Direction register vs data register in Embedded C - Interactive Practice

Practice - 5 Tasks

1fill in blank

easy

Complete the code to set pin 0 of PORTB as output.

Embedded C

DDRB |= (1 << [1]);

Drag options to blanks, or click blank then click option'

A1

B2

C3

D0

Attempts:

3 left

💡 Hint

Common Mistakes

Using PORTB instead of DDRB to set direction.

Setting the wrong bit number.

Setting bit 0 in DDRB configures pin 0 of PORTB as output.

2fill in blank

medium

Complete the code to write a high value to pin 2 of PORTC.

Embedded C

PORTC |= (1 << [1]);

Drag options to blanks, or click blank then click option'

A2

B1

C3

D0

Attempts:

3 left

💡 Hint

Common Mistakes

Using DDRC instead of PORTC to write data.

Setting the wrong bit number.

Setting bit 2 in PORTC writes a high value to pin 2.

3fill in blank

hard

Fix the error in the code to configure pin 1 of PORTD as input.

Embedded C

DDRD [1]= ~(1 << 1);

Drag options to blanks, or click blank then click option'

A|

B&

C^

D=

Attempts:

3 left

💡 Hint

Common Mistakes

Using '|=' instead of '&=' to clear the bit.

Using '=' which overwrites all bits.

Using '&=' with the negated bit clears bit 1, setting pin 1 as input.

4fill in blank

hard

Fill both blanks to set pin 3 of PORTB as output and write it low.

Embedded C

DDRB [1]= (1 << 3);
PORTB [2]= ~(1 << 3);

Drag options to blanks, or click blank then click option'

A|

B&

C=

D^

Attempts:

3 left

💡 Hint

Common Mistakes

Using '|=' or '&=' which only modifies bits, not sets exact value.

Not negating the bit when writing low.

Using '=' sets DDRB bit 3 as output by overwriting the register, and '&=' with negation clears PORTB bit 3 to write it low.

5fill in blank

hard

Fill all three blanks to configure pin 4 of PORTC as output, set it high, and then clear it.

Embedded C

DDRC [1]= (1 << 4);
PORTC [2]= (1 << 4);
PORTC [3]= ~(1 << 4);

Drag options to blanks, or click blank then click option'

A|

B&

C=

D^

Attempts:

3 left

💡 Hint

Common Mistakes

Using '|=' or '&=' which only modifies bits without overwriting.

Not negating the bit mask when clearing the pin.

Using '=' assigns exact values to DDRC and PORTC to set pin 4 output and set it high, then '&=' with negation clears the pin.