What is embedded C - Interactive Quiz & Practice

Practice - 5 Tasks

1fill in blank

easy

Complete the code to declare a variable in embedded C.

Embedded C

int [1] = 10;

Drag options to blanks, or click blank then click option'

Acount

B10

Cint

Dmain

Attempts:

3 left

💡 Hint

Common Mistakes

Using a number as a variable name.

Using a keyword as a variable name.

The variable name should be a valid identifier like count.

2fill in blank

medium

Complete the code to include the standard input-output header in embedded C.

Embedded C

#include [1]

Drag options to blanks, or click blank then click option'

A"stdlib.h"

B"stdio.h"

C<stdio.h>

D<string.h>

Attempts:

3 left

💡 Hint

Common Mistakes

Using quotes instead of angle brackets for standard headers.

Including the wrong header file.

The standard way to include the input-output header is #include <stdio.h>.

3fill in blank

hard

Fix the error in the embedded C function declaration.

Embedded C

void [1]() { }

Drag options to blanks, or click blank then click option'

AMain

Bmain

Cint

Dvoid

Attempts:

3 left

💡 Hint

Common Mistakes

Using uppercase 'Main' instead of 'main'.

Using a return type as the function name.

The entry point function in embedded C is main with lowercase 'm'.

4fill in blank

hard

Fill both blanks to create a simple infinite loop in embedded C.

Embedded C

while ([1]) {
    [2];
}

Drag options to blanks, or click blank then click option'

A1

B0

Ccontinue

Dbreak

Attempts:

3 left

💡 Hint

Common Mistakes

Using 0 as the condition which stops the loop.

Using break inside the loop which exits it.

An infinite loop uses while(1) and continue; to keep running.

5fill in blank

hard

Fill all three blanks to define and call a function that returns the sum of two integers.

Embedded C

int [1](int a, int b) {
    return a [2] b;
}

int result = [3](5, 3);

Drag options to blanks, or click blank then click option'

Aadd

B+

Dsum

Attempts:

3 left

💡 Hint

Common Mistakes

Using different names for function definition and call.

Using wrong operator for addition.

The function name is add, the operator is +, and the call uses add.

Practice

1. What is Embedded C primarily used for?

easy

A. Programming small computers inside devices

B. Creating websites

C. Designing video games

D. Writing desktop applications

Solution

1. Step 1: Understand the purpose of Embedded C

   Embedded C is a version of the C language used to program small computers inside devices, not general software like websites or games.

2. Step 2: Match the correct use case

   Since it controls hardware inside devices, the correct use is programming small computers inside devices.

3. Final Answer:

   Programming small computers inside devices -> Option A

4. Quick Check:

   Embedded C = device programming [OK]

Hint: Embedded C controls hardware inside devices [OK]

Common Mistakes:

• Confusing Embedded C with general software programming
• Thinking Embedded C is for web development
• Assuming it is used for game design

2. Which of the following is the correct way to declare a pin as output in Embedded C?

easy

A. setPin(13, HIGH);

B. outputPin(13);

C. pinWrite(13, OUTPUT);

D. pinMode(13, OUTPUT);

Solution

1. Step 1: Identify the standard syntax for pin setup

   In Embedded C (especially Arduino style), pinMode(pin, mode); sets a pin as input or output.

2. Step 2: Check each option

   Only pinMode(13, OUTPUT); correctly declares pin 13 as output.

3. Final Answer:

   pinMode(13, OUTPUT); -> Option D

4. Quick Check:

   pinMode sets pin mode [OK]

Hint: Use pinMode(pin, OUTPUT) to set output pin [OK]

Common Mistakes:

• Using wrong function names like outputPin or pinWrite
• Confusing setting pin value with setting pin mode
• Missing parentheses or semicolons

3. What will be the output of this Embedded C code snippet?

int main() {
  int pinState = 0;
  pinState = 1;
  if (pinState) {
    return 5;
  } else {
    return 0;
  }
}

medium

A. 1

B. 5

C. 0

D. Compilation error

Solution

1. Step 1: Analyze variable assignment and condition

   Variable pinState is set to 1, which is true in C conditional.

2. Step 2: Follow the if condition

   Since pinState is true, the program returns 5.

3. Final Answer:

   5 -> Option B

4. Quick Check:

   pinState=1 triggers return 5 [OK]

Hint: Non-zero values in if condition mean true [OK]

Common Mistakes:

• Thinking return value is 1 instead of 5
• Confusing assignment with comparison
• Assuming compilation error due to missing headers

4. Find the error in this Embedded C code snippet:

void setup() {
  pinMode(13, OUTPUT)
}

void loop() {
  digitalWrite(13, HIGH);
  delay(1000);
  digitalWrite(13, LOW);
  delay(1000);
}

medium

A. Missing semicolon after pinMode line

B. digitalWrite function is incorrect

C. delay function cannot be used in Embedded C

D. setup function should return int

Solution

1. Step 1: Check syntax line by line

   The line pinMode(13, OUTPUT) is missing a semicolon at the end.

2. Step 2: Verify other lines

   Other functions like digitalWrite and delay are correct and allowed in Embedded C.

3. Final Answer:

   Missing semicolon after pinMode line -> Option A

4. Quick Check:

   Every statement needs semicolon [OK]

Hint: Check for missing semicolons after statements [OK]

Common Mistakes:

• Ignoring missing semicolon errors
• Thinking delay is not allowed in Embedded C
• Assuming setup must return int

5. You want to toggle an LED connected to pin 8 every second using Embedded C. Which code snippet correctly implements this?

hard

A. void loop() {
digitalWrite(8, HIGH);
delay(1000);
digitalWrite(8, LOW);
}

B. void loop() {
digitalWrite(8, 1);
digitalWrite(8, 0);
delay(1000);
}

C. void loop() {
static int state = 0;
state = !state;
digitalWrite(8, state);
delay(1000);
}

D. void loop() {
digitalWrite(8, HIGH);
digitalWrite(8, LOW);
}

Solution

1. Step 1: Understand toggling logic

   Toggling means switching the LED state from ON to OFF repeatedly every second.

2. Step 2: Analyze each option

   void loop() { digitalWrite(8, HIGH); delay(1000); digitalWrite(8, LOW); } turns ON for 1s then OFF briefly (no delay after LOW), not proper toggle. void loop() { static int state = 0; state = !state; digitalWrite(8, state); delay(1000); } uses a static variable to flip state each loop, correctly toggling LED every second. void loop() { digitalWrite(8, 1); digitalWrite(8, 0); delay(1000); } turns ON then OFF immediately without delay between states. void loop() { digitalWrite(8, HIGH); digitalWrite(8, LOW); } turns ON then OFF immediately without delay, so no visible toggle.

3. Final Answer:

   code with static state toggling -> Option C

4. Quick Check:

   Toggle needs state flip and delay [OK]

Hint: Use a variable to flip LED state each loop [OK]

Common Mistakes:

• Not using a variable to track LED state
• Missing delay between ON and OFF
• Turning LED ON and OFF immediately without pause