Type aliases use the 'type' keyword and can define unions like in option C.
Which statement is true about type aliases and interfaces?
AType aliases can represent unions, interfaces cannot
BInterfaces can represent unions, type aliases cannot
CBoth are exactly the same
DNeither can represent object shapes
✗ Incorrect
Type aliases can represent unions and primitives; interfaces mainly describe object shapes.
Explain why type aliases are useful in TypeScript and give an example.
Think about how naming a type helps when you use it many times.
You got /3 concepts.
Describe the difference between type aliases and interfaces in TypeScript.
Consider what kinds of types each can represent.
You got /3 concepts.
Practice
(1/5)
1. Why do we use type aliases in TypeScript?
easy
A. To declare variables without types
B. To execute code faster at runtime
C. To replace interfaces completely
D. To give a simple name to a complex type for easier reuse
Solution
Step 1: Understand the purpose of type aliases
Type aliases let you create a new name for a type, especially useful for complex types.
Step 2: Compare with other options
They do not affect runtime speed, do not replace interfaces fully, and are not for declaring variables without types.
Final Answer:
To give a simple name to a complex type for easier reuse -> Option D
Quick Check:
Type aliases simplify complex types = A [OK]
Hint: Type aliases simplify complex types for reuse [OK]
Common Mistakes:
Thinking type aliases improve runtime speed
Confusing type aliases with interfaces
Using type aliases to declare variables without types
2. Which of the following is the correct syntax to create a type alias for an object with properties name (string) and age (number)?
easy
A. type Person = { name: string; age: number };
B. alias Person = { name: string; age: number };
C. interface Person = { name: string; age: number };
D. type Person: { name: string; age: number };
Solution
Step 1: Recall correct type alias syntax
Type aliases use the keyword type followed by the name, equals sign, and the type definition.
Step 2: Check each option
type Person = { name: string; age: number }; matches the correct syntax. Options A, B, and C use wrong keywords or punctuation. interface Person = { name: string; age: number }; uses interface, not a type alias.
Final Answer:
type Person = { name: string; age: number }; -> Option A
Quick Check:
Correct type alias syntax = D [OK]
Hint: Remember: type alias uses 'type Name = Type;' [OK]
Common Mistakes:
Using 'alias' instead of 'type'
Confusing interfaces with type aliases
Using colon ':' instead of equals '='
3. What will be the output of this TypeScript code?
type ID = string | number;
function printId(id: ID) {
if (typeof id === 'string') {
return id.toUpperCase();
} else {
return id + 1;
}
}
printId(5);
medium
A. 5
B. 6
C. Error: toUpperCase is not a function
D. undefined
Solution
Step 1: Understand the type alias and function logic
The type alias ID allows string or number. The function checks if id is a string, then calls toUpperCase(). Otherwise, it adds 1.
Step 2: Trace the function call with printId(5)
Since 5 is a number, it goes to the else branch and returns 5 + 1 = 6.
Final Answer:
6 -> Option B
Quick Check:
Number input adds 1 = 6 [OK]
Hint: Check type conditions carefully to predict output [OK]
Common Mistakes:
Assuming 5 is treated as string
Expecting error from toUpperCase on number
Ignoring type narrowing in if-else
4. Identify the error in this TypeScript code using a type alias:
type User = {
name: string;
age: number;
};
const user: User = {
name: "Alice",
age: "25"
};
medium
A. Name property should be a number
B. Type alias syntax is incorrect
C. Age property should be a number, not a string
D. Missing semicolon after user object
Solution
Step 1: Check the type alias definition
The User type requires age to be a number.
Step 2: Check the object assigned to user
The age property is given as a string "25", which conflicts with the number type.
Final Answer:
Age property should be a number, not a string -> Option C
Quick Check:
Type mismatch in property = B [OK]
Hint: Match property types exactly as defined [OK]
Common Mistakes:
Ignoring type mismatch errors
Thinking semicolon is mandatory after object
Confusing type alias syntax with interface
5. You want to create a reusable type alias for a function that takes a string and returns a boolean. Which of these is the best way to define it and use it in a function?
hard
A. type StringCheck = (input: string) => boolean;
const isLong: StringCheck = input => input.length > 5;
B. type StringCheck = string => boolean;
const isLong: StringCheck = input => input.length > 5;
C. type StringCheck = (string) => bool;
const isLong: StringCheck = input => input.length > 5;
D. type StringCheck = (input: string) => bool;
const isLong: StringCheck = input => input.length > 5;
Solution
Step 1: Review correct function type alias syntax
Function types use the form (param: type) => returnType. Boolean type is boolean in TypeScript.
Step 2: Check each option for syntax correctness
type StringCheck = (input: string) => boolean;
const isLong: StringCheck = input => input.length > 5; correctly defines the type alias and uses it. Options A, B, and D have incorrect syntax for function types. type StringCheck = (input: string) => bool;
const isLong: StringCheck = input => input.length > 5; uses bool which is invalid in TypeScript.
Final Answer:
type StringCheck = (input: string) => boolean;
const isLong: StringCheck = input => input.length > 5; -> Option A
Quick Check:
Correct function type alias syntax = C [OK]
Hint: Function types use (param: type) => returnType syntax [OK]
Common Mistakes:
Using 'bool' instead of 'boolean'
Omitting parameter names or types
Incorrect arrow function type syntax
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