Left shift and right shift behavior in Embedded C - Interactive Code Practice

Practice - 5 Tasks

1fill in blank

easy

Complete the code to left shift the variable value by 2 bits.

Embedded C

int value = 5;
int result = value [1] 2;

Drag options to blanks, or click blank then click option'

A-

B>>

C+

D<<

Attempts:

3 left

💡 Hint

Common Mistakes

Using the right shift operator instead of left shift.

Using addition instead of bit shifting.

The left shift operator << moves bits to the left, effectively multiplying the number by 2 for each shift.

2fill in blank

medium

Complete the code to right shift the variable value by 3 bits.

Embedded C

unsigned int value = 32;
unsigned int result = value [1] 3;

Drag options to blanks, or click blank then click option'

A<<

B>>

C+

D-

Attempts:

3 left

💡 Hint

Common Mistakes

Using left shift instead of right shift.

Using subtraction instead of bit shifting.

The right shift operator >> moves bits to the right, effectively dividing the number by 2 for each shift.

3fill in blank

medium

Fix the error in the code to correctly perform a left shift by 1 bit.

Embedded C

int value = 10;
int result = value [1] 1;

Drag options to blanks, or click blank then click option'

A<<

B>>

C+

D-

Attempts:

3 left

💡 Hint

Common Mistakes

Using right shift operator instead of left shift.

Using arithmetic operators instead of bit shift.

The correct operator for left shift is <<. Using >> would shift bits to the right.

4fill in blank

hard

Fill both blanks to complete the loop that left shifts numbers greater than 3 by 2 bits into the shifted array.

Embedded C

int numbers[] = {1, 2, 3, 4, 5};
int shifted[5];
int idx = 0;
for(int i = 0; i < 5; i++) {
    if(numbers[i] [1] 3) {
        shifted[idx++] = numbers[i] [2] 2;
    }
}

Drag options to blanks, or click blank then click option'

A>

B<<

C<

D>>

Attempts:

3 left

💡 Hint

Common Mistakes

Using less than instead of greater than in the condition.

Using right shift instead of left shift.

The condition uses > to check numbers greater than 3. The left shift operator << shifts bits left by 2.

5fill in blank

hard

Fill all three blanks to create a loop that right shifts each number by 1 bit if it is less than 10, otherwise left shifts by 1 bit.

Embedded C

int numbers[] = {5, 10, 15};
int results[3];
for(int i = 0; i < 3; i++) {
    if(numbers[i] [1] 10) {
        results[i] = numbers[i] [2] 1;
    } else {
        results[i] = numbers[i] [3] 1;
    }
}

Drag options to blanks, or click blank then click option'

A<

B>>

C<<

D>

Attempts:

3 left

💡 Hint

Common Mistakes

Using greater than instead of less than in the condition.

Mixing up left and right shift operators.

The condition uses < to check if the number is less than 10. If true, it right shifts (>>) by 1 bit; otherwise, it left shifts (<<) by 1 bit.