Challenge - 5 Problems
Scalar Subquery Master
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Test your skills under time pressure!
❓ query_result
intermediate2:00remaining
Output of scalar subquery in SELECT clause
Given the tables Employees and Departments, what is the output of the following query?
SELECT e.EmployeeID, e.Name, (SELECT d.DepartmentName FROM Departments d WHERE d.DepartmentID = e.DepartmentID) AS DeptName FROM Employees e WHERE e.EmployeeID = 3;
SQL
SELECT e.EmployeeID, e.Name, (SELECT d.DepartmentName FROM Departments d WHERE d.DepartmentID = e.DepartmentID) AS DeptName FROM Employees e WHERE e.EmployeeID = 3;
Attempts:
2 left
💡 Hint
Think about how the scalar subquery returns a single value for each row in Employees.
✗ Incorrect
The scalar subquery fetches the DepartmentName from Departments where DepartmentID matches the employee's DepartmentID. For EmployeeID 3, the department is Sales, so DeptName is 'Sales'.
🧠 Conceptual
intermediate1:30remaining
Understanding scalar subquery behavior
What happens if a scalar subquery in the SELECT clause returns more than one row?
Attempts:
2 left
💡 Hint
Scalar means a single value, not multiple.
✗ Incorrect
A scalar subquery must return exactly one value. If it returns more than one row, the database raises an error.
📝 Syntax
advanced2:00remaining
Identify the syntax error in scalar subquery usage
Which option contains a syntax error in using a scalar subquery in the SELECT clause?
SQL
SELECT e.EmployeeID, (SELECT DepartmentName FROM Departments WHERE DepartmentID = e.DepartmentID) AS DeptName FROM Employees e;
Attempts:
2 left
💡 Hint
Check if table aliases are consistent and if all tables are referenced properly.
✗ Incorrect
Option A references 'e.DepartmentID' but does not alias Employees as 'e', causing a syntax error.
❓ optimization
advanced2:30remaining
Optimizing scalar subquery in SELECT
Which query is more efficient when retrieving employee names with their department names?
Attempts:
2 left
💡 Hint
Consider how joins and subqueries affect performance.
✗ Incorrect
Using a JOIN (option A) is generally more efficient than a scalar subquery for each row because it avoids repeated subquery execution.
🔧 Debug
expert3:00remaining
Debugging unexpected NULL from scalar subquery
Given the query:
Why might DeptName be NULL for some employees even though their DepartmentID exists in Departments?
SELECT e.EmployeeID, e.Name, (SELECT d.DepartmentName FROM Departments d WHERE d.DepartmentID = e.DepartmentID) AS DeptName FROM Employees e;
Why might DeptName be NULL for some employees even though their DepartmentID exists in Departments?
Attempts:
2 left
💡 Hint
Check data consistency and matching conditions between tables.
✗ Incorrect
If DepartmentID values do not match exactly due to data type differences or extra spaces, the subquery returns no rows, resulting in NULL.