distortion -> Option D

4. Quick Check:

   Missing 2/T causes frequency distortion [OK]

Hint: Always include 2/T factor to avoid frequency errors [OK]

Common Mistakes:

• Ignoring the 2/T factor
• Assuming syntax error instead of scaling error
• Thinking filter stability is directly affected

5. You want to design a digital Butterworth low-pass filter with cutoff frequency 1000 Hz using bilinear transformation. The sampling frequency is 8000 Hz. Which step is essential to correctly map the analog cutoff frequency to the digital domain?

hard

A. Pre-warp the analog cutoff frequency using Ω = 2 * fs * tan(π * f_c / fs)

B. Use the cutoff frequency directly without modification

C. Divide the cutoff frequency by 2 before applying bilinear transform

D. Multiply the cutoff frequency by the sampling frequency

Solution

1. Step 1: Understand frequency warping in bilinear transform

   The bilinear transformation causes frequency warping, so the analog cutoff frequency must be pre-warped to match the desired digital cutoff.

2. Step 2: Apply pre-warping formula

   The correct pre-warping formula is Ω = 2 * fs * tan(π * f_c / fs), where fs is sampling frequency and f_c is desired cutoff frequency.

3. Final Answer:

   Pre-warp the analog cutoff frequency using Ω = 2 * fs * tan(π * f_c / fs) -> Option A

4. Quick Check:

   Pre-warping corrects frequency warping [OK]

Hint: Pre-warp cutoff frequency to fix bilinear warping [OK]

Common Mistakes:

• Skipping pre-warping step
• Using cutoff frequency directly
• Incorrectly scaling cutoff frequency