What if you could instantly know if two things are truly one and the same, not just lookalikes?
Why Identity operators (=== and !==) in Swift? - Purpose & Use Cases
Imagine you have two boxes that look the same and hold the same toys, but you want to know if they are actually the exact same box, not just similar.
Without identity operators, you might compare the contents of the boxes and get confused if they look alike but are actually different boxes. This can lead to mistakes and extra work checking each box carefully.
Identity operators (=== and !==) let you quickly check if two things are the exact same object in memory, like checking if two keys open the same lock, saving time and avoiding errors.
if box1 == box2 { print("Boxes look the same") }
if box1 === box2 { print("Boxes are the exact same") }
This lets you easily tell if two variables point to the same object, which is crucial for managing shared resources or avoiding duplicate work.
When building an app, you might want to know if two buttons are actually the same button instance to update it correctly without creating duplicates.
Identity operators check if two references point to the exact same object.
They help avoid confusion between similar but different objects.
Using them makes your code clearer and more efficient when managing objects.
Practice
=== check in Swift?Solution
Step 1: Understand the purpose of
The======operator checks if two references point to the same object in memory.Step 2: Differentiate from value equality
Unlike==, which checks value equality,===checks identity (same instance).Final Answer:
If two variables refer to the exact same class instance -> Option CQuick Check:
===checks identity [OK]
- Confusing === with == for value equality
- Using === with structs or value types
- Thinking === checks type equality
a and b are NOT the same object in Swift?Solution
Step 1: Identify the correct identity operator for inequality
The operator to check if two references are NOT the same object is!==.Step 2: Verify syntax correctness
Options C and D have invalid operators. if a != b uses!=which checks value inequality, not identity.Final Answer:
if a !== b -> Option DQuick Check:
Use !== for identity inequality [OK]
- Using != instead of !== for identity check
- Typing invalid operators like !=== or !====
- Confusing identity operators with value operators
class Person {}
let p1 = Person()
let p2 = p1
let p3 = Person()
print(p1 === p2)
print(p1 === p3)What will be the output?
Solution
Step 1: Analyze the references
p2is assigned top1, so both point to the same object.p3is a new instance.Step 2: Evaluate identity comparisons
p1 === p2is true because they are the same instance.p1 === p3is false because they are different instances.Final Answer:
true\nfalse -> Option AQuick Check:
Same instance = true, different instance = false [OK]
- Assuming p1 and p3 are same because same class
- Confusing value equality with identity
- Forgetting p2 points to p1's instance
struct Point {
var x: Int
var y: Int
}
let p1 = Point(x: 1, y: 2)
let p2 = Point(x: 1, y: 2)
if p1 === p2 {
print("Same point")
}Solution
Step 1: Identify the types used
Pointis a struct, which is a value type in Swift.Step 2: Understand identity operator restrictions
Identity operators===and!==only work with class instances (reference types), not value types like structs.Final Answer:
Cannot use === with structs because they are value types -> Option BQuick Check:
=== only for class instances [OK]
- Trying to use === with value types
- Assuming structs have identity
- Ignoring compiler error message
Car and an array of Car instances. You want to find if a specific Car instance myCar is already in the array by identity (same object), not by value. Which Swift code correctly checks this?Solution
Step 1: Understand identity check in collections
To check if an instance exists by identity, use===inside a closure withcontains(where:).Step 2: Analyze options
if cars.contains(where: { $0 === myCar }) { print("Found") } uses===correctly. Options B and C use==orof:which check value equality or require Equatable conformance. if cars.filter({ $0 == myCar }).count > 0 { print("Found") } uses==which is value equality.Final Answer:
if cars.contains(where: { $0 === myCar }) { print("Found") } -> Option AQuick Check:
Use contains(where:) with === for identity [OK]
- Using contains(myCar) which checks value equality
- Assuming == checks identity
- Not using closure for identity check
Ready to prove it?
Pass the test and this pattern moves unknown
