sizeof and memory budgeting in Embedded C - Mini Project: Build & Apply

Memory Budgeting with sizeof in Embedded C

📖 Scenario: You are working on a small embedded system with limited memory. You need to keep track of how much memory your variables use to avoid running out of space.

🎯 Goal: Build a simple program that calculates the total memory used by different variables using the sizeof operator.

📋 What You'll Learn

Create variables of different types

Use sizeof to find the size of each variable

Calculate the total memory used

Print the total memory size

💡 Why This Matters

🌍 Real World

Embedded systems often have very limited memory. Knowing how much memory your variables use helps you avoid crashes and bugs.

💼 Career

Embedded C programmers must manage memory carefully. Using <code>sizeof</code> helps estimate memory needs and optimize code.

1

Create variables of different types

Create three variables: an int called count, a char called flag, and a float called temperature.

Embedded C

# Create variables: int count, char flag, float temperature
// Your code here

Hint

Use the syntax type name; to declare variables.

2

Create variables to hold sizes

Create three size_t variables called size_count, size_flag, and size_temperature to store the sizes of count, flag, and temperature respectively.

Embedded C

int count;
char flag;
float temperature;
// Create size_t variables: size_count, size_flag, size_temperature
// Your code here

Hint

Use size_t to store sizes returned by sizeof.

3

Use sizeof to get sizes

Assign the size of count to size_count, the size of flag to size_flag, and the size of temperature to size_temperature using the sizeof operator.

Embedded C

int count;
char flag;
float temperature;
size_t size_count;
size_t size_flag;
size_t size_temperature;
// Assign sizes using sizeof
// Your code here

Hint

Use sizeof(variable) to get the size in bytes.

4

Calculate and print total memory used

Create a size_t variable called total_size that sums size_count, size_flag, and size_temperature. Then print total_size using printf with the format specifier %zu.

Embedded C

int count;
char flag;
float temperature;
size_t size_count = sizeof(count);
size_t size_flag = sizeof(flag);
size_t size_temperature = sizeof(temperature);
// Calculate total_size and print it
// Your code here

Hint

Use size_t total_size = size_count + size_flag + size_temperature; and printf("Total memory used: %zu bytes\n", total_size);.

Practice

1. What does the sizeof operator in embedded C tell you?

easy

A. The number of bytes used by a data type or variable

B. The number of bits in a variable

C. The value stored in a variable

D. The memory address of a variable

Solution

1. Step 1: Understand the purpose of sizeof

   The sizeof operator returns the size in bytes of a data type or variable in memory.

2. Step 2: Differentiate from other concepts

   It does not give the value stored, bits count, or address, only the byte size.

3. Final Answer:

   The number of bytes used by a data type or variable -> Option A

4. Quick Check:

   sizeof = bytes used [OK]

Hint: Remember: sizeof = bytes occupied in memory [OK]

Common Mistakes:

• Confusing bytes with bits
• Thinking sizeof returns variable value
• Mixing sizeof with pointer address

2. Which of the following is the correct syntax to get the size of the int data type in embedded C?

easy

A. sizeof(int);

B. sizeof int;

C. size_of(int);

D. sizeof[int];

Solution

1. Step 1: Recall correct sizeof syntax

   The sizeof operator requires parentheses around the variable or type name.

2. Step 2: Check each option

   sizeof(int); uses sizeof(int); which is correct syntax. Options B and D are invalid syntax, and C is not a valid operator.

3. Final Answer:

   sizeof(int); -> Option A

4. Quick Check:

   Use parentheses with sizeof [OK]

Hint: Always use parentheses with sizeof(variable) [OK]

Common Mistakes:

• Omitting parentheses
• Using square brackets instead of parentheses
• Typing size_of instead of sizeof

3. Consider the code snippet:

char arr[10];
int total_size = sizeof(arr);

What is the value of total_size assuming char is 1 byte?

medium

A. 4

B. 40

C. 1

D. 10

Solution

1. Step 1: Calculate size of array

   The array arr has 10 elements of type char, each 1 byte.

2. Step 2: Multiply element size by count

   Total size = 10 elements * 1 byte = 10 bytes.

3. Final Answer:

   10 -> Option D

4. Quick Check:

   Array size = element count x sizeof(element) = 10 [OK]

Hint: Array size = number of elements x sizeof element [OK]

Common Mistakes:

• Confusing element size with total size
• Assuming int size instead of char
• Using sizeof pointer instead of array

4. What is wrong with this code snippet?

int *ptr;
int size = sizeof(ptr) / sizeof(int);
ptr = malloc(size * sizeof(int));

medium

A. malloc is missing a cast to int*

B. sizeof(int) is incorrect, should be sizeof(ptr)

C. sizeof(ptr) returns pointer size, not array size

D. ptr is not initialized before sizeof

Solution

1. Step 1: Understand sizeof on pointer

   sizeof(ptr) returns the size of the pointer itself (usually 4 or 8 bytes), not the size of the array it points to.

2. Step 2: Identify the error in size calculation

   Dividing pointer size by sizeof(int) does not give the number of elements to allocate.

3. Final Answer:

   sizeof(ptr) returns pointer size, not array size -> Option C

4. Quick Check:

   Pointer size ≠ array size [OK]

Hint: sizeof(pointer) gives pointer size, not data size [OK]

Common Mistakes:

• Using sizeof(pointer) to find array length
• Forgetting malloc returns void* needing cast (in C++)
• Assuming pointer is initialized before sizeof

5. You have a memory budget of 73 bytes. You want to store an array of 16-bit integers (short) and a struct:

struct Data {
  char flag;
  int value;
};

If short is 2 bytes, char 1 byte, and int 4 bytes, what is the maximum number of short elements you can store if you also need space for 5 Data structs?

hard

A. 22

B. 24

C. 26

D. 28

Solution

1. Step 1: Calculate size of one Data struct

   Size = size of char + size of int = 1 + 4 = 5 bytes.
   Assuming no padding for simplicity.

2. Step 2: Calculate total size for 5 Data structs

   5 structs x 5 bytes = 25 bytes.

3. Step 3: Calculate remaining memory for shorts

   Total budget 73 bytes - 25 bytes = 48 bytes left.

4. Step 4: Calculate max shorts fitting in remaining memory

   Each short is 2 bytes, so max elements = 48 / 2 = 24 elements.

5. Step 5: Consider struct padding

   Usually, struct Data will be padded to align int at 4 bytes:
   Layout: char flag (1 byte) + 3 bytes padding + int value (4 bytes) = 8 bytes per struct.
   Total for 5 structs = 5 x 8 = 40 bytes.

6. Step 6: Calculate remaining memory with padding

   73 - 40 = 33 bytes left for shorts.

7. Step 7: Calculate max shorts with padding

   33 bytes / 2 bytes per short = 16.5 -> 16 shorts.

8. Step 8: Re-examine options

   Options are larger than 16, so question expects total shorts + structs size ≤ 73.
   Try 24: 24 shorts x 2 bytes = 48 bytes + 5 structs x 8 bytes = 40 bytes -> 88 bytes (too big).

9. Step 9: Reconsider question intent

   Question asks max shorts if 5 structs also stored.
   So total memory = shorts size + structs size ≤ 73 bytes.
   Assuming no padding (5 bytes per struct), total structs = 25 bytes.
   73 - 25 = 48 bytes for shorts -> 48/2 = 24 shorts max.

10. Final Answer:

    24 -> Option B

11. Quick Check:

    Memory budget - structs size = shorts size [OK]

Hint: Subtract struct size from budget, divide remainder by short size [OK]

Common Mistakes:

• Ignoring struct padding/alignment
• Using pointer size instead of actual struct size
• Not subtracting struct memory before shorts calculation