Efficient loop construction in ARM Architecture - Interactive Code Practice

Practice - 5 Tasks

1fill in blank

easy

Complete the code to initialize the loop counter register.

ARM Architecture

MOV [1], #10

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AR0

BR3

CR1

DR2

Attempts:

3 left

💡 Hint

Common Mistakes

Using a register reserved for special purposes like R15 (program counter).

Choosing a register not typically used for counters like R3.

The register R1 is commonly used as a loop counter in ARM assembly. Here, it is loaded with the value 10 to control the loop iterations.

2fill in blank

medium

Complete the code to decrement the loop counter register.

ARM Architecture

SUB [1], [1], #1

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AR1

BR0

CR2

DR3

Attempts:

3 left

💡 Hint

Common Mistakes

Decrementing a different register than the one used as the counter.

Using an immediate value other than 1.

The loop counter register R1 is decremented by 1 each iteration to count down the loop.

3fill in blank

hard

Fix the error in the loop condition check to branch if the counter is not zero.

ARM Architecture

CMP [1], #0
BNE loop_start

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AR1

BR0

CR2

DR3

Attempts:

3 left

💡 Hint

Common Mistakes

Comparing the wrong register.

Using a branch instruction that does not check for zero.

The CMP instruction compares the loop counter R1 with zero. The BNE (branch if not equal) instruction branches back to the loop start if R1 is not zero, continuing the loop.

4fill in blank

hard

Fill both blanks to create a loop that counts down from 5 and branches correctly.

ARM Architecture

MOV [1], #5
loop_start:
SUB [2], [2], #1
CMP [2], #0
BNE loop_start

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AR4

BR5

CR6

DR7

Attempts:

3 left

💡 Hint

Common Mistakes

Using different registers for initialization and decrement.

Choosing registers reserved for special purposes.

Register R5 is used as the loop counter. It is initialized to 5, decremented each iteration, and checked against zero to control the loop.

5fill in blank

hard

Fill all three blanks to implement a loop that counts down from 8, decrements the counter, and branches if not zero.

ARM Architecture

MOV [1], #8
loop:
SUB [2], [2], #1
CMP [3], #0
BNE loop

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AR8

BR9

CR10

DR11

Attempts:

3 left

💡 Hint

Common Mistakes

Mixing different registers in the loop instructions.

Using registers reserved for special functions.

Register R9 is used consistently as the loop counter. It is loaded with 8, decremented, and compared to zero to control the loop flow.

Practice

1. What is the main benefit of using efficient loops in ARM assembly programming?

easy

A. They increase the size of the program

B. They remove the need for any instructions

C. They make the code harder to read

D. They make the program run faster and use less power

Solution

1. Step 1: Understand loop efficiency

   Efficient loops reduce the number of instructions and cycles needed to repeat tasks.

2. Step 2: Identify benefits of efficient loops

   Fewer instructions mean faster execution and less power consumption.

3. Final Answer:

   They make the program run faster and use less power -> Option D

4. Quick Check:

   Efficient loops = faster + less power [OK]

Hint: Efficient loops save time and energy [OK]

Common Mistakes:

• Thinking loops increase program size
• Assuming loops make code harder to read
• Believing loops remove all instructions

2. Which ARM instruction is commonly used to efficiently decrease a loop counter and check if it reached zero?

easy

A. SUBS

B. MOV

C. ADD

D. NOP

Solution

1. Step 1: Identify instruction for decrement and flag update

   SUBS subtracts and updates condition flags, useful for loop counters.

2. Step 2: Confirm usage in loops

   SUBS combined with BNE (branch if not equal) creates efficient loops.

3. Final Answer:

   SUBS -> Option A

4. Quick Check:

   SUBS decreases counter and sets flags [OK]

Hint: SUBS subtracts and updates flags for loops [OK]

Common Mistakes:

• Choosing ADD which adds instead of subtracts
• Using MOV which only copies values
• Selecting NOP which does nothing

3. Consider this ARM assembly loop snippet:

    MOV R0, #5
loop:
    SUBS R0, R0, #1
    BNE loop

What will be the final value in register R0 after the loop finishes?

medium

A. 5

B. 0

C. -1

D. 1

Solution

1. Step 1: Trace the loop iterations

   R0 starts at 5, each loop subtracts 1 and checks if zero. Loop runs while R0 != 0.

2. Step 2: Understand SUBS and BNE behavior

   When R0 reaches 1, SUBS makes it 0, BNE skips. But SUBS subtracts before checking, so last value is 0.

3. Step 3: Check final register value

   Actually, SUBS subtracts 1 each time, so after last iteration R0 becomes 0, then BNE fails and loop ends.

4. Final Answer:

   0 -> Option B

5. Quick Check:

   Loop ends when R0 = 0 [OK]

Hint: Loop ends when counter hits zero [OK]

Common Mistakes:

• Thinking R0 stays at initial value
• Assuming R0 becomes negative
• Confusing loop exit condition

4. Identify the error in this ARM loop code:

    MOV R1, #3
start:
    SUB R1, R1, #1
    BNE start

medium

A. BNE should be BEQ

B. MOV should be replaced with ADD

C. SUB should be SUBS to update flags

D. Loop label 'start' is missing a colon

Solution

1. Step 1: Check instruction for loop counter decrement

   SUB does not update condition flags, so BNE cannot check zero condition correctly.

2. Step 2: Correct instruction usage

   SUBS subtracts and updates flags, enabling BNE to branch properly.

3. Final Answer:

   SUB should be SUBS to update flags -> Option C

4. Quick Check:

   Use SUBS for loops with BNE [OK]

Hint: Use SUBS, not SUB, for loop counters [OK]

Common Mistakes:

• Ignoring flag update requirement
• Changing MOV unnecessarily
• Misunderstanding branch instructions

5. You want to create an efficient ARM loop that counts down from 10 to 1 and sums these values in R2. Which loop structure is best?

hard

A. MOV R0, #10
MOV R2, #0
loop:
SUBS R0, R0, #1
ADD R2, R2, R0
BNE loop

B. MOV R0, #10
MOV R2, #0
loop:
SUBS R0, R0, #1
ADD R2, R2, R0
BEQ loop

C. MOV R0, #10
MOV R2, #0
loop:
SUB R0, R0, #1
ADD R2, R2, R0
BNE loop

D. MOV R0, #10
MOV R2, #0
loop:
SUBS R0, R0, #1
ADD R2, R2, #1
BNE loop

Solution

1. Step 1: Analyze loop counter and sum update

   R0 starts at 10, SUBS decrements and updates flags, ADD adds current R0 to R2.

2. Step 2: Check branch condition

   BNE loops while R0 != 0, correctly counting down from 9 to 0 (since SUBS subtracts before add).

3. Step 3: Confirm sum correctness

   Since SUBS subtracts first, R0 goes 9 to 0, sum includes 9 down to 0, which sums 45 (1 to 9). To include 10, initial ADD before loop needed, but given options, this is best.

4. Final Answer:

   SUBS R0, R0, #1; ADD R2, R2, R0; BNE loop -> Option A

5. Quick Check:

   SUBS + BNE + ADD with R0 counter [OK]

Hint: Use SUBS with BNE and add counter value [OK]

Common Mistakes:

• Using BEQ instead of BNE for loop
• Using SUB without flag update
• Adding constant 1 instead of counter value