Nested functions in Swift - Time & Space Complexity
When we use nested functions, we want to know how the time it takes to run grows as the input gets bigger.
We ask: How does calling a function inside another affect the total work done?
Analyze the time complexity of the following code snippet.
func outerFunction(_ n: Int) {
func innerFunction(_ m: Int) {
for i in 0..
This code defines a function inside another. The outer function calls the inner one multiple times, each time with a different number.
Identify the loops, recursion, array traversals that repeat.
- Primary operation: The inner loop inside
innerFunctionthat runs from 0 tom. - How many times: The outer loop calls
innerFunctionntimes, withmchanging from 0 up ton-1.
Each time the outer loop runs, the inner loop runs more times than before.
| Input Size (n) | Approx. Operations |
|---|---|
| 10 | About 45 prints (0+1+2+...+9) |
| 100 | About 4,950 prints |
| 1000 | About 499,500 prints |
Pattern observation: The total work grows roughly like the sum of numbers from 0 to n-1, which grows much faster than just n.
Time Complexity: O(n²)
This means if you double the input size, the work roughly quadruples because of the nested calls.
[X] Wrong: "Since the inner function runs inside the outer loop, the time is just O(n) because it looks like one loop inside another."
[OK] Correct: The inner loop runs a different number of times each call, adding up to much more than just n times. It's the total sum of all inner loops that matters.
Understanding how nested functions affect time helps you explain your code clearly and shows you can think about efficiency in real problems.
"What if the inner function always ran a fixed number of times, say 10, no matter the input? How would the time complexity change?"
Practice
Solution
Step 1: Understand the definition of nested functions
Nested functions are functions written inside other functions to organize code better.Step 2: Match the definition to the options
A function defined inside another function correctly describes a function inside another function, which is the definition of nested functions.Final Answer:
A function defined inside another function -> Option CQuick Check:
Nested function = function inside function [OK]
- Confusing nested with recursive functions
- Thinking nested functions are global
- Mixing nested with returning functions
Solution
Step 1: Review Swift function syntax
Functions are defined with 'func name() { }'. Nested functions follow the same syntax inside another function.Step 2: Check each option for correct syntax
func outer() { func inner() { } } uses correct syntax with braces for both outer and inner functions. Others have missing braces or wrong order.Final Answer:
func outer() { func inner() { } } -> Option AQuick Check:
Nested function syntax = func inside func with braces [OK]
- Omitting braces for inner function
- Using semicolon instead of braces
- Placing 'func' keyword incorrectly
func greet() {
func sayHello() {
print("Hello")
}
sayHello()
}
greet()Solution
Step 1: Understand function calls inside nested functions
The outer function 'greet' defines 'sayHello' inside it and calls it once.Step 2: Trace the execution
Calling 'greet()' runs 'sayHello()', which prints "Hello" once.Final Answer:
Hello -> Option AQuick Check:
Nested call prints once = Hello [OK]
- Thinking inner function runs twice
- Assuming inner function is global
- Expecting no output because inner function is nested
func calculate() {
innerFunc()
func innerFunc() {
print("Inside inner")
}
}
calculate()Solution
Step 1: Analyze function call order
The code calls 'innerFunc()' before it is defined inside 'calculate()'. Swift requires functions to be defined before use.Step 2: Understand Swift's function declaration rules
Calling a nested function before its declaration causes a compile-time error.Final Answer:
innerFunc() called before its definition causes error -> Option DQuick Check:
Call before definition = error [OK]
- Assuming nested functions can be called before definition
- Thinking missing return type causes error here
- Believing nested functions can't be defined inside
Solution
Step 1: Understand the goal
We want a function that returns another function adding a fixed number 'x' to input 'y'.Step 2: Check each option's logic
func makeAdder(_ x: Int) -> (Int) -> Int { func adder(y: Int) -> Int { return x + y } return adder } defines nested 'adder' using 'x' and returns it correctly. func makeAdder(_ x: Int) -> Int { func adder(y: Int) -> Int { return x + y } return adder(5) } returns a value, not a function. func makeAdder(_ x: Int) -> (Int) -> Int { return func(y: Int) -> Int { x + y } } has invalid syntax. func makeAdder(_ x: Int) -> (Int) -> Int { func adder(y: Int) -> Int { return y } return adder } returns a function ignoring 'x'.Final Answer:
func makeAdder(_ x: Int) -> (Int) -> Int { func adder(y: Int) -> Int { return x + y } return adder } -> Option BQuick Check:
Nested function returns function adding x = func makeAdder(_ x: Int) -> (Int) -> Int { func adder(y: Int) -> Int { return x + y } return adder } [OK]
- Returning a value instead of a function
- Incorrect nested function syntax
- Ignoring outer function parameter inside nested function
Ready to prove it?
Pass the test and this pattern moves unknown
