Strict null checks and safety in Typescript - Mini Project: Build & Apply

Strict null checks and safety

📖 Scenario: You are building a simple user profile system where some user information might be missing. You want to make sure your TypeScript code safely handles cases where values can be null or undefined.

🎯 Goal: Create a TypeScript program that uses strict null checks to safely access user data and avoid runtime errors.

📋 What You'll Learn

Create a user object with some properties possibly null or undefined.

Add a configuration variable to control if the user is active.

Use strict null checks to safely access user properties.

Print the user's name or a default message if the name is missing.

💡 Why This Matters

🌍 Real World

Handling user data safely is important in web apps where some information might be missing or optional.

💼 Career

Strict null checks help prevent runtime errors and improve code quality in TypeScript projects.

1

Create a user object with nullable properties

Create a constant called user with type { name: string | null; age: number | undefined; } and assign it the value { name: null, age: undefined }.

Typescript

# Create a constant called user with nullable properties
# Your code here

Hint

Use | null and | undefined to allow properties to be missing.

2

Add an active status configuration variable

Create a boolean variable called isActive and set it to true.

Typescript

const user: { name: string | null; age: number | undefined } = { name: null, age: undefined };
# Create a boolean variable called isActive and set it to true
# Your code here

Hint

Use let isActive: boolean = true; to declare the variable.

3

Use strict null checks to safely access user name

Create a constant called displayName that uses a conditional expression to assign user.name if it is not null, otherwise assign the string 'Guest'.

Typescript

const user: { name: string | null; age: number | undefined } = { name: null, age: undefined };
let isActive: boolean = true;
# Create displayName using conditional expression to check if user.name is not null
# Your code here

Hint

Use user.name !== null ? user.name : 'Guest' to safely assign the name.

4

Print the display name

Write a console.log statement to print the value of displayName.

Typescript

const user: { name: string | null; age: number | undefined } = { name: null, age: undefined };
let isActive: boolean = true;
const displayName: string = user.name !== null ? user.name : 'Guest';
# Print displayName using console.log
# Your code here

Hint

Use console.log(displayName); to show the result.

Practice

1.

What does enabling strictNullChecks in TypeScript do?

easy

A. It allows assigning null to any type without errors.

B. It automatically converts all null values to empty strings.

C. It disables type checking for null and undefined.

D. It forces you to explicitly handle null and undefined values.

Solution

1. Step 1: Understand strictNullChecks purpose

   Enabling strictNullChecks makes TypeScript require explicit handling of null and undefined values to avoid runtime errors.

2. Step 2: Analyze options

   Only It forces you to explicitly handle null and undefined values. correctly describes this behavior. Options B, C, and D are incorrect because they describe behaviors that strictNullChecks does not do.

3. Final Answer:

   It forces you to explicitly handle null and undefined values. -> Option D

4. Quick Check:

   strictNullChecks = explicit null handling [OK]

Hint: Remember: strictNullChecks means no silent nulls [OK]

Common Mistakes:

• Thinking nulls are automatically converted
• Assuming null checks are disabled
• Believing null can be assigned anywhere

2.

Which of the following is the correct way to check for null or undefined before accessing a variable value in TypeScript with strictNullChecks enabled?

let value: string | null | undefined;

easy

A. if (value !== null && value !== undefined) { console.log(value.length); }

B. if (value) { console.log(value.length); }

C. console.log(value.length);

D. if (value == null) { console.log(value.length); }

Solution

1. Step 1: Understand null and undefined checks

   With strictNullChecks, you must check both null and undefined explicitly before accessing properties.

2. Step 2: Evaluate each option

   if (value !== null && value !== undefined) { console.log(value.length); } correctly checks both null and undefined. if (value) { console.log(value.length); } may fail if value is an empty string. console.log(value.length); causes an error. if (value == null) { console.log(value.length); } checks for null but then accesses length inside the if, which is incorrect logic.

3. Final Answer:

   if (value !== null && value !== undefined) { console.log(value.length); } -> Option A

4. Quick Check:

   Check both null and undefined explicitly [OK]

Hint: Use !== null && !== undefined to be safe [OK]

Common Mistakes:

• Using only if(value) which fails on empty strings
• Accessing properties without checks
• Using == null but then accessing inside that block

3.

What will be the output of the following TypeScript code with strictNullChecks enabled?

function greet(name: string | null) {
  if (name === null) {
    return "Hello, guest!";
  }
  return `Hello, ${name.toUpperCase()}!`;
}

console.log(greet(null));
console.log(greet("alice"));

medium

A. "Hello, null!" and "Hello, ALICE!"

B. "Hello, guest!" and "Hello, ALICE!"

C. Compilation error due to missing null check

D. Runtime error on null input

Solution

1. Step 1: Analyze null check in function

   The function checks if name === null and returns "Hello, guest!" in that case, so it safely handles null.

2. Step 2: Check outputs for calls

   Calling greet(null) returns "Hello, guest!". Calling greet("alice") returns "Hello, ALICE!" because toUpperCase() is called on a string.

3. Final Answer:

   "Hello, guest!" and "Hello, ALICE!" -> Option B

4. Quick Check:

   Null check prevents errors, outputs as expected [OK]

Hint: Check null before using string methods [OK]

Common Mistakes:

• Expecting runtime error on null
• Thinking compilation error occurs
• Ignoring null check and causing error

4.

Identify the error in this TypeScript code with strictNullChecks enabled and suggest a fix:

function printLength(text: string | null) {
  console.log(text.length);
}

medium

A. Error: Object is possibly 'null'. Fix: Add a null check before accessing length.

B. Error: Missing return type. Fix: Add : void to function.

C. Error: text should be string only. Fix: Remove null from type.

D. No error. Code is correct.

Solution

1. Step 1: Identify the error

   Accessing text.length without checking if text is null causes a compile error under strictNullChecks.

2. Step 2: Suggest fix

   Add a check like if (text !== null) before accessing length to ensure safety.

3. Final Answer:

   Error: Object is possibly 'null'. Fix: Add a null check before accessing length. -> Option A

4. Quick Check:

   Always check null before property access [OK]

Hint: Add null checks before property access [OK]

Common Mistakes:

• Ignoring null check and expecting no error
• Changing type instead of fixing code
• Thinking return type causes error

5.

Given this TypeScript function with strictNullChecks enabled, which modification safely handles undefined and null inputs without errors?

function formatName(name: string | null | undefined) {
  return name.toUpperCase();
}

hard

A. Use non-null assertion: return name!.toUpperCase();

B. Change parameter type to string only and remove null and undefined.

C. Add a check: if (name == null) return "Unknown"; before calling toUpperCase().

D. Remove strictNullChecks from tsconfig.

Solution

1. Step 1: Identify unsafe code

   Calling toUpperCase() on name without checking for null or undefined causes errors with strictNullChecks.

2. Step 2: Evaluate options for safety

   Add a check: if (name == null) return "Unknown"; before calling toUpperCase(). adds a check for both null and undefined (using == null) and returns a default string, safely avoiding errors. Change parameter type to string only and remove null and undefined. removes null safety but is less flexible. Use non-null assertion: return name!.toUpperCase(); forces non-null assertion which can cause runtime errors. Remove strictNullChecks from tsconfig. disables safety feature, not recommended.

3. Final Answer:

   Add a check: if (name == null) return "Unknown"; before calling toUpperCase(). -> Option C

4. Quick Check:

   Check null/undefined before method calls [OK]

Hint: Use if(name == null) to check null and undefined together [OK]

Common Mistakes:

• Using non-null assertion unsafely
• Removing null from type instead of checking
• Disabling strictNullChecks instead of fixing code