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Swiftprogramming~15 mins

Extending built-in types in Swift - Mini Project: Build & Apply

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Extending built-in types
📖 Scenario: Imagine you want to add a new feature to Swift's built-in Int type. You want to check if a number is even or odd easily, just like calling a simple property.
🎯 Goal: You will create an extension to the Int type that adds a computed property called isEven. This property will return true if the number is even, and false if it is odd.
📋 What You'll Learn
Create an extension for the built-in Int type
Add a computed property called isEven that returns a Bool
Use the modulo operator (%) to determine if a number is even
Test the new property with a few example numbers
Print the results to the console
💡 Why This Matters
🌍 Real World
Extending built-in types lets you add useful features to existing data types without changing their original code. This helps keep your code clean and reusable.
💼 Career
Many Swift developers extend built-in types to add custom behavior, making their apps more expressive and easier to maintain.
Progress0 / 4 steps
1
Create an integer variable
Create a variable called number and set it to the integer 10.
Swift
Hint

Use var number = 10 to create the variable.

2
Create an extension for Int
Create an extension for the built-in Int type. Inside it, add a computed property called isEven that returns a Bool. For now, just return false inside the property.
Swift
Hint

Use extension Int { var isEven: Bool { return false } } to create the extension and property.

3
Implement the isEven logic
Change the isEven computed property to return true if the number is even, and false if it is odd. Use the modulo operator % to check if self % 2 == 0.
Swift
Hint

Use return self % 2 == 0 inside the computed property.

4
Test and print the result
Use print to display the result of number.isEven. This will show true if number is even, or false if odd.
Swift
Hint

Use print(number.isEven) to show the result.

Practice

(1/5)
1. What is the main purpose of extending built-in types in Swift?
easy
A. To change the stored properties of existing types
B. To delete existing methods from built-in types
C. To add new methods or computed properties to existing types
D. To create subclasses of built-in types

Solution

  1. Step 1: Understand what extensions do

    Extensions allow adding new methods or computed properties to existing types without subclassing.
  2. Step 2: Identify what extensions cannot do

    Extensions cannot add stored properties or delete existing methods.
  3. Final Answer:

    To add new methods or computed properties to existing types -> Option C
  4. Quick Check:

    Extensions add methods/properties = B [OK]
Hint: Remember: extensions add features, not stored data [OK]
Common Mistakes:
  • Thinking extensions can add stored properties
  • Confusing extensions with subclassing
  • Believing extensions can remove methods
2. Which of the following is the correct syntax to extend the built-in Int type with a method isEven() that returns a Bool?
easy
A. extension Int { func isEven() -> Bool { return self % 2 == 0 } }
B. extend Int { func isEven() -> Bool { return self % 2 == 0 } }
C. extension Int { func isEven { return self % 2 == 0 } }
D. extension Int { isEven() -> Bool { return self % 2 == 0 } }

Solution

  1. Step 1: Identify the correct keyword for extension

    Swift uses the keyword extension to add methods to existing types.
  2. Step 2: Check method syntax

    The method must have parentheses and a return type: func isEven() -> Bool. The body uses self % 2 == 0.
  3. Final Answer:

    extension Int { func isEven() -> Bool { return self % 2 == 0 } } -> Option A
  4. Quick Check:

    Correct extension syntax = D [OK]
Hint: Use 'extension' keyword and full method signature [OK]
Common Mistakes:
  • Using 'extend' instead of 'extension'
  • Omitting parentheses in method declaration
  • Missing 'func' keyword before method name
3. Consider this Swift code:
extension String {
    func reversedString() -> String {
        return String(self.reversed())
    }
}

let word = "hello"
print(word.reversedString())

What is the output when this code runs?
medium
A. Error: reversed() not found
B. hello
C. nil
D. olleh

Solution

  1. Step 1: Understand the extension method

    The method reversedString() returns a new String made by reversing the characters of the original string.
  2. Step 2: Apply method to 'hello'

    Reversing "hello" results in "olleh".
  3. Final Answer:

    olleh -> Option D
  4. Quick Check:

    String reversed = olleh [OK]
Hint: Remember reversed() returns characters reversed [OK]
Common Mistakes:
  • Expecting original string output
  • Thinking reversed() returns an error
  • Confusing reversed() with reverse()
4. What is wrong with this Swift extension code?
extension Double {
    var squared: Double {
        return self * self
    }

    var storedValue: Double = 0.0
}
medium
A. Extensions cannot add stored properties like 'storedValue'
B. Computed properties must use 'func' keyword
C. The 'squared' property must be a method, not a property
D. The extension must be declared as 'class extension'

Solution

  1. Step 1: Review extension property rules

    Extensions can add computed properties but cannot add stored properties.
  2. Step 2: Identify the stored property

    The line var storedValue: Double = 0.0 tries to add a stored property, which is not allowed.
  3. Final Answer:

    Extensions cannot add stored properties like 'storedValue' -> Option A
  4. Quick Check:

    No stored properties in extensions = A [OK]
Hint: Remember: only computed properties allowed in extensions [OK]
Common Mistakes:
  • Trying to add stored properties in extensions
  • Confusing computed properties with stored properties
  • Thinking extensions require 'class' keyword
5. You want to extend the built-in Array type in Swift to add a method secondElement() that returns the second element if it exists, or nil otherwise. Which of the following extensions correctly implements this?
hard
A. extension Array { func secondElement() -> Element { return self[1] } }
B. extension Array { func secondElement() -> Element? { return self.count > 1 ? self[1] : nil } }
C. extension Array { var secondElement: Element? { if self.count >= 2 { return self[2] } else { return nil } } }
D. extension Array { func secondElement() -> Element? { if self.count > 0 { return self[1] } else { return nil } } }

Solution

  1. Step 1: Check method signature and return type

    The method should return an optional Element (Element?) because the second element might not exist.
  2. Step 2: Verify index and condition

    Arrays are zero-indexed, so the second element is at index 1. The condition should check if count > 1 to safely access index 1.
  3. Step 3: Compare options

    The correct one uses ternary operator: return self.count > 1 ? self[1] : nil. The non-optional return crashes on short arrays. The computed property uses index 2 (third element). The if-else checks count > 0, allowing index 1 access when count == 1, causing runtime crash.
  4. Final Answer:

    extension Array { func secondElement() -> Element? { return self.count > 1 ? self[1] : nil } } -> Option B
  5. Quick Check:

    Safe optional return with index 1 = A [OK]
Hint: Check array count > 1 and return optional Element [OK]
Common Mistakes:
  • Accessing wrong index (like 2 instead of 1)
  • Returning non-optional Element causing crash
  • Using computed property but with wrong index
Recommended

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10 questions~5 mineasy hard