Numeric literal formats in Swift - Interactive Code Practice

Practice - 5 Tasks

1fill in blank

easy

Complete the code to declare a hexadecimal integer literal.

Swift

let hexNumber = 0[1]1A

Drag options to blanks, or click blank then click option'

Ab

Bo

Cx

Dd

Attempts:

3 left

💡 Hint

Common Mistakes

Using 0b or 0o instead of 0x for hexadecimal.

Forgetting the letter after 0.

In Swift, hexadecimal literals start with 0x.

2fill in blank

medium

Complete the code to declare a binary integer literal.

Swift

let binaryNumber = 0[1]1011

Drag options to blanks, or click blank then click option'

Ax

Bo

Cd

Db

Attempts:

3 left

💡 Hint

Common Mistakes

Using 0x or 0o instead of 0b for binary.

Omitting the prefix.

Binary literals in Swift start with 0b.

3fill in blank

hard

Fix the error in the code to declare an octal integer literal.

Swift

let octalNumber = 0[1]17

Drag options to blanks, or click blank then click option'

Ao

Bx

Cb

Dd

Attempts:

3 left

💡 Hint

Common Mistakes

Using 0b or 0x instead of 0o for octal.

Writing octal numbers without prefix.

Octal literals in Swift start with 0o.

4fill in blank

hard

Fill both blanks to declare a floating-point literal with an exponent.

Swift

let floatNumber = 1.25[1]3[2]2

Drag options to blanks, or click blank then click option'

Ae

Bp

C+

D-

Attempts:

3 left

💡 Hint

Common Mistakes

Using 'p' instead of 'e' for decimal exponents.

Omitting the sign after the exponent.

Floating-point literals with decimal exponents use e followed by a plus or minus sign.

5fill in blank

hard

Fill all three blanks to declare a hexadecimal floating-point literal with a negative exponent.

Swift

let hexFloat = 0x1.[1]p[2][3]

Drag options to blanks, or click blank then click option'

A8

B4

C-

D+

Attempts:

3 left

💡 Hint

Common Mistakes

Using 'e' instead of 'p' for hexadecimal floating-point literals.

Omitting the sign before the exponent.

Hexadecimal floating-point literals use p followed by a sign and exponent number.