Bird
Raised Fist0
Swiftprogramming~10 mins

Codable protocol for encoding/decoding in Swift - Interactive Code Practice

Choose your learning style10 modes available
Practice - 5 Tasks
Answer the questions below
1fill in blank
easy

Complete the code to make the struct conform to Codable.

Swift
struct User: [1] {
    var name: String
    var age: Int
}
Drag options to blanks, or click blank then click option'
ACodable
BEquatable
CHashable
DIdentifiable
Attempts:
3 left
💡 Hint
Common Mistakes
Using Equatable instead of Codable.
Forgetting to conform to any protocol.
2fill in blank
medium

Complete the code to encode the user instance to JSON data.

Swift
let user = User(name: "Alice", age: 30)
let encoder = JSONEncoder()
let data = try? encoder.[1](user)
Drag options to blanks, or click blank then click option'
Aencode
Bserialize
Cdecode
Dconvert
Attempts:
3 left
💡 Hint
Common Mistakes
Using decode instead of encode.
Trying to use serialize or convert which are not methods of JSONEncoder.
3fill in blank
hard

Fix the error in decoding JSON data to a User instance.

Swift
let decoder = JSONDecoder()
let user = try? decoder.[1](User.self, from: jsonData)
Drag options to blanks, or click blank then click option'
Aencode
Bserialize
Cdecode
Dconvert
Attempts:
3 left
💡 Hint
Common Mistakes
Using encode instead of decode.
Trying to use serialize or convert which are not methods of JSONDecoder.
4fill in blank
hard

Fill both blanks to create a dictionary from an array of users with their names as keys.

Swift
let users = [User(name: "Bob", age: 25), User(name: "Carol", age: 28)]
let userDict = Dictionary(uniqueKeysWithValues: users.map { [1] in ([1].[2], [1].age) })
Drag options to blanks, or click blank then click option'
Auser
Bname
Cage
Ditem
Attempts:
3 left
💡 Hint
Common Mistakes
Using property names instead of variable names in the closure parameters.
Mixing up the order of variables.
5fill in blank
hard

Fill all three blanks to encode a User instance and convert it to a JSON string.

Swift
let user = User(name: "Dave", age: 40)
let encoder = JSONEncoder()
if let data = try? encoder.[1](user) {
    let jsonString = String(data: data, encoding: [2])
    print(jsonString ?? [3])
}
Drag options to blanks, or click blank then click option'
Aencode
Butf8
C"Invalid JSON"
Ddecode
Attempts:
3 left
💡 Hint
Common Mistakes
Using decode instead of encode.
Using wrong encoding like ascii.
Not providing a fallback string.

Practice

(1/5)
1. What is the main purpose of the Codable protocol in Swift?
easy
A. To create user interfaces quickly
B. To enable easy encoding and decoding of data to formats like JSON
C. To manage memory automatically
D. To handle network requests

Solution

  1. Step 1: Understand Codable's role

    The Codable protocol allows Swift types to be encoded to and decoded from external representations like JSON.
  2. Step 2: Compare with other options

    Options B, C, and D relate to UI, memory, and networking, which are unrelated to Codable.
  3. Final Answer:

    To enable easy encoding and decoding of data to formats like JSON -> Option B
  4. Quick Check:

    Codable = encoding/decoding data [OK]
Hint: Codable means convert data to/from JSON easily [OK]
Common Mistakes:
  • Confusing Codable with UI or networking protocols
  • Thinking Codable manages memory
  • Assuming Codable is for database operations
2. Which of the following is the correct way to declare a struct that supports encoding and decoding using Codable?
easy
A. struct User: Codable { var name: String; var age: Int }
B. struct User { var name: String; var age: Int }
C. struct User: Encodable { var name: String; var age: Int }
D. struct User: Decodable { var name: String; var age: Int }

Solution

  1. Step 1: Check Codable conformance

    To support both encoding and decoding, the struct must conform to Codable, which combines Encodable and Decodable.
  2. Step 2: Analyze options

    struct User: Codable { var name: String; var age: Int } correctly uses : Codable. Options C and D only support encoding or decoding, not both. struct User { var name: String; var age: Int } has no conformance.
  3. Final Answer:

    struct User: Codable { var name: String; var age: Int } -> Option A
  4. Quick Check:

    Use Codable to encode and decode both ways [OK]
Hint: Use Codable to encode and decode both ways [OK]
Common Mistakes:
  • Using only Encodable or Decodable when both needed
  • Forgetting to add Codable conformance
  • Declaring struct without protocol conformance
3. Given the following code, what will be printed?
struct Person: Codable {
    var name: String
    var age: Int
}

let jsonData = "{\"name\": \"Anna\", \"age\": 30}".data(using: .utf8)!
let decoder = JSONDecoder()
if let person = try? decoder.decode(Person.self, from: jsonData) {
    print(person.name)
} else {
    print("Failed to decode")
}
medium
A. Anna
B. Failed to decode
C. 30
D. nil

Solution

  1. Step 1: Decode JSON string to Person

    The JSON string matches the Person struct keys and types, so decoding succeeds.
  2. Step 2: Print the name property

    Since decoding succeeds, person.name is "Anna", which is printed.
  3. Final Answer:

    Anna -> Option A
  4. Quick Check:

    Decoded name = Anna [OK]
Hint: Match JSON keys exactly to struct properties [OK]
Common Mistakes:
  • Mismatching JSON keys and struct properties
  • Not unwrapping optional data safely
  • Confusing print output with age value
4. What is wrong with this code snippet that tries to decode JSON into a struct conforming to Codable?
struct Product: Codable {
    var id: Int
    var name: String
}

let json = "{\"id\": 101, \"title\": \"Book\"}"
let data = json.data(using: .utf8)!
let decoder = JSONDecoder()
let product = try? decoder.decode(Product.self, from: data)
medium
A. The JSON string is not valid JSON
B. The struct does not conform to Codable
C. The JSON key "title" does not match the struct property "name"
D. The decoder is not initialized properly

Solution

  1. Step 1: Compare JSON keys with struct properties

    The JSON has key "title" but the struct expects "name"; this mismatch causes decoding to fail.
  2. Step 2: Check other code parts

    The struct conforms to Codable, JSON is valid, and decoder is correctly initialized, so no issues there.
  3. Final Answer:

    The JSON key "title" does not match the struct property "name" -> Option C
  4. Quick Check:

    JSON keys must match struct properties exactly [OK]
Hint: JSON keys must match struct property names exactly [OK]
Common Mistakes:
  • Ignoring key name mismatches
  • Assuming decoder setup causes error
  • Not validating JSON format
5. You want to encode a struct with an optional property that should be omitted from the JSON if it is nil. Which approach using Codable is correct?
hard
A. Declare the property as optional and use JSONEncoder's default behavior
B. Use Decodable instead of Codable
C. Make the property non-optional and assign a default value
D. Use a custom encode(to:) method to skip encoding nil properties

Solution

  1. Step 1: Understand default Codable behavior

    By default, JSONEncoder encodes optional properties as null if nil, not omitting them.
  2. Step 2: Use custom encoding to omit nil

    To omit nil optional properties, implement a custom encode(to:) method and encode only non-nil values.
  3. Step 3: Evaluate other options

    Declare the property as optional and use JSONEncoder's default behavior keeps nulls, C changes property type, B is unrelated to encoding.
  4. Final Answer:

    Use a custom encode(to:) method to skip encoding nil properties -> Option D
  5. Quick Check:

    Custom encode(to:) omits nil optionals [OK]
Hint: Custom encode(to:) skips nil optionals in JSON [OK]
Common Mistakes:
  • Expecting default encoder to omit nil optionals
  • Making optional properties non-optional unnecessarily
  • Confusing Decodable with encoding behavior
Recommended

Ready to prove it?

Pass the test and this pattern moves unknown strong while earning +1 Grip toward your certificate.

10 questions~5 mineasy hard