Function declaration syntax in Swift - Interactive Code Practice

Practice - 5 Tasks

1fill in blank

easy

Complete the code to declare a function named greet.

Swift

func [1]() {
    print("Hello!")
}

Drag options to blanks, or click blank then click option'

Agreet

BsayHello

Chello

DprintGreeting

Attempts:

3 left

💡 Hint

Common Mistakes

Using a different function name than requested.

Forgetting to write the function name after func.

The function name should be greet as specified.

2fill in blank

medium

Complete the code to declare a function named add that takes two Int parameters.

Swift

func add(_ a: Int, _ b: Int) -> Int {
    return a [1] b
}

Drag options to blanks, or click blank then click option'

A/

B-

C*

D+

Attempts:

3 left

💡 Hint

Common Mistakes

Using subtraction or multiplication instead of addition.

Forgetting to return the result.

The function should add the two parameters, so the operator is +.

3fill in blank

hard

Fix the error in the function declaration to correctly return a String.

Swift

func welcomeMessage(name: String) -> [1] {
    return "Welcome, \(name)!"
}

Drag options to blanks, or click blank then click option'

AString

BBool

CInt

DVoid

Attempts:

3 left

💡 Hint

Common Mistakes

Using the wrong return type like Int or Bool.

Forgetting to specify the return type.

The function returns a greeting message, which is a String.

4fill in blank

hard

Fill both blanks to declare a function that takes a Double and returns its square as Double.

Swift

func square(number: [1]) -> [2] {
    return number * number
}

Drag options to blanks, or click blank then click option'

ADouble

BInt

CString

DBool

Attempts:

3 left

💡 Hint

Common Mistakes

Using different types for parameter and return value.

Using Int instead of Double.

The parameter and return type are both Double because the function squares a Double number.

5fill in blank

hard

Fill all three blanks to declare a function that returns a dictionary with keys as uppercase strings and values as their lengths for words longer than 3 letters.

Swift

func wordLengths(words: [String]) -> [String: Int] {
    return words.filter { $0.count [3] 3 }.reduce(into: [String: Int]()) { result, word in result[[1]] = [2] }
}

Drag options to blanks, or click blank then click option'

Aword.uppercased()

Bword.count

C>

D<

Attempts:

3 left

💡 Hint

Common Mistakes

Using lowercase words as keys.

Using wrong comparison operators.

Mixing up keys and values.

The function creates a dictionary with uppercase words as keys and their lengths as values, filtering words longer than 3 letters.