What is the main purpose of using the bilinear transformation method in signal processing?
Think about how analog filters are adapted for digital use.
The bilinear transformation method is used to convert analog filter designs into digital filter designs. It maps the s-plane to the z-plane, preserving the stability of the filter and avoiding aliasing.
What is the output of the following Python code that uses the bilinear transform formula to map an analog frequency to digital frequency?
import numpy as np # Analog frequency in radians per second omega_analog = np.pi / 2 # Sampling frequency fs = 2 * np.pi # Bilinear transform frequency mapping formula omega_digital = 2 * fs * np.tan(omega_analog / 2) print(round(omega_digital, 3))
Recall that tan(π/4) = 1 and fs = 2π.
The code calculates omega_digital = 2 * 2π * tan(π/4) = 4π ≈ 12.566, but since fs is 2π, the calculation is 2 * 2π * 1 = 4π ≈ 12.566. The printed rounded value is 12.566, which is not among the options. However, the formula for frequency warping is usually omega_digital = 2 * fs * tan(omega_analog / (2 * fs)), so the code or options need correction.
Given an analog filter with poles at s = -1 and s = -2, what are the poles of the digital filter after applying the bilinear transformation with sampling frequency fs = 10 rad/s?
import numpy as np fs = 10 s_poles = np.array([-1, -2]) z_poles = (1 + s_poles / (2 * fs)) / (1 - s_poles / (2 * fs)) print(np.round(z_poles, 3))
Use the bilinear transform formula: z = (1 + s/(2fs)) / (1 - s/(2fs))
Applying the formula for each pole: For s = -1, z = (1 - 1/(20)) / (1 + 1/(20)) = 0.818; for s = -2, z = (1 - 2/(20)) / (1 + 2/(20)) = 0.667.
Which plot correctly shows the frequency warping effect of the bilinear transformation mapping analog frequencies (0 to π) to digital frequencies (0 to π)?
Remember that bilinear transform compresses high frequencies.
The bilinear transform causes frequency warping where low frequencies map almost linearly, but higher frequencies are compressed, so the curve bends downward approaching π.
What error does the following Python code raise when applying the bilinear transform to poles?
import numpy as np fs = 5 s_poles = np.array([-10, -20]) z_poles = (1 + s_poles / (2 * fs)) / (1 - s_poles / (2 * fs)) print(z_poles)
Check the denominator values carefully.
For s = -10 and fs = 5, denominator 1 - s/(2*fs) becomes zero for s = -10, causing division by zero and raising ZeroDivisionError.