Bird
Raised Fist0
Swiftprogramming~20 mins

Default parameter values in Swift - Practice Problems & Coding Challenges

Choose your learning style10 modes available
Challenge - 5 Problems
🎖️
Swift Default Parameter Master
Get all challenges correct to earn this badge!
Test your skills under time pressure!
❓ Predict Output
intermediate
2:00remaining
Output of function with default parameters
What is the output of this Swift code when calling greet() without any arguments?
Swift
func greet(name: String = "Friend", greeting: String = "Hello") {
    print("\(greeting), \(name)!")
}
greet()
AError: Missing arguments
BHello, !
CFriend, Hello!
DHello, Friend!
Attempts:
2 left
💡 Hint
Check the default values assigned to the parameters in the function definition.
❓ Predict Output
intermediate
2:00remaining
Function call with one default parameter overridden
What will be printed when calling greet(name: "Alice") with the function below?
Swift
func greet(name: String = "Friend", greeting: String = "Hello") {
    print("\(greeting), \(name)!")
}
greet(name: "Alice")
AHello, Alice!
BAlice, Hello!
CError: Missing argument for greeting
DHello, Friend!
Attempts:
2 left
💡 Hint
Only the name parameter is provided; the other uses its default.
❓ Predict Output
advanced
2:00remaining
Output with default parameters and argument labels
What is the output of this Swift code?
Swift
func calculateArea(width: Int = 10, height: Int = 5) -> Int {
    return width * height
}
print(calculateArea(height: 3))
A50
BError: Missing argument for width
C30
D15
Attempts:
2 left
💡 Hint
The width parameter uses its default value.
❓ Predict Output
advanced
2:00remaining
Default parameter with mutable variable
What will be printed after this code runs?
Swift
var count = 5
func increment(by amount: Int = count) -> Int {
    return amount + 1
}
count = 10
print(increment())
AError: Cannot use variable 'count' as default parameter
B11
C5
D6
Attempts:
2 left
💡 Hint
Swift requires default parameter values to be compile-time constants; variables are not allowed.
🧠 Conceptual
expert
2:00remaining
Why default parameter values must be compile-time constants
Why does Swift require default parameter values to be compile-time constants or literals?
ABecause Swift does not support functions with optional parameters
BBecause default values are evaluated once at compile time and cannot depend on runtime variables
CBecause default values are ignored during function calls
DBecause default values must be mutable to change during execution
Attempts:
2 left
💡 Hint
Think about when the default value is set and how it relates to program execution.

Practice

(1/5)
1. What is the main purpose of using default parameter values in Swift functions?
easy
A. To make functions run faster
B. To provide fallback values when arguments are not passed
C. To force the caller to always provide arguments
D. To declare variables inside the function

Solution

  1. Step 1: Understand default parameters

    Default parameter values allow a function to use a preset value if no argument is provided.
  2. Step 2: Identify the purpose

    This makes calling the function easier and avoids errors from missing arguments.
  3. Final Answer:

    To provide fallback values when arguments are not passed -> Option B
  4. Quick Check:

    Default parameters = fallback values [OK]
Hint: Default values fill in missing arguments automatically [OK]
Common Mistakes:
  • Thinking default values speed up code
  • Believing default values force arguments
  • Confusing default parameters with variable declarations
2. Which of the following is the correct way to declare a Swift function with a default parameter value?
easy
A. func greet(name: String) { name = "Guest"; print("Hello, \(name)!") }
B. func greet(name: String) = "Guest" { print("Hello, \(name)!") }
C. func greet(name: String default "Guest") { print("Hello, \(name)!") }
D. func greet(name: String = "Guest") { print("Hello, \(name)!") }

Solution

  1. Step 1: Review Swift default parameter syntax

    In Swift, default values are assigned using an equals sign after the parameter type.
  2. Step 2: Check each option

    func greet(name: String = "Guest") { print("Hello, \(name)!") } uses correct syntax: name: String = "Guest". Others have syntax errors.
  3. Final Answer:

    func greet(name: String = "Guest") { print("Hello, \(name)!") } -> Option D
  4. Quick Check:

    Default parameter syntax = type = value [OK]
Hint: Use = after type to set default value [OK]
Common Mistakes:
  • Placing default value outside parentheses
  • Using = after parameter name without type
  • Trying to assign default inside function body
3. What will be the output of this Swift code?
func multiply(_ a: Int, by b: Int = 2) -> Int {
    return a * b
}

print(multiply(5))
medium
A. Error: Missing argument for parameter 'b'
B. 5
C. 10
D. 25

Solution

  1. Step 1: Understand function parameters

    The function multiply takes two parameters: 'a' and 'b' with a default value of 2.
  2. Step 2: Evaluate the call multiply(5)

    Only 'a' is provided as 5, so 'b' uses default 2. Result is 5 * 2 = 10.
  3. Final Answer:

    10 -> Option C
  4. Quick Check:

    5 * default 2 = 10 [OK]
Hint: If argument missing, default value is used [OK]
Common Mistakes:
  • Expecting error for missing argument
  • Using first argument for both parameters
  • Confusing default value with multiplication factor
4. Identify the error in this Swift function declaration:
func greet(name: String = "User", _ age: Int) {
    print("Hello \(name), you are \(age) years old.")
}
medium
A. Default parameter must be last in the parameter list
B. Missing return type
C. Cannot use default values with String type
D. Function body syntax error

Solution

  1. Step 1: Check parameter order rules

    In Swift, parameters with default values must come after parameters without defaults.
  2. Step 2: Analyze given function

    'name' has a default but appears before 'age' which has no default. This causes a compile error.
  3. Final Answer:

    Default parameter must be last in the parameter list -> Option A
  4. Quick Check:

    Default params last = correct order [OK]
Hint: Place parameters with defaults after others [OK]
Common Mistakes:
  • Putting default parameters before non-default ones
  • Assuming return type is mandatory for void functions
  • Confusing type restrictions on default values
5. You want to write a Swift function formatMessage that takes a text and an optional prefix with default value "Info:". It should return a string combining prefix and text separated by a space. Which is the correct function and call to get output "Info: Hello"?
hard
A. func formatMessage(text: String, prefix: String = "Info:") -> String { return "\(prefix) \(text)" } print(formatMessage(text: "Hello"))
B. func formatMessage(prefix: String = "Info:", text: String) -> String { return "\(text) \(prefix)" } print(formatMessage(text: "Hello"))
C. func formatMessage(text: String, prefix: String) -> String { return "\(prefix) \(text)" } print(formatMessage(text: "Hello"))
D. func formatMessage(text: String, prefix: String = "Info:") -> String { return "\(text) \(prefix)" } print(formatMessage(text: "Hello"))

Solution

  1. Step 1: Define function with default parameter last

    Parameter with default 'prefix' must come after 'text' without default.
  2. Step 2: Check function call and output

    Calling with only 'text' uses default prefix "Info:" and returns "Info: Hello".
  3. Final Answer:

    func formatMessage(text: String, prefix: String = "Info:") -> String { return "\(prefix) \(text)" } print(formatMessage(text: "Hello")) -> Option A
  4. Quick Check:

    Default param last + call with one arg = correct output [OK]
Hint: Default params last, call with missing arg uses default [OK]
Common Mistakes:
  • Placing default parameter before non-default
  • Calling function without required parameters
  • Swapping order of prefix and text in output
Recommended

Ready to prove it?

Pass the test and this pattern moves unknown strong while earning +1 Grip toward your certificate.

10 questions~5 mineasy hard