Why grouping is needed in SQL - Test Your Understanding

Practice - 5 Tasks

1fill in blank

easy

Complete the code to select the total sales for each product.

SQL

SELECT product_id, SUM(sales) FROM sales_data GROUP BY [1];

Drag options to blanks, or click blank then click option'

Asales

Bproduct_id

Ctotal

Ddate

Attempts:

3 left

💡 Hint

Common Mistakes

Grouping by sales instead of product_id.

Not using GROUP BY at all.

Grouping by product_id allows us to calculate the total sales per product.

2fill in blank

medium

Complete the code to find the average score for each student.

SQL

SELECT student_name, AVG(score) FROM exam_results GROUP BY [1];

Drag options to blanks, or click blank then click option'

Astudent_name

Bclass

Cscore

Dexam_date

Attempts:

3 left

💡 Hint

Common Mistakes

Grouping by score instead of student_name.

Forgetting to use GROUP BY.

Grouping by student_name lets us calculate the average score per student.

3fill in blank

hard

Fix the error in the query to get the count of orders per customer.

SQL

SELECT customer_id, COUNT(order_id) FROM orders [1] customer_id;

Drag options to blanks, or click blank then click option'

AORDER BY

BWHERE

CHAVING

DGROUP BY

Attempts:

3 left

💡 Hint

Common Mistakes

Using ORDER BY instead of GROUP BY.

Using WHERE clause incorrectly.

The GROUP BY clause groups rows by customer_id so COUNT counts orders per customer.

4fill in blank

hard

Fill both blanks to get the total sales and average price per category.

SQL

SELECT category, [1](sales), [2](price) FROM products GROUP BY category;

Drag options to blanks, or click blank then click option'

ASUM

BAVG

CCOUNT

DMAX

Attempts:

3 left

💡 Hint

Common Mistakes

Using COUNT instead of SUM or AVG.

Mixing up SUM and AVG functions.

Use SUM to add sales and AVG to find average price per category.

5fill in blank

hard

Fill all three blanks to get the number of employees, average salary, and maximum age per department.

SQL

SELECT department, [1](employee_id), [2](salary), [3](age) FROM employees GROUP BY department;

Drag options to blanks, or click blank then click option'

ACOUNT

BAVG

CMAX

DMIN

Attempts:

3 left

💡 Hint

Common Mistakes

Using MIN instead of MAX for age.

Using SUM instead of COUNT for employee count.

Use COUNT to count employees, AVG for average salary, and MAX for maximum age per department.

Practice

1. Why do we use GROUP BY in SQL queries?

easy

A. To organize rows into groups based on column values

B. To sort the results alphabetically

C. To delete duplicate rows from the table

D. To change the data type of a column

Solution

1. Step 1: Understand the purpose of grouping

   Grouping organizes rows that share the same value in specified columns into sets.

2. Step 2: Identify what GROUP BY does in SQL

   It collects rows into groups so aggregate functions like SUM or COUNT can be applied per group.

3. Final Answer:

   To organize rows into groups based on column values -> Option A

4. Quick Check:

   Grouping = Organizing rows by column values [OK]

Hint: Grouping collects rows by column values for summary [OK]

Common Mistakes:

• Confusing grouping with sorting
• Thinking grouping deletes duplicates
• Assuming grouping changes data types

2. Which of the following is the correct syntax to group data by the column department?

easy

A. SELECT department, COUNT(*) FROM employees GROUP BY department;

B. SELECT department, COUNT(*) FROM employees ORDER BY department;

C. SELECT department, COUNT(*) FROM employees WHERE department;

D. SELECT department, COUNT(*) FROM employees HAVING department;

Solution

1. Step 1: Identify the correct clause for grouping

   The GROUP BY clause groups rows by column values.

2. Step 2: Check each option's syntax

   SELECT department, COUNT(*) FROM employees GROUP BY department; uses GROUP BY department, which is correct. Others use clauses for sorting, filtering, or incomplete syntax.

3. Final Answer:

   SELECT department, COUNT(*) FROM employees GROUP BY department; -> Option A

4. Quick Check:

   Correct grouping uses GROUP BY [OK]

Hint: Use GROUP BY to group, not ORDER BY or WHERE [OK]

Common Mistakes:

• Using ORDER BY instead of GROUP BY
• Using WHERE to filter groups
• Using HAVING without aggregation

3. Given the table sales with columns region and amount, what will this query return?

SELECT region, SUM(amount) FROM sales GROUP BY region;

medium

A. Syntax error due to missing WHERE clause

B. List of all sales amounts without grouping

C. Sum of all sales amounts without region breakdown

D. Total sales amount for each region

Solution

1. Step 1: Understand the query components

   The query groups rows by region and sums amount per group.

2. Step 2: Predict the output

   It returns one row per region with the total sales amount for that region.

3. Final Answer:

   Total sales amount for each region -> Option D

4. Quick Check:

   GROUP BY region + SUM(amount) = total per region [OK]

Hint: GROUP BY + SUM = totals per group [OK]

Common Mistakes:

• Thinking it sums all rows ignoring groups
• Expecting a syntax error without WHERE
• Confusing grouping with filtering

4. Identify the error in this query:

SELECT department, COUNT(employee_id) FROM employees;

medium

A. SELECT must include WHERE clause

B. Missing GROUP BY clause for department

C. COUNT cannot be used with employee_id

D. employee_id should be in HAVING clause

Solution

1. Step 1: Analyze the SELECT and aggregation

   The query selects department and counts employee_id but lacks grouping.

2. Step 2: Understand SQL rules for aggregation

   When using aggregate functions with other columns, those columns must be in GROUP BY.

3. Final Answer:

   Missing GROUP BY clause for department -> Option B

4. Quick Check:

   Aggregate + column needs GROUP BY [OK]

Hint: Use GROUP BY with non-aggregated columns [OK]

Common Mistakes:

• Omitting GROUP BY with aggregates
• Misusing HAVING for columns
• Thinking COUNT can't use column names

5. You want to find the average salary per job title but only for job titles with more than 5 employees. Which query correctly uses grouping and filtering?

hard

A. SELECT job_title, AVG(salary) FROM employees GROUP BY job_title WHERE COUNT(*) > 5;

B. SELECT job_title, AVG(salary) FROM employees WHERE COUNT(*) > 5 GROUP BY job_title;

C. SELECT job_title, AVG(salary) FROM employees GROUP BY job_title HAVING COUNT(*) > 5;

D. SELECT job_title, AVG(salary) FROM employees HAVING COUNT(*) > 5 GROUP BY job_title;

Solution

1. Step 1: Understand filtering groups with HAVING

   To filter groups after aggregation, use HAVING, not WHERE.

2. Step 2: Check query order and clauses

   SELECT job_title, AVG(salary) FROM employees GROUP BY job_title HAVING COUNT(*) > 5; correctly groups by job_title and filters groups with more than 5 employees using HAVING.

3. Final Answer:

   SELECT job_title, AVG(salary) FROM employees GROUP BY job_title HAVING COUNT(*) > 5; -> Option C

4. Quick Check:

   Filter groups with HAVING after GROUP BY [OK]

Hint: Use HAVING to filter groups, not WHERE [OK]

Common Mistakes:

• Using WHERE to filter aggregated groups
• Placing HAVING before GROUP BY
• Confusing clause order in SQL