[Solved] Given the following code snippet, what is the value of RCC->APB1ENR after execution?RCC->APB1ENR = 0x00000000; RCC->APB1ENR |= (1 APB1ENR |= (1 | ARM Architecture

ARM Architecture - Bus Architecture

Given the following code snippet, what is the value of RCC->APB1ENR after execution?

RCC->APB1ENR = 0x00000000;
RCC->APB1ENR |= (1 << 17);
RCC->APB1ENR |= (1 << 0);

A0x00000001

B0x00020001

C0x00010001

D0x00020000

Step-by-Step Solution

Solution:

Step 1: Start with initial value
RCC->APB1ENR is initially 0x00000000 (all bits cleared).
Step 2: Set bit 17
Setting bit 17 means adding 0x00020000 (1 shifted left 17 places).
Step 3: Set bit 0
Setting bit 0 adds 0x00000001.
Step 4: Calculate final value
0x00000000 + 0x00020000 + 0x00000001 = 0x00020001.
Final Answer:
0x00020001 -> Option B
Quick Check:
Bit 17 + bit 0 set = 0x00020001 [OK]

Quick Trick: Add hex values for each bit set to find final register value [OK]

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Given the following code snippet, what is the value of RCC->APB1ENR after execution?