Why Swift for Apple and beyond - Test Your Understanding

Practice - 5 Tasks

1fill in blank

easy

Complete the code to print a welcome message in Swift.

Swift

print([1])

Drag options to blanks, or click blank then click option'

AHello, Swift!

Bprintln("Hello, Swift!")

Cprint("Hello, Swift!")

D"Hello, Swift!"

Attempts:

3 left

💡 Hint

Common Mistakes

Forgetting the quotes around the text.

Trying to print without quotes causes an error.

In Swift, text must be inside double quotes to be a string. So, "Hello, Swift!" is correct.

2fill in blank

medium

Complete the code to declare a constant named 'platform' with value 'Apple'.

Swift

let [1] = "Apple"

Drag options to blanks, or click blank then click option'

Aplatform

BPlatform

Capple

Ddevice

Attempts:

3 left

💡 Hint

Common Mistakes

Using uppercase 'Platform' instead of lowercase.

Using a different variable name.

We want the constant named exactly platform as stated.

3fill in blank

hard

Fix the error in the function that returns a greeting message.

Swift

func greet() -> String {
    return [1]
}

Drag options to blanks, or click blank then click option'

A"Hello Swift"

BHello Swift

Cprint("Hello Swift")

Dreturn "Hello Swift"

Attempts:

3 left

💡 Hint

Common Mistakes

Returning text without quotes causes an error.

Using print inside return is incorrect.

The function must return a string value. The string needs quotes. So "Hello Swift" is correct.

4fill in blank

hard

Fill both blanks to create a dictionary of Apple platforms and their release years.

Swift

let platforms = ["iOS": [1], "macOS": [2]]

Drag options to blanks, or click blank then click option'

A2007

B2001

C2010

D1999

Attempts:

3 left

💡 Hint

Common Mistakes

Mixing up the years for iOS and macOS.

Using years not related to Apple platforms.

iOS was released in 2007 and macOS in 2001.

5fill in blank

hard

Fill all three blanks to create a filtered dictionary of platforms released after 2005.

Swift

let recentPlatforms = Dictionary(uniqueKeysWithValues: platforms.filter { ([1], [2]) in [3] > 2005 })

Drag options to blanks, or click blank then click option'

Aname

Byear

Cplatform

DreleaseYear

Attempts:

3 left

💡 Hint

Common Mistakes

Using variable names that don't match like 'name' or 'releaseYear'.

Confusing keys and values, e.g., using 'platform' in the numeric condition.

We destructure each dictionary entry into platform (key) and year (value) in the filter closure parameters, then filter where year > 2005. Dictionary(uniqueKeysWithValues:) reconstructs the dictionary from the filtered (key, value) pairs.