[Solved] Given the following ARM assembly code snippet, what will be the value in register r2 after execution?CMP r0, r1 BEQ equal_label MOV r2, #0 B end_label equal_label:... | ARM Architecture

ARM Architecture - Control Flow Instructions

Given the following ARM assembly code snippet, what will be the value in register r2 after execution?

CMP r0, r1
BEQ equal_label
MOV r2, #0
B end_label
equal_label:
MOV r2, #1
end_label:

Assume r0 = 5 and r1 = 5.

AUndefined

B0

C5

D1

Step-by-Step Solution

Solution:

Step 1: Analyze the CMP and BEQ instructions
CMP compares r0 and r1. Since both are 5, they are equal, so the zero flag is set. BEQ will branch to equal_label.
Step 2: Follow the branch and MOV instructions
The code jumps to equal_label and executes MOV r2, #1, setting r2 to 1. The instructions after BEQ are skipped.
Final Answer:
1 -> Option D
Quick Check:
Equal values cause BEQ to set r2 to 1 [OK]

Quick Trick: If CMP finds equal, BEQ jumps to set r2=1 [OK]

Common Mistakes:

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Given the following ARM assembly code snippet, what will be the value in register r2 after execution?