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SQLquery~10 mins

MIN and MAX functions in SQL - Interactive Code Practice

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Practice - 5 Tasks
Answer the questions below
1fill in blank
easy

Complete the code to find the highest salary from the employees table.

SQL
SELECT [1](salary) FROM employees;
Drag options to blanks, or click blank then click option'
AMIN
BMAX
CCOUNT
DSUM
Attempts:
3 left
💡 Hint
Common Mistakes
Using MIN instead of MAX.
Using SUM or COUNT which do different calculations.
2fill in blank
medium

Complete the code to find the lowest price in the products table.

SQL
SELECT [1](price) FROM products;
Drag options to blanks, or click blank then click option'
AAVG
BSUM
CMAX
DMIN
Attempts:
3 left
💡 Hint
Common Mistakes
Using MAX instead of MIN.
Using AVG or SUM which calculate averages or totals.
3fill in blank
hard

Fix the error in the code to get the maximum age from the users table.

SQL
SELECT [1](age) FROM users;
Drag options to blanks, or click blank then click option'
AMAX
BMIN
CMAX)
DMAX(
Attempts:
3 left
💡 Hint
Common Mistakes
Leaving unbalanced parentheses.
Using MIN instead of MAX.
4fill in blank
hard

Fill both blanks to find the minimum and maximum scores from the tests table.

SQL
SELECT [1](score) AS min_score, [2](score) AS max_score FROM tests;
Drag options to blanks, or click blank then click option'
AMIN
BSUM
CMAX
DCOUNT
Attempts:
3 left
💡 Hint
Common Mistakes
Using SUM or COUNT instead of MIN or MAX.
Swapping MIN and MAX functions.
5fill in blank
hard

Fill all three blanks to select the maximum price, minimum price, and average price from the items table.

SQL
SELECT [1](price) AS max_price, [2](price) AS min_price, [3](price) AS avg_price FROM items;
Drag options to blanks, or click blank then click option'
AMAX
BMIN
CAVG
DSUM
Attempts:
3 left
💡 Hint
Common Mistakes
Using SUM instead of AVG for average price.
Mixing up MIN and MAX functions.

Practice

(1/5)
1. What does the SQL function MIN() do when applied to a column of numbers?
easy
A. Calculates the average of the numbers
B. Finds the largest number in the column
C. Finds the smallest number in the column
D. Counts the total numbers in the column

Solution

  1. Step 1: Understand the purpose of MIN()

    The MIN() function is designed to find the smallest value in a column of data.
  2. Step 2: Compare with other functions

    Unlike MAX() which finds the largest, or AVG() which calculates average, MIN() specifically returns the minimum value.
  3. Final Answer:

    Finds the smallest number in the column -> Option C
  4. Quick Check:

    MIN() = smallest value [OK]
Hint: MIN() always returns the smallest value in a column [OK]
Common Mistakes:
  • Confusing MIN() with MAX()
  • Thinking MIN() calculates average
  • Using MIN() to count rows
2. Which of the following is the correct syntax to find the maximum salary from a table named Employees?
easy
A. SELECT MAX salary FROM Employees;
B. SELECT MAX{salary} FROM Employees;
C. SELECT MAX[salary] FROM Employees;
D. SELECT MAX(salary) FROM Employees;

Solution

  1. Step 1: Recall correct function syntax

    The correct syntax for SQL aggregate functions like MAX() requires parentheses around the column name.
  2. Step 2: Check syntax

    SELECT MAX(salary) FROM Employees; uses MAX(salary) which is correct. Forms without parentheses or using [] {} are invalid.
  3. Final Answer:

    SELECT MAX(salary) FROM Employees; -> Option D
  4. Quick Check:

    MAX() uses parentheses around column [OK]
Hint: Use parentheses around column name in MAX() [OK]
Common Mistakes:
  • Omitting parentheses in function calls
  • Using square or curly brackets instead of parentheses
  • Misspelling function names
3. Given the table Products with a column Price containing values (100, 250, 50, 400), what will the query SELECT MIN(Price), MAX(Price) FROM Products; return?
medium
A. (400, 50)
B. (50, 400)
C. (100, 250)
D. (0, 400)

Solution

  1. Step 1: Identify minimum price

    From the values (100, 250, 50, 400), the smallest price is 50.
  2. Step 2: Identify maximum price

    The largest price in the list is 400.
  3. Final Answer:

    (50, 400) -> Option B
  4. Quick Check:

    MIN = 50, MAX = 400 [OK]
Hint: MIN returns smallest, MAX returns largest value [OK]
Common Mistakes:
  • Mixing up MIN and MAX values
  • Assuming default zero minimum
  • Confusing order of returned values
4. What is wrong with this query to find the maximum age from the Users table?
SELECT MAX age FROM Users;
medium
A. Missing parentheses around the column name
B. MAX function cannot be used on numeric columns
C. Table name should be in quotes
D. MAX should be lowercase

Solution

  1. Step 1: Check function syntax

    The MAX() function requires parentheses around the column name, so MAX age is invalid syntax.
  2. Step 2: Verify other options

    MAX works on numeric columns, table names don't need quotes, and function names are case-insensitive in SQL.
  3. Final Answer:

    Missing parentheses around the column name -> Option A
  4. Quick Check:

    MAX() needs parentheses [OK]
Hint: Always use parentheses with MAX() [OK]
Common Mistakes:
  • Omitting parentheses in function calls
  • Thinking MAX() only works on strings
  • Adding unnecessary quotes around table names
5. You have a table Orders with columns OrderID, CustomerID, and TotalAmount. How would you write a query to find the highest order amount for each customer?
hard
A. SELECT CustomerID, MAX(TotalAmount) FROM Orders GROUP BY CustomerID;
B. SELECT MAX(TotalAmount) FROM Orders WHERE CustomerID;
C. SELECT CustomerID, MAX(TotalAmount) FROM Orders;
D. SELECT CustomerID, TotalAmount FROM Orders WHERE MAX(TotalAmount);

Solution

  1. Step 1: Understand grouping requirement

    To find the highest order amount per customer, we must group data by CustomerID.
  2. Step 2: Use MAX() with GROUP BY

    Using MAX(TotalAmount) with GROUP BY CustomerID returns the maximum order amount for each customer.
  3. Step 3: Why others fail

    Using MAX() in a WHERE clause is invalid, WHERE CustomerID; is meaningless, and selecting CustomerID with MAX() without GROUP BY causes an error because CustomerID is not aggregated.
  4. Final Answer:

    SELECT CustomerID, MAX(TotalAmount) FROM Orders GROUP BY CustomerID; -> Option A
  5. Quick Check:

    Use GROUP BY with MAX() for per-group max [OK]
Hint: Use GROUP BY with MAX() to get max per group [OK]
Common Mistakes:
  • Forgetting GROUP BY when using MAX per group
  • Using MAX() in WHERE clause incorrectly
  • Selecting columns without grouping