[Solved] Given the code snippet:RCC->APB1ENR = 0; RCC->APB1ENR |= (1 APB1ENR |= (1 What is the final value of RCC->APB1ENR in binary (8 bits shown)? | ARM Architecture

ARM Architecture - Bus Architecture

Given the code snippet:

RCC->APB1ENR = 0;
RCC->APB1ENR |= (1 << 4);
RCC->APB1ENR |= (1 << 6);

What is the final value of RCC->APB1ENR in binary (8 bits shown)?

A01000000

B01010000

C00010000

D00000000

Step-by-Step Solution

Solution:

Step 1: Analyze bit positions set
Bits 4 and 6 are set to 1 using |= operator.
Step 2: Convert bits to binary
Bit 4 = 00010000, bit 6 = 01000000; combined = 01010000.
Final Answer:
01010000 -> Option B
Quick Check:
Bits 4 and 6 set = 01010000 [OK]

Quick Trick: Add bits set to get final binary value [OK]

Common Mistakes:

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