Switch with where clauses in Swift - Interactive Code Practice

Practice - 5 Tasks

1fill in blank

easy

Complete the code to match the number 10 in the switch statement.

Swift

let number = 10
switch number {
case  [1]:
    print("Number is ten")
default:
    print("Number is something else")
}

Drag options to blanks, or click blank then click option'

A5

B15

C20

D10

Attempts:

3 left

💡 Hint

Common Mistakes

Choosing a number different from 10 will not match the case.

The case must match the value 10 to print "Number is ten".

2fill in blank

medium

Complete the where clause to check if the number is even.

Swift

let number = 8
switch number {
case let x where x [1] 2 == 0:
    print("Even number")
default:
    print("Odd number")
}

Drag options to blanks, or click blank then click option'

A-

B+

C%

D*

Attempts:

3 left

💡 Hint

Common Mistakes

Using + or - instead of % will not check evenness.

The modulo operator (%) checks the remainder. If remainder is 0 when divided by 2, the number is even.

3fill in blank

hard

Fix the error in the where clause to check if the number is positive.

Swift

let number = -3
switch number {
case let x where x [1] 0:
    print("Positive number")
default:
    print("Non-positive number")
}

Drag options to blanks, or click blank then click option'

A<

B>

C==

D!=

Attempts:

3 left

💡 Hint

Common Mistakes

Using < will check for negative numbers instead.

To check if a number is positive, it must be greater than 0.

4fill in blank

hard

Fill both blanks to check if the number is between 1 and 10 inclusive.

Swift

let number = 7
switch number {
case let x where x [1] 1 && x [2] 10:
    print("Number is between 1 and 10")
default:
    print("Number is out of range")
}

Drag options to blanks, or click blank then click option'

A>=

B<

C<=

D>

Attempts:

3 left

💡 Hint

Common Mistakes

Using > or < only excludes the boundary numbers.

The number should be greater than or equal to 1 and less than or equal to 10.

5fill in blank

hard

Fill both blanks to check if the number is odd and greater than 5.

Swift

let number = 7
switch number {
case let x where x [1] 2 != 0 && x [2] 5:
    print("Odd number greater than 5")
default:
    print("Other number")
}

Drag options to blanks, or click blank then click option'

A%

B>

C==

D<

Attempts:

3 left

💡 Hint

Common Mistakes

Using == 0 checks even numbers, not odd.

The modulo operator % checks oddness (not equal to 0), and > 5 checks if number is greater than 5.