Break and continue behavior in Swift - Interactive Code Practice

Practice - 5 Tasks

1fill in blank

easy

Complete the code to stop the loop when i equals 3.

Swift

for i in 1...5 {
    if i == 3 {
        [1]
    }
    print(i)
}

Drag options to blanks, or click blank then click option'

Abreak

Bexit

Creturn

Dcontinue

Attempts:

3 left

💡 Hint

Common Mistakes

Using continue instead of break, which skips only the current iteration.

The break statement stops the loop immediately when the condition is met.

2fill in blank

medium

Complete the code to skip printing the number 3 but continue the loop.

Swift

for i in 1...5 {
    if i == 3 {
        [1]
    }
    print(i)
}

Drag options to blanks, or click blank then click option'

Abreak

Bexit

Ccontinue

Dreturn

Attempts:

3 left

💡 Hint

Common Mistakes

Using break instead of continue, which stops the loop entirely.

The continue statement skips the current iteration and continues with the next one.

3fill in blank

hard

Fix the error in the loop to correctly skip the number 2 and stop at 4.

Swift

for i in 1...5 {
    if i == 2 {
        [1]
    }
    if i == 4 {
        break
    }
    print(i)
}

Drag options to blanks, or click blank then click option'

Acontinue

Bbreak

Creturn

Dexit

Attempts:

3 left

💡 Hint

Common Mistakes

Using break to skip 2, which stops the loop too early.

Use continue to skip printing 2, and break to stop at 4.

4fill in blank

hard

Fill both blanks to skip odd numbers and stop the loop when i is 8.

Swift

for i in 1...10 {
    if i [1] 2 != 0 {
        [2]
    }
    if i == 8 {
        break
    }
    print(i)
}

Drag options to blanks, or click blank then click option'

A%

Bcontinue

C==

Dbreak

Attempts:

3 left

💡 Hint

Common Mistakes

Using == instead of % to check odd numbers.

Using break instead of continue to skip odd numbers.

Use % to check if a number is odd and continue to skip it.

5fill in blank

hard

Fill all three blanks to print only even numbers less than 7.

Swift

for i in 1...10 {
    if i [1] 2 != 0 {
        [2]
    }
    if i [3] 7 {
        break
    }
    print(i)
}

Drag options to blanks, or click blank then click option'

A%

Bcontinue

C>=

D<

Attempts:

3 left

💡 Hint

Common Mistakes

Using < instead of >= to stop loop.

Using break instead of continue to skip odd numbers.

Check if number is odd with %, skip with continue, and stop loop when i ≥ 7 using >=.

Practice

1. What does the break statement do inside a Swift loop?

easy

A. Restarts the loop from the beginning.

B. Skips the current iteration and continues with the next one.

C. Pauses the loop until a condition is met.

D. Stops the entire loop immediately and exits it.

Solution

1. Step 1: Understand the role of break in loops

   The break statement immediately stops the loop and exits it, no matter where it is in the loop.

2. Step 2: Compare with other options

   continue skips to the next iteration, but break stops the loop entirely. Restarting or pausing the loop is not the behavior of break.

3. Final Answer:

   Stops the entire loop immediately and exits it. -> Option D

4. Quick Check:

   break stops loop [OK]

Hint: Break means stop the loop completely [OK]

Common Mistakes:

• Confusing break with continue
• Thinking break restarts the loop
• Assuming break pauses the loop

2. Which of the following is the correct syntax to skip the current iteration in a Swift for loop?

easy

A. skip

B. continue

C. break

D. stop

Solution

1. Step 1: Identify the keyword to skip iteration

   In Swift, continue is used to skip the rest of the current loop iteration and move to the next one.

2. Step 2: Verify other options

   break stops the loop, skip and stop are not valid Swift keywords for loops.

3. Final Answer:

   continue -> Option B

4. Quick Check:

   Skip iteration = continue [OK]

Hint: Use continue to skip current loop step [OK]

Common Mistakes:

• Using break instead of continue
• Using non-existent keywords like skip or stop
• Confusing continue with break

3. What will be the output of this Swift code?

for i in 1...5 {
    if i == 3 {
        break
    }
    print(i)
}

medium

A. 1 2

B. No output

C. 3 4 5

D. 1 2 3 4 5

Solution

1. Step 1: Analyze the loop and break condition

   The loop runs from 1 to 5. When i equals 3, break stops the loop immediately.

2. Step 2: Determine printed values before break

   Values 1 and 2 are printed before reaching 3. At 3, loop stops, so 3, 4, 5 are not printed.

3. Final Answer:

   1 2 -> Option A

4. Quick Check:

   Break stops at 3, prints before it [OK]

Hint: Break stops loop before printing 3 [OK]

Common Mistakes:

• Assuming break skips only current iteration
• Thinking all numbers print
• Confusing break with continue

4. Find the error in this Swift code snippet:

for i in 1...5 {
    if i == 3 {
        continue
    }
    if i == 6 {
        break
    }
    print(i)
}

medium

A. break should come before continue in the code.

B. continue cannot be used inside a for loop.

C. The loop will never break because i never reaches 6.

D. The range 1...5 is invalid.

Solution

1. Step 1: Check the loop range and conditions

   The loop runs from 1 to 5, so i will never be 6.

2. Step 2: Analyze the break condition

   Since i == 6 never occurs, the break statement will never execute, so the loop runs fully except skipping 3 due to continue.

3. Final Answer:

   The loop will never break because i never reaches 6. -> Option C

4. Quick Check:

   Break condition unreachable [OK]

Hint: Check if break condition can ever be true [OK]

Common Mistakes:

• Thinking continue is invalid in for loops
• Assuming break runs before continue always
• Not checking loop range carefully

5. You want to print all numbers from 1 to 10 except 5 and stop printing after 8. Which code snippet correctly uses break and continue in Swift?

hard

A. for i in 1...10 {
if i == 5 { continue }
if i > 8 { break }
print(i)
}

B. for i in 1...10 {
if i == 5 { break }
if i > 8 { continue }
print(i)
}

C. for i in 1...10 {
if i == 5 { continue }
if i > 7 { continue }
print(i)
}

D. for i in 1...10 {
if i == 5 { break }
if i > 8 { break }
print(i)
}

Solution

1. Step 1: Understand requirements

   Skip printing 5 (use continue) and stop printing after 8 (use break when > 8).

2. Step 2: Check each option

   for i in 1...10 { if i == 5 { continue } if i > 8 { break } print(i) } uses continue to skip 5 and break to stop after 8, matching requirements exactly.

3. Final Answer:

   for i in 1...10 { if i == 5 { continue } if i > 8 { break } print(i) } -> Option A

4. Quick Check:

   Continue skips 5, break stops loop after 8 [OK]

Hint: Continue skips, break stops loop [OK]

Common Mistakes:

• Using break to skip 5 instead of continue
• Using continue to stop loop after 8
• Mixing order of break and continue incorrectly