Rest machining for remaining material in CNC Programming - Time & Space Complexity
When using rest machining, the machine only works on leftover material from a previous cut.
We want to understand how the time to finish changes as the leftover material changes.
Analyze the time complexity of the following rest machining code snippet.
G90 G54
M06 T1
G00 X0 Y0 Z5
; Rough cut
G01 Z-5 F100
G01 X100 Y0 F200
G01 X100 Y100
G01 X0 Y100
G01 X0 Y0
; Rest machining for leftover
G01 Z-3 F100
G01 X50 Y0 F200
G01 X50 Y50
G01 X0 Y50
G01 X0 Y0
M30
This code first rough cuts a full square, then does rest machining on a smaller leftover area.
Look for repeated movements or loops in the code.
- Primary operation: Linear moves along the leftover material edges.
- How many times: The rest machining moves repeat for each leftover section, smaller than the full cut.
As leftover material size grows, rest machining moves increase roughly in proportion.
| Input Size (leftover area) | Approx. Operations |
|---|---|
| 10 units | About 4 moves |
| 50 units | About 8 moves |
| 100 units | About 12 moves |
Pattern observation: More leftover means more moves, growing roughly in a straight line.
Time Complexity: O(n)
This means the time to finish rest machining grows directly with the size of leftover material.
[X] Wrong: "Rest machining always takes the same time regardless of leftover size."
[OK] Correct: The machine only moves where leftover exists, so less leftover means fewer moves and less time.
Understanding how leftover material affects machining time helps you explain efficiency improvements in manufacturing automation.
"What if the leftover material is split into multiple small areas instead of one big area? How would the time complexity change?"