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Typescriptprogramming~10 mins

Rest parameters with types in Typescript - Interactive Code Practice

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Practice - 5 Tasks
Answer the questions below
1fill in blank
easy

Complete the code to declare a function with rest parameters typed as numbers.

Typescript
function sum(...numbers: [1]) { return numbers.reduce((a, b) => a + b, 0); }
Drag options to blanks, or click blank then click option'
Astring[]
Bnumber[]
Cany
Dboolean[]
Attempts:
3 left
💡 Hint
Common Mistakes
Using 'any' instead of a specific type.
Forgetting to use array syntax '[]' for rest parameters.
2fill in blank
medium

Complete the code to type the rest parameter as an array of strings.

Typescript
function greetAll(...greetings: [1]) { greetings.forEach(greet => console.log(greet)); }
Drag options to blanks, or click blank then click option'
Astring[]
Bstring
CArray<string>
Dany[]
Attempts:
3 left
💡 Hint
Common Mistakes
Using 'string' instead of 'string[]'.
Using 'any[]' which is less specific.
3fill in blank
hard

Fix the error by correctly typing the rest parameter as an array of booleans.

Typescript
function checkFlags(...flags: [1]) { return flags.every(flag => flag === true); }
Drag options to blanks, or click blank then click option'
Aany
BArray<boolean>
Cboolean
Dboolean[]
Attempts:
3 left
💡 Hint
Common Mistakes
Using 'boolean' instead of 'boolean[]'.
Using 'any' which is not specific.
4fill in blank
hard

Fill both blanks to declare a function with rest parameters typed as an array of numbers and return their product.

Typescript
function multiplyAll(...[1]: [2]) { return [1].reduce((a, b) => a * b, 1); }
Drag options to blanks, or click blank then click option'
Anums
Bnumber[]
Cvalues
Dstring[]
Attempts:
3 left
💡 Hint
Common Mistakes
Using a string array type instead of number array.
Forgetting to name the rest parameter.
5fill in blank
hard

Fill all three blanks to declare a function with rest parameters typed as strings, filter those longer than 3 characters, and return the filtered array.

Typescript
function filterLongStrings(...[1]: [2]): [2] { return [1].filter(str => str.length > 3); }
Drag options to blanks, or click blank then click option'
Awords
Bstring[]
Cnumber[]
Dany[]
Attempts:
3 left
💡 Hint
Common Mistakes
Using 'number[]' or 'any[]' instead of 'string[]'.
Mismatching parameter and return types.

Practice

(1/5)
1. What does the rest parameter syntax ...args: number[] do in a TypeScript function?
easy
A. It collects all remaining arguments into an array of numbers.
B. It restricts the function to accept only one number argument.
C. It declares a single number variable named args.
D. It spreads an array of numbers into separate arguments.

Solution

  1. Step 1: Understand rest parameter syntax

    The ...args gathers all extra arguments passed to the function into one array.
  2. Step 2: Recognize the type annotation

    The : number[] means this array contains only numbers.
  3. Final Answer:

    It collects all remaining arguments into an array of numbers. -> Option A
  4. Quick Check:

    Rest parameter with type = collects arguments as typed array [OK]
Hint: Rest parameters gather extra arguments into a typed array [OK]
Common Mistakes:
  • Confusing rest parameter with spread operator
  • Thinking it accepts only one argument
  • Ignoring the type annotation on the rest parameter
2. Which of the following is the correct syntax to declare a function with a rest parameter of strings in TypeScript?
easy
A. function greet(...names: string[]) {}
B. function greet(names: ...string[]) {}
C. function greet(...names: string) {}
D. function greet(...names: [string]) {}

Solution

  1. Step 1: Identify correct rest parameter syntax

    The rest parameter must use ... before the parameter name and be typed as an array type.
  2. Step 2: Check each option

    function greet(...names: string[]) {} uses ...names: string[], which is correct. Others misuse the spread or array syntax.
  3. Final Answer:

    function greet(...names: string[]) {} -> Option A
  4. Quick Check:

    Rest parameter syntax = ...name: type[] [OK]
Hint: Rest parameter needs ... before name and array type after [OK]
Common Mistakes:
  • Placing ... after the parameter name
  • Using a single type instead of an array type
  • Using tuple syntax instead of array type
3. What is the output of this TypeScript code?
function sum(...nums: number[]) {
  return nums.reduce((a, b) => a + b, 0);
}
console.log(sum(1, 2, 3, 4));
medium
A. 1234
B. Error: nums is not iterable
C. undefined
D. 10

Solution

  1. Step 1: Understand rest parameter collects arguments

    The ...nums collects all arguments into an array: [1, 2, 3, 4].
  2. Step 2: Calculate sum using reduce

    The reduce adds all numbers: 1+2=3, 3+3=6, 6+4=10.
  3. Final Answer:

    10 -> Option D
  4. Quick Check:

    Sum of 1,2,3,4 = 10 [OK]
Hint: Rest gathers numbers; reduce sums them [OK]
Common Mistakes:
  • Concatenating numbers as strings
  • Forgetting initial value in reduce
  • Misunderstanding rest parameter as single number
4. Identify the error in this TypeScript function:
function joinStrings(...strings: string) {
  return strings.join(", ");
}
medium
A. The function should return an array, not a string.
B. The join method cannot be used on strings.
C. Rest parameter must be typed as an array, e.g., string[].
D. Rest parameter cannot be used with strings.

Solution

  1. Step 1: Check rest parameter type

    The rest parameter must be typed as an array type, like string[], not just string.
  2. Step 2: Understand why join fails

    Since strings is typed as a single string, join method is invalid.
  3. Final Answer:

    Rest parameter must be typed as an array, e.g., string[]. -> Option C
  4. Quick Check:

    Rest parameter type = array type [OK]
Hint: Rest parameter type must be an array type [OK]
Common Mistakes:
  • Typing rest parameter as a single element type
  • Trying to call array methods on a non-array
  • Ignoring TypeScript type errors
5. You want to create a TypeScript function multiplyAll that accepts any number of numeric arguments and returns their product. Which is the best way to type the rest parameter and implement this function?
hard
A. function multiplyAll(nums: number[]): number { return nums.reduce((a, b) => a * b); }
B. function multiplyAll(...nums: number[]): number { return nums.reduce((a, b) => a * b, 1); }
C. function multiplyAll(...nums: number): number { return nums.reduce((a, b) => a * b, 1); }
D. function multiplyAll(...nums: any[]): any { return nums.reduce((a, b) => a * b, 0); }

Solution

  1. Step 1: Choose correct rest parameter typing

    The rest parameter must be typed as number[] to accept multiple numbers.
  2. Step 2: Implement product with correct initial value

    Use reduce with initial value 1 to multiply all numbers correctly.
  3. Step 3: Evaluate options

    function multiplyAll(...nums: number[]): number { return nums.reduce((a, b) => a * b, 1); } matches correct typing and logic. function multiplyAll(nums: number[]): number { return nums.reduce((a, b) => a * b); } lacks rest parameter. function multiplyAll(...nums: number): number { return nums.reduce((a, b) => a * b, 1); } has wrong type. function multiplyAll(...nums: any[]): any { return nums.reduce((a, b) => a * b, 0); } uses any and wrong initial value.
  4. Final Answer:

    function multiplyAll(...nums: number[]): number { return nums.reduce((a, b) => a * b, 1); } -> Option B
  5. Quick Check:

    Rest parameter typed number[] and reduce with 1 = correct [OK]
Hint: Rest parameter as number[] and reduce with 1 for product [OK]
Common Mistakes:
  • Using single number type instead of array for rest
  • Forgetting initial value in reduce
  • Using any type losing type safety
  • Starting reduce with 0 causing product always 0
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