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Embedded Cprogramming~10 mins

GPIO register configuration in Embedded C - Interactive Code Practice

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Practice - 5 Tasks
Answer the questions below
1fill in blank
easy

Complete the code to set the GPIO pin 5 as output.

Embedded C
GPIO_DIR |= (1 << [1]);
Drag options to blanks, or click blank then click option'
A1
B3
C7
D5
Attempts:
3 left
💡 Hint
Common Mistakes
Using the wrong pin number in the shift operation.
Forgetting to use the bitwise OR operator.
2fill in blank
medium

Complete the code to clear GPIO pin 2 output.

Embedded C
GPIO_DATA &= ~([1] << 2);
Drag options to blanks, or click blank then click option'
A0
B2
C1
D3
Attempts:
3 left
💡 Hint
Common Mistakes
Using the wrong value to shift.
Not using the bitwise NOT operator.
3fill in blank
hard

Fix the error in setting GPIO pin 4 high.

Embedded C
GPIO_DATA [1] (1 << 4);
Drag options to blanks, or click blank then click option'
A&=
B|=
C^=
D=
Attempts:
3 left
💡 Hint
Common Mistakes
Using &= which clears bits instead of setting.
Using = which overwrites the entire register.
4fill in blank
hard

Fill both blanks to configure pin 3 as input and enable pull-up resistor.

Embedded C
GPIO_DIR [1]= ~(1 << 3);
GPIO_PUR [2]= (1 << 3);
Drag options to blanks, or click blank then click option'
A&
B|
C~
D^
Attempts:
3 left
💡 Hint
Common Mistakes
Using |= to set direction bit instead of clearing it.
Not enabling pull-up resistor correctly.
5fill in blank
hard

Fill all three blanks to toggle pin 6 output safely.

Embedded C
if (GPIO_DATA & (1 << [1])) {
    GPIO_DATA [2]= ~(1 << [3]);
} else {
    GPIO_DATA |= (1 << 6);
}
Drag options to blanks, or click blank then click option'
A6
B&=
C~
D|=
Attempts:
3 left
💡 Hint
Common Mistakes
Using wrong pin number in the mask.
Using |= instead of &= to clear the bit.

Practice

(1/5)
1. What is the primary purpose of configuring GPIO registers in embedded C?
easy
A. To handle interrupts from external devices
B. To increase the clock speed of the microcontroller
C. To allocate memory for variables
D. To set pins as input or output for hardware interaction

Solution

  1. Step 1: Understand GPIO register role

    GPIO registers control the mode and state of microcontroller pins.
  2. Step 2: Identify the main use

    Setting pins as input or output allows the microcontroller to read sensors or control devices.
  3. Final Answer:

    To set pins as input or output for hardware interaction -> Option D
  4. Quick Check:

    GPIO config = pin mode setup [OK]
Hint: GPIO controls pin direction and state [OK]
Common Mistakes:
  • Confusing GPIO with clock or memory settings
  • Thinking GPIO handles interrupts directly
  • Assuming GPIO sets processor speed
2. Which of the following is the correct way to set bit 3 of a GPIO register named GPIO_DIR to configure pin 3 as output?
easy
A. GPIO_DIR = (1 << 3);
B. GPIO_DIR = GPIO_DIR & (1 << 3);
C. GPIO_DIR = GPIO_DIR | (1 << 3);
D. GPIO_DIR = ~GPIO_DIR | (1 << 3);

Solution

  1. Step 1: Understand bitwise OR for setting bits

    Using OR with (1 << 3) sets bit 3 without changing other bits.
  2. Step 2: Analyze each option

    GPIO_DIR = GPIO_DIR | (1 << 3); correctly sets bit 3. GPIO_DIR = GPIO_DIR & (1 << 3); clears other bits. GPIO_DIR = (1 << 3); overwrites all bits. GPIO_DIR = ~GPIO_DIR | (1 << 3); inverts bits incorrectly.
  3. Final Answer:

    GPIO_DIR = GPIO_DIR | (1 << 3); -> Option C
  4. Quick Check:

    Set bit with OR = correct [OK]
Hint: Use OR (|) to set bits without clearing others [OK]
Common Mistakes:
  • Using AND (&) instead of OR (|) to set bits
  • Overwriting register instead of modifying bits
  • Using NOT (~) incorrectly
3. Given the code snippet:
uint8_t GPIO_DATA = 0x00;
GPIO_DATA |= (1 << 2);
GPIO_DATA &= ~(1 << 0);
GPIO_DATA |= (1 << 0);

What is the final value of GPIO_DATA in hexadecimal?
medium
A. 0x04
B. 0x05
C. 0x01
D. 0x00

Solution

  1. Step 1: Apply each operation step-by-step

    Start: GPIO_DATA = 0x00 (binary 0000 0000).
    After GPIO_DATA |= (1 << 2): sets bit 2 -> 0000 0100 (0x04).
    After GPIO_DATA &= ~(1 << 0): clears bit 0 -> still 0000 0100 (0x04).
    After GPIO_DATA |= (1 << 0): sets bit 0 -> 0000 0101 (0x05).
  2. Step 2: Convert final binary to hex

    Binary 0000 0101 equals hex 0x05.
  3. Final Answer:

    0x05 -> Option B
  4. Quick Check:

    Bit 2 and 0 set = 0x05 [OK]
Hint: Track bits set/cleared stepwise [OK]
Common Mistakes:
  • Ignoring bit clear operation
  • Confusing bit positions
  • Not converting binary to hex correctly
4. Identify the error in this GPIO pin configuration code snippet:
GPIO_DIR &= ~(1 << 5); // Set pin 5 as input
GPIO_DIR |= (1 << 5); // Set pin 5 as output
medium
A. Pin 5 is configured as both input and output, causing conflict
B. Bitwise AND operator is used incorrectly
C. Shift operator should be << 4 instead of << 5
D. GPIO_DIR register cannot be modified directly

Solution

  1. Step 1: Analyze the two lines

    First line clears bit 5 to set pin 5 as input.
    Second line sets bit 5 to set pin 5 as output.
  2. Step 2: Understand the conflict

    Both lines contradict each other immediately, so pin 5 cannot be both input and output at the same time.
  3. Final Answer:

    Pin 5 is configured as both input and output, causing conflict -> Option A
  4. Quick Check:

    Conflicting pin modes = error [OK]
Hint: Avoid setting same pin input and output simultaneously [OK]
Common Mistakes:
  • Overwriting pin mode without delay or condition
  • Misunderstanding bitwise operators
  • Assuming GPIO_DIR is read-only
5. You want to configure pins 0, 2, and 4 as outputs and pins 1, 3, and 5 as inputs using a single 8-bit GPIO_DIR register. Which code snippet correctly sets this configuration without affecting other bits?
hard
A. GPIO_DIR = (GPIO_DIR & 0xAA) | 0x15;
B. GPIO_DIR = (GPIO_DIR & 0x55) | 0x2A;
C. GPIO_DIR = (GPIO_DIR & 0x3F) | 0xC0;
D. GPIO_DIR = (GPIO_DIR & 0xF0) | 0x0F;

Solution

  1. Step 1: Identify bits for outputs and inputs

    Outputs: pins 0,2,4 -> bits 0,2,4 set to 1 -> binary 0001 0101 (0x15).
    Inputs: pins 1,3,5 -> bits 1,3,5 preserved.
  2. Step 2: Use mask to clear bits 0,2,4 before setting

    Mask 0xAA (1010 1010) clears bits 0,2,4 when ANDed.
    Then OR with 0x15 sets output bits.
    So: GPIO_DIR = (GPIO_DIR & 0xAA) | 0x15;
  3. Final Answer:

    GPIO_DIR = (GPIO_DIR & 0xAA) | 0x15; -> Option A
  4. Quick Check:

    Mask inputs, set outputs correctly [OK]
Hint: Clear output bits with mask, then OR to set [OK]
Common Mistakes:
  • Using wrong mask to clear bits
  • Overwriting entire register losing other bits
  • Confusing input bits with output bits
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