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SQLquery~30 mins

How GROUP BY changes query execution in SQL - Try It Yourself

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How GROUP BY changes query execution
📖 Scenario: You work at a small bookstore that keeps track of sales in a database table called sales. Each sale records the book_title, the genre of the book, and the quantity sold.Your manager wants to understand how many books were sold in total for each genre to decide which genres to promote.
🎯 Goal: Build a SQL query that groups sales by genre and calculates the total quantity sold for each genre using GROUP BY.
📋 What You'll Learn
Create a table called sales with columns book_title (text), genre (text), and quantity (integer).
Insert the exact sales data provided.
Write a query that groups the sales by genre.
Calculate the total quantity sold per genre using SUM(quantity).
Use GROUP BY genre in the query.
💡 Why This Matters
🌍 Real World
Grouping sales data by category helps businesses understand which product types sell best and make informed marketing decisions.
💼 Career
Data analysts and database developers often write GROUP BY queries to summarize and report data efficiently.
Progress0 / 4 steps
1
Create the sales table and insert data
Write SQL statements to create a table called sales with columns book_title (text), genre (text), and quantity (integer). Then insert these exact rows into sales: ('The Hobbit', 'Fantasy', 5), ('1984', 'Dystopian', 8), ('The Silmarillion', 'Fantasy', 3), ('Brave New World', 'Dystopian', 6), ('The Catcher in the Rye', 'Classic', 4).
SQL
Hint

Use CREATE TABLE to define the table and INSERT INTO to add the rows exactly as given.

2
Add a variable for the aggregation column
Define a variable or alias called total_quantity that will hold the sum of quantity for each group. This will be used in the next query step.
SQL
Hint

In SQL, you create an alias for the sum inside the SELECT statement using SUM(quantity) AS total_quantity. This will be done in the next step.

3
Write the query to group sales by genre and sum quantity
Write a SQL query that selects genre and the sum of quantity as total_quantity from the sales table. Use GROUP BY genre to group the rows by genre.
SQL
Hint

Use SELECT genre, SUM(quantity) AS total_quantity FROM sales GROUP BY genre to group and sum.

4
Complete the query with ordering by total quantity
Add an ORDER BY clause to the query to sort the results by total_quantity in descending order, so the genre with the highest sales appears first.
SQL
Hint

Use ORDER BY total_quantity DESC to sort from highest to lowest total quantity.

Practice

(1/5)
1. What does the GROUP BY clause do in an SQL query?
easy
A. It filters rows based on a condition.
B. It groups rows that have the same values in specified columns.
C. It deletes duplicate rows from the result.
D. It sorts the rows in ascending order.

Solution

  1. Step 1: Understand the purpose of GROUP BY

    The GROUP BY clause collects rows with the same values in specified columns into groups.
  2. Step 2: Compare with other SQL clauses

    Sorting is done by ORDER BY, filtering by WHERE, and removing duplicates by DISTINCT, not GROUP BY.
  3. Final Answer:

    It groups rows that have the same values in specified columns. -> Option B
  4. Quick Check:

    GROUP BY groups rows by column values [OK]
Hint: GROUP BY groups rows by column values, not sorting or filtering [OK]
Common Mistakes:
  • Confusing GROUP BY with ORDER BY
  • Thinking GROUP BY filters rows
  • Assuming GROUP BY removes duplicates
2. Which of the following is the correct syntax to group rows by the column department?
easy
A. SELECT department, COUNT(*) FROM employees WHERE department;
B. SELECT department, COUNT(*) FROM employees ORDER BY department;
C. SELECT department, COUNT(*) FROM employees GROUP BY department;
D. SELECT department, COUNT(*) FROM employees HAVING department;

Solution

  1. Step 1: Identify correct GROUP BY usage

    The GROUP BY clause must follow the FROM clause and specify the column to group by, here 'department'.
  2. Step 2: Check each option's syntax

    SELECT department, COUNT(*) FROM employees GROUP BY department; uses GROUP BY correctly. SELECT department, COUNT(*) FROM employees ORDER BY department; uses ORDER BY which sorts, not groups. SELECT department, COUNT(*) FROM employees WHERE department; uses WHERE incorrectly. SELECT department, COUNT(*) FROM employees HAVING department; uses HAVING without GROUP BY, which is invalid.
  3. Final Answer:

    SELECT department, COUNT(*) FROM employees GROUP BY department; -> Option C
  4. Quick Check:

    GROUP BY syntax: SELECT ... FROM ... GROUP BY column [OK]
Hint: GROUP BY follows FROM and lists columns to group by [OK]
Common Mistakes:
  • Using ORDER BY instead of GROUP BY
  • Using WHERE to group rows
  • Using HAVING without GROUP BY
3. Given the table sales with columns region and amount, what is the output of this query?
SELECT region, SUM(amount) FROM sales GROUP BY region;
medium
A. A list of regions with the total sales amount per region.
B. A list of all sales amounts without grouping.
C. An error because SUM() cannot be used with GROUP BY.
D. A list of regions sorted by amount.

Solution

  1. Step 1: Understand GROUP BY with aggregate functions

    The query groups rows by 'region' and calculates the sum of 'amount' for each group.
  2. Step 2: Analyze the output

    The result shows each region once with the total sales amount summed from all rows in that region.
  3. Final Answer:

    A list of regions with the total sales amount per region. -> Option A
  4. Quick Check:

    GROUP BY + SUM() = totals per group [OK]
Hint: GROUP BY with SUM() gives totals per group [OK]
Common Mistakes:
  • Expecting all rows without grouping
  • Thinking SUM() causes error with GROUP BY
  • Confusing grouping with sorting
4. What is wrong with this query?
SELECT department, employee_name, COUNT(*) FROM employees GROUP BY department;
medium
A. You cannot select employee_name without grouping by it or using an aggregate function.
B. COUNT(*) cannot be used with GROUP BY.
C. GROUP BY must come before SELECT.
D. The query is correct and will run without errors.

Solution

  1. Step 1: Check columns in SELECT with GROUP BY

    When using GROUP BY on 'department', all selected columns must be grouped or aggregated.
  2. Step 2: Identify the error

    'employee_name' is neither grouped nor aggregated, causing a syntax error.
  3. Final Answer:

    You cannot select employee_name without grouping by it or using an aggregate function. -> Option A
  4. Quick Check:

    Non-grouped columns must be aggregated [OK]
Hint: All selected columns must be grouped or aggregated [OK]
Common Mistakes:
  • Selecting non-grouped columns without aggregation
  • Thinking COUNT(*) is invalid with GROUP BY
  • Misplacing GROUP BY clause
5. You want to find departments with more than 5 employees. Which query correctly uses GROUP BY and HAVING to achieve this?
hard
A. SELECT department, COUNT(*) FROM employees GROUP BY department WHERE COUNT(*) > 5;
B. SELECT department, COUNT(*) FROM employees HAVING COUNT(*) > 5 GROUP BY department;
C. SELECT department, COUNT(*) FROM employees WHERE COUNT(*) > 5 GROUP BY department;
D. SELECT department, COUNT(*) FROM employees GROUP BY department HAVING COUNT(*) > 5;

Solution

  1. Step 1: Understand HAVING clause usage

    HAVING filters groups after aggregation, so it must come after GROUP BY.
  2. Step 2: Check query order and syntax

    SELECT department, COUNT(*) FROM employees GROUP BY department HAVING COUNT(*) > 5; correctly places HAVING after GROUP BY with condition COUNT(*) > 5. Other options misuse HAVING or WHERE clauses.
  3. Final Answer:

    SELECT department, COUNT(*) FROM employees GROUP BY department HAVING COUNT(*) > 5; -> Option D
  4. Quick Check:

    HAVING filters groups after GROUP BY [OK]
Hint: Use HAVING after GROUP BY to filter groups [OK]
Common Mistakes:
  • Using WHERE to filter aggregated results
  • Placing HAVING before GROUP BY
  • Confusing WHERE and HAVING clauses