Via size and drill diameter in PCB Design - Dashboard Guide

Dashboard Mode - Via size and drill diameter

Goal

Understand how via size and drill diameter affect PCB manufacturing and electrical performance.

Sample Data

Via ID	Drill Diameter (mm)	Via Diameter (mm)	Annular Ring Width (mm)	Electrical Resistance (mΩ)
V1	0.3	0.6	0.15	50
V2	0.4	0.8	0.2	35
V3	0.5	1.0	0.25	25
V4	0.6	1.2	0.3	20
V5	0.7	1.4	0.35	15

Dashboard Components

• KPI Card: Average Drill Diameter
  Formula: Average of Drill Diameter column = (0.3+0.4+0.5+0.6+0.7)/5 = 0.5 mm
• KPI Card: Average Electrical Resistance
  Formula: Average of Electrical Resistance column = (50+35+25+20+15)/5 = 29 mΩ
• Bar Chart: Drill Diameter vs Electrical Resistance
  Shows each Via ID on X-axis and Electrical Resistance on Y-axis with bars colored by Drill Diameter size.
• Scatter Plot: Via Diameter vs Electrical Resistance
  X-axis: Via Diameter, Y-axis: Electrical Resistance, points labeled by Via ID to show relationship.
• Table: Full data table with all columns for detailed view.

Dashboard Layout

+----------------------+----------------------+
|  KPI: Avg Drill Dia  |  KPI: Avg Resistance  |
+----------------------+----------------------+
|                      Bar Chart                     |
|           Drill Diameter vs Electrical Resistance  |
+---------------------------------------------------+
|               Scatter Plot: Via Diameter vs Resistance             |
+---------------------------------------------------+
|                         Data Table                          |
+---------------------------------------------------+

Interactivity

User can filter by Via ID or range of Drill Diameter. Filtering updates all components: KPIs recalculate averages, charts update to show only selected vias, and table filters rows accordingly.

Self Check

If you add a filter to show only vias with Drill Diameter >= 0.5 mm, which components update and how?

• Average Drill Diameter KPI updates to average of 0.5, 0.6, 0.7 = 0.6 mm
• Average Electrical Resistance KPI updates to average of 25, 20, 15 = 20 mΩ
• Bar Chart shows only V3, V4, V5 bars
• Scatter Plot shows only points for V3, V4, V5
• Data Table shows only rows for V3, V4, V5

Key Result

Dashboard shows how via drill diameter and size relate to electrical resistance in PCB design.

Practice

1. What does the term via size in PCB design usually refer to?

easy

A. The length of the trace connected to the via

B. Only the drill hole diameter

C. The thickness of the PCB

D. The total diameter including drill hole and annular ring

Solution

1. Step 1: Understand via size components

   Via size includes the drill hole plus the annular ring around it.

2. Step 2: Define via size

   Via size = drill diameter + 2 x annular ring width.

3. Final Answer:

   The total diameter including drill hole and annular ring -> Option D

4. Quick Check:

   Via size = drill + 2xannular ring [OK]

Hint: Via size always includes drill plus annular ring twice [OK]

Common Mistakes:

• Confusing drill diameter with via size
• Ignoring annular ring width
• Thinking via size is PCB thickness

2. Which of the following formulas correctly calculates the via size if the drill diameter is D and annular ring width is R?

easy

A. Via size = D + 2 * R

B. Via size = D + R

C. Via size = 2 * (D + R)

D. Via size = D - 2 * R

Solution

1. Step 1: Recall the via size formula

   Via size equals drill diameter plus twice the annular ring width.

2. Step 2: Apply formula to variables

   Via size = D + 2 x R.

3. Final Answer:

   Via size = D + 2 * R -> Option A

4. Quick Check:

   Via size = drill + 2xannular ring [OK]

Hint: Remember annular ring counts twice around drill [OK]

Common Mistakes:

• Adding annular ring only once
• Multiplying drill diameter incorrectly
• Subtracting annular ring width

3. If a PCB designer uses a drill diameter of 0.3 mm and an annular ring width of 0.1 mm, what is the total via size?

medium

A. 0.4 mm

B. 0.6 mm

C. 0.5 mm

D. 0.7 mm

Solution

1. Step 1: Identify given values

   Drill diameter D = 0.3 mm, annular ring R = 0.1 mm.

2. Step 2: Calculate via size

   Via size = D + 2 x R = 0.3 + 2 x 0.1 = 0.3 + 0.2 = 0.5 mm.

3. Final Answer:

   0.5 mm -> Option C

4. Quick Check:

   0.3 + 2x0.1 = 0.5 mm [OK]

Hint: Add drill plus twice annular ring width [OK]

Common Mistakes:

• Adding annular ring once only
• Mixing units or decimal points
• Choosing closest but incorrect option

4. A PCB design rule states the minimum annular ring width is 0.15 mm. A designer sets drill diameter to 0.4 mm and via size to 0.55 mm. What is wrong?

medium

A. Via size is too small for the annular ring requirement

B. Drill diameter is too large

C. Annular ring width is too large

D. Via size is correctly set

Solution

1. Step 1: Calculate required via size

   Minimum annular ring R = 0.15 mm, drill D = 0.4 mm, so via size = 0.4 + 2x0.15 = 0.7 mm.

2. Step 2: Compare with given via size

   Given via size is 0.55 mm, which is less than required 0.7 mm.

3. Final Answer:

   Via size is too small for the annular ring requirement -> Option A

4. Quick Check:

   Via size < required minimum [OK]

Hint: Check if via size ≥ drill + 2xannular ring [OK]

Common Mistakes:

• Ignoring minimum annular ring width
• Assuming drill diameter can be changed
• Thinking via size can be smaller than drill

5. A PCB manufacturer requires a minimum annular ring width of 0.12 mm and a maximum drill diameter of 0.5 mm. If a designer wants a via size of 0.8 mm, what is the largest drill diameter they can use?

hard

A. 0.56 mm or less

B. 0.56 mm

C. 0.56 mm or more

D. 0.56 mm exactly

Solution

1. Step 1: Write the via size formula

   Via size = drill diameter + 2 x annular ring width.

2. Step 2: Substitute known values and solve for drill diameter

   0.8 = drill + 2 x 0.12 -> drill = 0.8 - 0.24 = 0.56 mm.

3. Step 3: Check manufacturer max drill diameter

   Max drill diameter allowed is 0.5 mm, but calculated drill is 0.56 mm, which is too large.

4. Step 4: Interpret largest drill diameter possible

   Designer must use drill diameter ≤ 0.5 mm to meet manufacturer limit, so largest drill diameter is 0.5 mm, less than 0.56 mm.

5. Final Answer:

   0.56 mm -> Option B

6. Quick Check:

   Drill ≤ 0.5 mm and via size = 0.8 mm [OK]

Hint: Solve via size formula, check max drill limit [OK]

Common Mistakes:

• Ignoring max drill diameter limit
• Assuming drill can be larger than max allowed
• Confusing annular ring with drill diameter