Base class and subclass in Swift

Introduction

Base classes let you create a general blueprint. Subclasses let you make special versions that add or change things.

When you want to share common features between different objects.

When you want to create a general type and then make more specific types from it.

When you want to reuse code and avoid repeating yourself.

When you want to organize your code in a clear, logical way.

When you want to add new features to an existing class without changing it.

Syntax

Swift

class BaseClass {
    // properties and methods
}

class SubClass: BaseClass {
    // extra properties and methods
}

Use a colon : to show that one class is a subclass of another.

The subclass gets all the properties and methods of the base class automatically.

Examples

Here, Dog is a subclass of Animal. It can do everything Animal can, plus bark.

Swift

class Animal {
    func sound() {
        print("Some sound")
    }
}

class Dog: Animal {
    func bark() {
        print("Woof!")
    }
}

Bicycle changes the number of wheels and the drive behavior from the base Vehicle class.

Swift

class Vehicle {
    var wheels = 4
    func drive() {
        print("Driving")
    }
}

class Bicycle: Vehicle {
    override var wheels: Int {
        get { 2 }
        set { }
    }
    override func drive() {
        print("Pedaling the bicycle")
    }
}

Sample Program

This program shows a base class Person and a subclass Student. The subclass adds a new property and changes the greeting.

Swift

class Person {
    var name: String
    init(name: String) {
        self.name = name
    }
    func greet() {
        print("Hello, my name is \(name)")
    }
}

class Student: Person {
    var school: String
    init(name: String, school: String) {
        self.school = school
        super.init(name: name)
    }
    override func greet() {
        print("Hi, I'm \(name) and I study at \(school)")
    }
}

let person = Person(name: "Alice")
person.greet()

let student = Student(name: "Bob", school: "Greenwood High")
student.greet()

Important Notes

Use override keyword when a subclass changes a method or property from the base class.

Call super.init() in subclass initializers to set up the base class part.

Subclasses inherit all non-private properties and methods from the base class.

Summary

Base classes provide a general template.

Subclasses extend or change the base class features.

Use inheritance to reuse code and organize related classes.

Practice

1. What is the main purpose of a base class in Swift?

easy

A. To prevent other classes from inheriting

B. To provide a general template for other classes to build upon

C. To store data only without any functions

D. To create instances that cannot be used

Solution

1. Step 1: Understand the role of a base class

   A base class defines common properties and methods that other classes can reuse.

2. Step 2: Compare options with this role

   To provide a general template for other classes to build upon correctly states the base class is a general template. Other options describe incorrect or unrelated roles.

3. Final Answer:

   To provide a general template for other classes to build upon -> Option B

4. Quick Check:

   Base class = general template [OK]

Hint: Base class = general template for subclasses [OK]

Common Mistakes:

• Thinking base class cannot be inherited
• Confusing base class with instances
• Assuming base class only stores data

2. Which of the following is the correct way to declare a subclass named Dog inheriting from a base class Animal in Swift?

easy

A. class Dog inherits Animal { }

B. class Dog extends Animal { }

C. class Dog: Animal { }

D. class Dog < Animal { }

Solution

1. Step 1: Recall Swift subclass syntax

   In Swift, a subclass is declared using a colon (:) after the subclass name followed by the base class name.

2. Step 2: Match options to syntax

   class Dog: Animal { } uses class Dog: Animal { }, which is correct. Other options use incorrect keywords or symbols.

3. Final Answer:

   class Dog: Animal { } -> Option C

4. Quick Check:

   Subclass syntax = colon (:) [OK]

Hint: Use colon (:) to inherit in Swift class declaration [OK]

Common Mistakes:

• Using 'inherits' or 'extends' keywords (not Swift)
• Using wrong symbols like <
• Omitting the colon between subclass and base class

3. Consider this Swift code:

class Vehicle {
    func sound() -> String {
        return "Vroom"
    }
}

class Car: Vehicle {
    override func sound() -> String {
        return "Beep"
    }
}

let myCar = Car()
print(myCar.sound())

What will be printed when this code runs?

medium

A. "Beep"

B. "Vroom"

C. Compilation error

D. "Car"

Solution

1. Step 1: Understand method overriding in subclass

   The subclass Car overrides the sound() method to return "Beep" instead of the base class "Vroom".

2. Step 2: Identify which method is called

   When calling myCar.sound(), the overridden method in Car runs, returning "Beep".

3. Final Answer:

   "Beep" -> Option A

4. Quick Check:

   Overridden method runs = "Beep" [OK]

Hint: Overridden methods in subclass replace base methods [OK]

Common Mistakes:

• Expecting base class method output
• Confusing method override with overload
• Thinking print shows class name

4. Identify the error in this Swift subclass declaration:

class Animal {
    func speak() {
        print("Animal sound")
    }
}

class Cat: Animal {
    func speak() {
        print("Meow")
    }
}

medium

A. Class names must be lowercase

B. Base class cannot have methods

C. Subclass cannot have methods with same name

D. Missing override keyword before speak() in subclass

Solution

1. Step 1: Check method overriding rules in Swift

   When a subclass provides its own version of a base class method, it must use the override keyword.

2. Step 2: Identify missing override keyword

   The speak() method in Cat lacks override, causing a compile error.

3. Final Answer:

   Missing override keyword before speak() in subclass -> Option D

4. Quick Check:

   Override keyword required for method override [OK]

Hint: Use override keyword when redefining base methods [OK]

Common Mistakes:

• Forgetting override keyword
• Thinking subclass methods cannot have same name
• Assuming class names must be lowercase

5. You want to create a base class Employee with a property name and a method work() that prints "Working". Then create a subclass Manager that overrides work() to print "Managing team" and adds a new method holdMeeting() that prints "Meeting started".

Which code correctly implements this?

hard

A. class Employee {
var name: String
init(name: String) {
self.name = name
}
func work() {
print("Working")
}
}

class Manager: Employee {
override func work() {
print("Managing team")
}
func holdMeeting() {
print("Meeting started")
}
}

B. class Employee {
var name: String
func work() {
print("Working")
}
}

class Manager: Employee {
func work() {
print("Managing team")
}
func holdMeeting() {
print("Meeting started")
}
}

C. class Employee {
var name: String
init(name: String) {
self.name = name
}
func work() {
print("Working")
}
}

class Manager: Employee {
func work() {
print("Managing team")
}
func holdMeeting() {
print("Meeting started")
}
}

D. class Employee {
var name: String
init(name: String) {
self.name = name
}
func work() {
print("Working")
}
}

class Manager: Employee {
override func work() {
print("Managing team")
}
}

Solution

1. Step 1: Check base class implementation

   The base class Employee must have a name property with initializer and a work() method printing "Working". class Employee { var name: String init(name: String) { self.name = name } func work() { print("Working") } } class Manager: Employee { override func work() { print("Managing team") } func holdMeeting() { print("Meeting started") } } and C have correct base class with initializer.

2. Step 2: Check subclass overrides and new method

   The subclass Manager must override work() with override keyword and add holdMeeting(). class Employee { var name: String init(name: String) { self.name = name } func work() { print("Working") } } class Manager: Employee { override func work() { print("Managing team") } func holdMeeting() { print("Meeting started") } } correctly uses override and adds holdMeeting(). class Employee { var name: String init(name: String) { self.name = name } func work() { print("Working") } } class Manager: Employee { func work() { print("Managing team") } func holdMeeting() { print("Meeting started") } } misses override. class Employee { var name: String func work() { print("Working") } } class Manager: Employee { func work() { print("Managing team") } func holdMeeting() { print("Meeting started") } } misses initializer in base class. class Employee { var name: String init(name: String) { self.name = name } func work() { print("Working") } } class Manager: Employee { override func work() { print("Managing team") } } misses holdMeeting().

3. Final Answer:

   Option A code correctly implements all requirements -> Option A

4. Quick Check:

   Override + new method + initializer = class Employee { var name: String init(name: String) { self.name = name } func work() { print("Working") } } class Manager: Employee { override func work() { print("Managing team") } func holdMeeting() { print("Meeting started") } } [OK]

Hint: Use override keyword and add new methods in subclass [OK]

Common Mistakes:

• Forgetting override keyword in subclass
• Missing initializer in base class
• Not adding new methods in subclass