Configuring pin as input or output in Embedded C - Interactive Practice

Practice - 5 Tasks

1fill in blank

easy

Complete the code to set pin 5 as an output.

Embedded C

DDRB |= (1 << [1]);

Drag options to blanks, or click blank then click option'

A3

B5

C7

D0

Attempts:

3 left

💡 Hint

Common Mistakes

Using the wrong pin number in the bit shift.

Forgetting to use the bitwise OR operator.

Setting bit 5 in DDRB configures pin 5 as an output.

2fill in blank

medium

Complete the code to configure pin 2 as an input.

Embedded C

DDRD &= ~(1 << [1]);

Drag options to blanks, or click blank then click option'

A1

B3

C4

D2

Attempts:

3 left

💡 Hint

Common Mistakes

Using bitwise OR instead of AND to clear the bit.

Shifting by the wrong pin number.

Clearing bit 2 in DDRD configures pin 2 as an input.

3fill in blank

hard

Fix the error in the code to set pin 7 as output.

Embedded C

DDRC [1] (1 << 7);

Drag options to blanks, or click blank then click option'

A|=

B&=

C^=

D=

Attempts:

3 left

💡 Hint

Common Mistakes

Using '=' which overwrites the entire register.

Using '&=' which clears bits instead of setting.

Use '|=' to set bit 7 without affecting other bits.

4fill in blank

hard

Fill both blanks to configure pin 4 as input and enable pull-up resistor.

Embedded C

DDRB [1] ~(1 << 4);
PORTB [2] (1 << 4);

Drag options to blanks, or click blank then click option'

A&=

B|=

C^=

D=

Attempts:

3 left

💡 Hint

Common Mistakes

Using '=' instead of '&=' or '|='.

Not enabling the pull-up resistor after setting input.

Use '&=' with negated bit mask to set pin as input, and '|=' to enable pull-up resistor.

5fill in blank

hard

Fill all three blanks to configure pin 3 as output, set it high, and clear pin 6 as input.

Embedded C

DDRD [1] (1 << 3);
PORTD [2] (1 << 3);
DDRD [3] ~(1 << 6);

Drag options to blanks, or click blank then click option'

A|=

C&=

D^=

Attempts:

3 left

💡 Hint

Common Mistakes

Using '^=' which toggles bits instead of setting or clearing.

Mixing up PORTD and DDRD registers.

Use '|=' to set pin 3 as output and set it high, and '&=' with negation to clear pin 6 as input.

Practice

1. Which register is used in embedded C to configure a microcontroller pin as input or output?

easy

A. PORT (Data Register)

B. TIMER Register

C. PIN (Input Register)

D. DDR (Data Direction Register)

Solution

1. Step 1: Understand pin configuration registers

   The DDR register controls whether a pin is input or output by setting bits to 0 or 1.

2. Step 2: Identify the correct register for direction

   PORT controls output values, PIN reads input values, TIMER is unrelated to pin direction.

3. Final Answer:

   DDR (Data Direction Register) -> Option D

4. Quick Check:

   DDR sets pin direction [OK]

Hint: Remember DDR sets direction: 1=output, 0=input [OK]

Common Mistakes:

• Confusing PORT with DDR
• Using PIN register to set direction
• Thinking TIMER controls pin mode

2. Which of the following lines correctly sets pin 3 of PORTB as output in embedded C?

easy

A. DDRB |= (1 << 3);

B. DDRB &= ~(1 << 3);

C. PORTB |= (1 << 3);

D. PINB |= (1 << 3);

Solution

1. Step 1: Understand setting pin as output

   To set a pin as output, set its bit in DDR register to 1 using bitwise OR.

2. Step 2: Analyze each option

   DDRB |= (1 << 3); uses DDRB |= (1 << 3) which sets bit 3 to 1 correctly. DDRB &= ~(1 << 3); clears bit 3 (input). Options C and D affect PORTB and PINB, not direction.

3. Final Answer:

   DDRB |= (1 << 3); -> Option A

4. Quick Check:

   Use |= with DDR to set output [OK]

Hint: Use |= with DDR to set output bit [OK]

Common Mistakes:

• Using &= ~ instead of |= to set output
• Modifying PORT or PIN instead of DDR
• Shifting wrong bit position

3. What is the effect of the following code snippet?

DDRC |= (1 << 2);  // Line 1
DDRC &= ~(1 << 2); // Line 2

medium

A. Pin 2 of PORTC is set as output then input

B. Pin 2 of PORTC remains output

C. Pin 2 of PORTC remains input

D. Syntax error in code

Solution

1. Step 1: Analyze Line 1

   DDRC |= (1 << 2) sets bit 2 to 1, configuring pin 2 as output.

2. Step 2: Analyze Line 2

   DDRC &= ~(1 << 2) clears bit 2 to 0, configuring pin 2 as input.

3. Final Answer:

   Pin 2 of PORTC is set as output then input -> Option A

4. Quick Check:

   Set then clear bit changes pin direction [OK]

Hint: |= sets output, &=~ clears to input [OK]

Common Mistakes:

• Thinking both lines set output
• Ignoring second line effect
• Confusing PORTC with DDRC

4. Identify the error in this code that tries to set pin 5 of PORTD as input:

DDRD |= (0 << 5);

medium

A. DDRD cannot be modified directly

B. Bit shift is incorrect, should be (1 << 5)

C. Should use &= ~ instead of |= to set input

D. No error, code is correct

Solution

1. Step 1: Understand setting pin as input

   To set a pin as input, clear its bit in DDR register using &= ~ (bitwise AND with NOT).

2. Step 2: Analyze the code

   DDRD |= (0 << 5) does nothing because (0 << 5) is 0; it does not clear bit 5. Correct way is DDRD &= ~(1 << 5).

3. Final Answer:

   Should use &= ~ instead of |= to set input -> Option C

4. Quick Check:

   Use &= ~ to clear bit for input [OK]

Hint: Use &= ~ to clear bit for input, not |= [OK]

Common Mistakes:

• Using |= with 0 does not clear bit
• Confusing bitwise OR and AND
• Not using bitwise NOT (~) when clearing

5. You want to configure pins 0, 1, and 2 of PORTA as outputs and pins 3 and 4 as inputs without changing other pins. Which code snippet correctly does this?

hard

A. DDRA |= (1 << 0) | (1 << 1) | (1 << 2) | (1 << 3) | (1 << 4);

B. DDRA |= (1 << 0) | (1 << 1) | (1 << 2); DDRA &= ~((1 << 3) | (1 << 4));

C. DDRA |= (1 << 0) & (1 << 1) & (1 << 2); DDRA &= ~((1 << 3) & (1 << 4));

D. DDRA = (1 << 0) | (1 << 1) | (1 << 2); DDRA = ~((1 << 3) | (1 << 4));

Solution

1. Step 1: Set pins 0,1,2 as outputs

   Use bitwise OR to set bits 0,1,2 without affecting others: DDRA |= (1<<0)|(1<<1)|(1<<2);

2. Step 2: Set pins 3,4 as inputs

   Clear bits 3 and 4 using bitwise AND with NOT: DDRA &= ~((1<<3)|(1<<4));

3. Final Answer:

   DDRA |= (1 << 0) | (1 << 1) | (1 << 2); DDRA &= ~((1 << 3) | (1 << 4)); -> Option B

4. Quick Check:

   Use |= to set output bits, &=~ to clear input bits [OK]

Hint: Set outputs with |=, inputs with &= ~ combined masks [OK]

Common Mistakes:

• Overwriting DDRA instead of modifying bits
• Using & instead of | for combining bits
• Setting input pins as output by mistake