Cost vs complexity trade-off in PCB Design - Interactive Practice

Practice - 5 Tasks

1fill in blank

easy

Complete the code to calculate the total cost by multiplying unit cost with quantity.

PCB Design

total_cost = unit_cost [1] quantity

Drag options to blanks, or click blank then click option'

A*

B+

C-

D/

Attempts:

3 left

💡 Hint

Common Mistakes

Using addition instead of multiplication

Using division or subtraction by mistake

Multiplying unit cost by quantity gives the total cost.

2fill in blank

medium

Complete the code to calculate complexity score by adding number of layers and number of components.

PCB Design

complexity_score = layers [1] components

Drag options to blanks, or click blank then click option'

A+

B-

C/

D*

Attempts:

3 left

💡 Hint

Common Mistakes

Using multiplication instead of addition

Using division or subtraction

Adding layers and components gives a simple complexity score.

3fill in blank

hard

Fix the error in the code to calculate cost per complexity unit by dividing total cost by complexity score.

PCB Design

cost_per_complexity = total_cost [1] complexity_score

Drag options to blanks, or click blank then click option'

A*

B-

C/

D+

Attempts:

3 left

💡 Hint

Common Mistakes

Using multiplication or addition instead of division

Using subtraction by mistake

Dividing total cost by complexity score gives cost per complexity unit.

4fill in blank

hard

Fill both blanks to create a dictionary mapping component names to their costs, but only include components costing more than 10.

PCB Design

component_costs = {name: cost for name, cost in components.items() if cost [1] 10 and name [2] 'Resistor'}

Drag options to blanks, or click blank then click option'

A>

B<

C!=

D==

Attempts:

3 left

💡 Hint

Common Mistakes

Using '<' instead of '>' for cost comparison

Using '==' instead of '!=' for name check

The code filters components costing more than 10 and excludes resistors by checking name not equal to 'Resistor'.

5fill in blank

hard

Fill all three blanks to create a dictionary of components with cost above 5, keys as uppercase names, and values as costs minus 2.

PCB Design

filtered_components = {name[1]: cost[2] 2 for name, cost in components.items() if cost [3] 5}

Drag options to blanks, or click blank then click option'

A.upper()

B-

C>

D+

Attempts:

3 left

💡 Hint

Common Mistakes

Using '+' instead of '-' for cost adjustment

Using '<' instead of '>' for filtering

Not converting names to uppercase

The dictionary comprehension uses name.upper() as keys, subtracts 2 from cost for values, and filters costs greater than 5.