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CNC Programmingscripting~10 mins

Depth of cut and step-over in CNC Programming - Interactive Code Practice

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Practice - 5 Tasks
Answer the questions below
1fill in blank
easy

Complete the code to set the depth of cut to 2 mm.

CNC Programming
depth_of_cut = [1]  # in millimeters
Drag options to blanks, or click blank then click option'
A2
B0.5
C5
D10
Attempts:
3 left
💡 Hint
Common Mistakes
Choosing a value too large or too small for typical depth of cut.
Confusing depth of cut with step-over.
2fill in blank
medium

Complete the code to set the step-over to 40% of the tool diameter.

CNC Programming
step_over = tool_diameter * [1]  # step-over as fraction
Drag options to blanks, or click blank then click option'
A0.5
B0.4
C0.25
D0.75
Attempts:
3 left
💡 Hint
Common Mistakes
Using 0.4 as 4 instead of 0.4.
Confusing step-over with depth of cut.
3fill in blank
hard

Fix the error in the code to calculate the number of passes needed for a given total depth and depth of cut.

CNC Programming
passes = int(total_depth / [1] + 0.999)  # round up to next whole pass
Drag options to blanks, or click blank then click option'
Adepth_of_cut
Bfeed_rate
Ctool_diameter
Dstep_over
Attempts:
3 left
💡 Hint
Common Mistakes
Using step-over instead of depth of cut in the division.
Using feed rate or tool diameter incorrectly.
4fill in blank
hard

Fill both blanks to create a dictionary showing passes and step-over in mm for a tool diameter of 10 mm and depth of cut 2 mm.

CNC Programming
settings = {'passes': int(total_depth / [1] + 0.999), 'step_over_mm': [2] * tool_diameter}
Drag options to blanks, or click blank then click option'
Adepth_of_cut
B0.4
C0.5
Dstep_over
Attempts:
3 left
💡 Hint
Common Mistakes
Mixing up step-over and depth of cut in calculations.
Using 0.5 instead of 0.4 for step-over.
5fill in blank
hard

Fill all three blanks to create a dictionary comprehension that maps tool names to their step-over in mm, only if step-over is less than 5 mm.

CNC Programming
step_overs = {name: diameter * [1] for name, diameter in tools.items() if diameter * [2] [3] 5}
Drag options to blanks, or click blank then click option'
A0.4
C<
D>
Attempts:
3 left
💡 Hint
Common Mistakes
Using different fractions for calculation and condition.
Using > instead of < in the condition.