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Embedded Cprogramming~10 mins

Struct packing and alignment in Embedded C - Interactive Code Practice

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Practice - 5 Tasks
Answer the questions below
1fill in blank
easy

Complete the code to define a packed struct in C.

Embedded C
struct __attribute__(([1])) PackedData {
    char a;
    int b;
};
Drag options to blanks, or click blank then click option'
Aaligned
Bunused
Cdeprecated
Dpacked
Attempts:
3 left
💡 Hint
Common Mistakes
Using __attribute__((aligned)) instead of packed
Forgetting to use attribute at all
2fill in blank
medium

Complete the code to specify 1-byte alignment for the struct.

Embedded C
struct Data {
    char a;
    int b;
} __attribute__(([1](1)));
Drag options to blanks, or click blank then click option'
Apacked
Baligned
Cdeprecated
Dunused
Attempts:
3 left
💡 Hint
Common Mistakes
Using packed instead of aligned
Not specifying the alignment value
3fill in blank
hard

Fix the error in the struct declaration to correctly pack the struct.

Embedded C
struct Data {
    char a;
    int b;
} __attribute__(([1]));
Drag options to blanks, or click blank then click option'
Apacked
Balign
Calignas
Dpack
Attempts:
3 left
💡 Hint
Common Mistakes
Using 'align' or 'pack' which are invalid
Confusing with C++11 alignas keyword
4fill in blank
hard

Fill both blanks to create a struct with 2-byte alignment and packed attribute.

Embedded C
struct Data {
    char a;
    short b;
} __attribute__(([1])) __attribute__(([2](2)));
Drag options to blanks, or click blank then click option'
Apacked
Baligned
Cdeprecated
Dunused
Attempts:
3 left
💡 Hint
Common Mistakes
Swapping the attributes
Using deprecated or unused attributes
5fill in blank
hard

Fill all three blanks to define a packed struct with 4-byte alignment and a member with 2-byte alignment.

Embedded C
struct Data {
    char a;
    short b __attribute__(([1](2)));
} __attribute__(([2])) __attribute__(([3](4)));
Drag options to blanks, or click blank then click option'
Aaligned
Bpacked
Cdeprecated
Dunused
Attempts:
3 left
💡 Hint
Common Mistakes
Using packed on member instead of aligned
Misordering attributes

Practice

(1/5)
1. What does struct packing do in embedded C?
easy
A. Removes extra spaces between fields to save memory
B. Adds extra spaces to align data on memory boundaries
C. Changes the data types of struct members
D. Automatically initializes struct members to zero

Solution

  1. Step 1: Understand struct packing purpose

    Struct packing removes padding bytes between fields to reduce memory usage.
  2. Step 2: Compare with alignment

    Alignment adds padding for faster access, packing removes it to save space.
  3. Final Answer:

    Removes extra spaces between fields to save memory -> Option A
  4. Quick Check:

    Struct packing = removes padding [OK]
Hint: Packing removes spaces, alignment adds spaces [OK]
Common Mistakes:
  • Confusing packing with alignment
  • Thinking packing changes data types
  • Assuming packing initializes values
2. Which of the following is the correct syntax to pack a struct in embedded C using GCC?
easy
A. struct MyStruct { int a; char b; } __packed;
B. struct MyStruct __packed { int a; char b; };
C. struct MyStruct { int a; char b; } __attribute__((aligned));
D. struct __attribute__((packed)) MyStruct { int a; char b; };

Solution

  1. Step 1: Recall GCC packing syntax

    GCC uses __attribute__((packed)) after struct keyword or at end of struct definition.
  2. Step 2: Identify correct placement

    struct __attribute__((packed)) MyStruct { int a; char b; }; places __attribute__((packed)) correctly after struct keyword.
  3. Final Answer:

    struct __attribute__((packed)) MyStruct { int a; char b; }; -> Option D
  4. Quick Check:

    GCC packing syntax = __attribute__((packed)) [OK]
Hint: Use __attribute__((packed)) after struct keyword [OK]
Common Mistakes:
  • Using __packed keyword which is not standard GCC
  • Placing __attribute__((aligned)) instead of packed
  • Putting attributes in wrong position
3. Consider this struct without packing:
struct Example {
  char a;
  int b;
};

sizeof(struct Example);

What is the likely output on a 32-bit system where int is 4 bytes and alignment is on 4-byte boundaries?
medium
A. 5
B. 8
C. 12
D. 16

Solution

  1. Step 1: Analyze struct member sizes and alignment

    char a = 1 byte, int b = 4 bytes aligned on 4-byte boundary.
  2. Step 2: Calculate padding and total size

    After char a, 3 bytes padding added to align int b. Total size = 1 + 3 + 4 = 8 bytes. Struct size must be multiple of largest alignment (4), which 8 satisfies.
  3. Final Answer:

    8 -> Option B
  4. Quick Check:

    Size with padding = 8 bytes [OK]
Hint: Add padding after smaller types to align next member [OK]
Common Mistakes:
  • Ignoring padding bytes
  • Adding padding after last member unnecessarily
  • Assuming size is sum of member sizes only
4. Given this code snippet:
struct Data {
  char c;
  int i;
} __attribute__((packed));

struct Data d;
printf("%zu", sizeof(d));

The output is 5, but the program crashes when accessing d.i. What is the likely cause?
medium
A. Accessing unaligned int causes crash on some systems
B. The struct is not actually packed
C. char c is not initialized
D. printf format specifier is incorrect

Solution

  1. Step 1: Understand packing effect on alignment

    Packing removes padding, so int i may not be aligned on 4-byte boundary.
  2. Step 2: Recognize hardware alignment requirements

    Some systems crash or fault when accessing unaligned int variables.
  3. Final Answer:

    Accessing unaligned int causes crash on some systems -> Option A
  4. Quick Check:

    Unaligned access = crash risk [OK]
Hint: Packed structs can cause unaligned access crashes [OK]
Common Mistakes:
  • Blaming printf format specifier
  • Assuming packing always safe
  • Ignoring hardware alignment rules
5. You have a struct with members:
char a;
short b;
int c;

On a 32-bit system, how can you arrange and pack this struct to minimize memory size without causing unaligned access faults?
hard
A. Order members as char a; int c; short b; and use packing
B. Order members as char a; short b; int c; without packing
C. Order members as int c; short b; char a; and use packing
D. Order members as short b; char a; int c; without packing

Solution

  1. Step 1: Understand alignment requirements

    int requires 4-byte alignment, short 2-byte, char 1-byte.
  2. Step 2: Arrange members largest to smallest

    Ordering int c; short b; char a; places largest first, minimizing padding.
  3. Step 3: Use packing carefully

    Packing removes padding but can cause unaligned access; here, ordering avoids unaligned access.
  4. Final Answer:

    Order members as int c; short b; char a; and use packing -> Option C
  5. Quick Check:

    Largest to smallest + packing = minimal size safe [OK]
Hint: Order largest to smallest type, then pack [OK]
Common Mistakes:
  • Ordering members smallest to largest causing padding
  • Packing without considering alignment faults
  • Ignoring hardware alignment rules
Recommended

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10 questions~5 mineasy hard