A computed property does not store a value directly. Instead, it provides a getter and optionally a setter to calculate a value when accessed or set.
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beginner
How do you define a read-only computed property in Swift?
You define a computed property with only a getter and no setter. For example:
var area: Double { return width * height }
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intermediate
Can computed properties have side effects in Swift?
Yes, computed properties can run code inside their getter or setter, so they can have side effects like logging or updating other values.
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beginner
What is the difference between stored and computed properties?
Stored properties hold actual values in memory. Computed properties calculate values on demand without storing them.
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intermediate
Show an example of a computed property with both getter and setter in Swift.
Example:
var temperatureCelsius: Double { get { return (temperatureFahrenheit - 32) * 5 / 9 } set { temperatureFahrenheit = newValue * 9 / 5 + 32 } }
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What does a computed property in Swift do?
ACannot have a setter
BStores a fixed value in memory
CCalculates a value when accessed
DOnly stores strings
✗ Incorrect
Computed properties calculate and return a value when accessed, instead of storing it.
Which keyword is used to define a computed property in Swift?
Alet
Bvar
Cfunc
Dclass
✗ Incorrect
Computed properties are defined using 'var' because their value can change.
Can a computed property have a setter in Swift?
AYes, to allow setting a new value
BNo, computed properties are read-only
COnly if marked with 'let'
DOnly inside structs
✗ Incorrect
Computed properties can have a setter to update related values.
What happens if a computed property has only a getter?
AIt causes a compile error
BIt can be set
CIt stores a value
DIt is read-only
✗ Incorrect
A computed property with only a getter is read-only.
Which of these is NOT true about computed properties?
AThey store values directly
BThey can have side effects
CThey use get and set blocks
DThey calculate values on demand
✗ Incorrect
Computed properties do not store values directly; they calculate them.
Explain what a computed property is and how it differs from a stored property in Swift.
Think about how values are stored or calculated.
You got /3 concepts.
Write a simple Swift computed property that calculates the area of a rectangle given width and height stored properties.
Use a getter to calculate the area.
You got /4 concepts.
Practice
(1/5)
1. What is a computed property in Swift?
easy
A. A property that can only be set but not read
B. A property that stores a fixed value permanently
C. A property that calculates its value dynamically when accessed
D. A property that is declared outside a class or struct
Solution
Step 1: Understand property types in Swift
Stored properties hold fixed values, while computed properties calculate values dynamically.
Step 2: Identify computed property behavior
Computed properties use code to return a value each time they are accessed instead of storing it.
Final Answer:
A property that calculates its value dynamically when accessed -> Option C
Quick Check:
Computed property = dynamic value calculation [OK]
Hint: Computed properties calculate values on demand, not stored [OK]
Common Mistakes:
Confusing computed properties with stored properties
Thinking computed properties store values permanently
Assuming computed properties cannot have setters
2. Which of the following is the correct syntax for a computed property with a getter in Swift?
easy
A. var area: Double get { width * height }
B. var area: Double = width * height
C. var area: Double { get { width * height } }
D. var area: Double { return width * height }
Solution
Step 1: Recall computed property syntax
Computed properties use curly braces with a getter that returns a value.
Step 2: Check each option
var area: Double { return width * height } correctly uses braces and return keyword. var area: Double = width * height is stored property syntax. var area: Double { width * height } misses return keyword. var area: Double get { width * height } has incorrect getter syntax.
Final Answer:
var area: Double { return width * height } -> Option D
Quick Check:
Computed property getter uses braces and return [OK]
Hint: Use braces and return keyword for computed property getter [OK]
Common Mistakes:
Omitting the return keyword inside getter
Using equals sign instead of braces
Incorrect getter syntax without braces
3. Consider this Swift struct:
struct Rectangle {
var width: Double
var height: Double
var area: Double {
return width * height
}
}
let rect = Rectangle(width: 3, height: 4)
print(rect.area)
What is the output?
medium
A. Compilation error
B. 12.0
C. 0.0
D. 7.0
Solution
Step 1: Understand the struct and computed property
Rectangle has width=3 and height=4. The computed property area returns width * height.
Step 2: Calculate the area value
3 * 4 = 12.0, so rect.area returns 12.0.
Final Answer:
12.0 -> Option B
Quick Check:
3 * 4 = 12.0 [OK]
Hint: Multiply width and height to get area from computed property [OK]
Common Mistakes:
Confusing stored and computed properties
Expecting area to be zero by default
Thinking code causes compilation error
4. Identify the error in this Swift code using a computed property:
struct Circle {
var radius: Double
var diameter: Double {
get {
return radius * 2
}
set {
radius = newValue / 2
}
}
}
let c = Circle(radius: 5)
c.diameter = 20
print(c.radius)
medium
A. Cannot assign to property 'radius' because 'c' is a constant
B. Missing return keyword in getter
C. Setter syntax is incorrect
D. No error, code runs and prints 10
Solution
Step 1: Analyze variable mutability
Variable 'c' is declared with 'let', making it immutable (constant).
Step 2: Understand setter behavior
Setter tries to modify 'radius' property, but 'c' is constant, so assignment is not allowed.
Final Answer:
Cannot assign to property 'radius' because 'c' is a constant -> Option A
Quick Check:
Constant instance cannot change properties via setter [OK]
Hint: Use var, not let, to allow property setters to modify instance [OK]
Common Mistakes:
Ignoring that 'let' makes instance immutable
Thinking setter syntax is wrong
Missing return keyword confusion
5. You want to create a Swift struct Temperature that stores a temperature in Celsius and has a computed property fahrenheit to get and set the temperature in Fahrenheit. Which implementation correctly updates Celsius when Fahrenheit is set?
hard
A. struct Temperature {
var celsius: Double
var fahrenheit: Double {
get { return celsius * 9 / 5 + 32 }
set { celsius = (newValue - 32) * 5 / 9 }
}
}
B. struct Temperature {
var celsius: Double
var fahrenheit: Double {
get { return celsius + 32 }
set { celsius = newValue - 32 }
}
}
C. struct Temperature {
var celsius: Double
var fahrenheit: Double {
get { return celsius * 2 + 30 }
set { celsius = (newValue - 30) / 2 }
}
}
D. struct Temperature {
var celsius: Double
var fahrenheit: Double {
get { return celsius * 5 / 9 + 32 }
set { celsius = (newValue - 32) * 9 / 5 }
}
}
struct Temperature {
var celsius: Double
var fahrenheit: Double {
get { return celsius * 9 / 5 + 32 }
set { celsius = (newValue - 32) * 5 / 9 }
}
} uses correct formulas in getter and setter. The other options use incorrect formulas.
Final Answer:
The implementation with correct conversion formulas -> Option A
Quick Check:
Correct formulas = struct Temperature {
var celsius: Double
var fahrenheit: Double {
get { return celsius * 9 / 5 + 32 }
set { celsius = (newValue - 32) * 5 / 9 }
}
} [OK]
Hint: Use correct math formulas for temperature conversion in getter/setter [OK]
Common Mistakes:
Mixing up Celsius and Fahrenheit formulas
Using addition instead of multiplication
Forgetting to update Celsius in setter
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