Bird
Raised Fist0
SQLquery~30 mins

FULL OUTER JOIN behavior in SQL - Mini Project: Build & Apply

Choose your learning style10 modes available

Start learning this pattern below

Jump into concepts and practice - no test required

or
Recommended
Test this pattern10 questions across easy, medium, and hard to know if this pattern is strong
Understanding FULL OUTER JOIN Behavior in SQL
📖 Scenario: You work in a small bookstore. You have two lists: one with books currently in stock and another with books ordered but not yet arrived. You want to see all books, whether they are in stock, ordered, or both.
🎯 Goal: Create two tables in_stock and ordered with book titles and quantities. Then write a FULL OUTER JOIN query to combine these tables, showing all books with their stock and order quantities.
📋 What You'll Learn
Create a table called in_stock with columns book_title (text) and quantity_in_stock (integer).
Insert exactly these rows into in_stock: ('The Hobbit', 5), ('1984', 8), ('Dune', 3).
Create a table called ordered with columns book_title (text) and quantity_ordered (integer).
Insert exactly these rows into ordered: ('Dune', 7), ('The Catcher in the Rye', 4), ('1984', 2).
Write a FULL OUTER JOIN query joining in_stock and ordered on book_title.
Select book_title, quantity_in_stock, and quantity_ordered in the result.
💡 Why This Matters
🌍 Real World
Bookstores and inventory systems often need to combine data from current stock and incoming orders to manage inventory effectively.
💼 Career
Understanding FULL OUTER JOIN is important for database analysts and developers who work with relational databases to combine and analyze data from multiple sources.
Progress0 / 4 steps
1
Create the in_stock table and insert data
Create a table called in_stock with columns book_title (text) and quantity_in_stock (integer). Then insert these rows exactly: ('The Hobbit', 5), ('1984', 8), ('Dune', 3).
SQL
Hint

Use CREATE TABLE to make the table, then INSERT INTO with the exact rows.

2
Create the ordered table and insert data
Create a table called ordered with columns book_title (text) and quantity_ordered (integer). Then insert these rows exactly: ('Dune', 7), ('The Catcher in the Rye', 4), ('1984', 2).
SQL
Hint

Use CREATE TABLE and INSERT INTO like before, but for the ordered table.

3
Write the FULL OUTER JOIN query
Write a SELECT query that uses FULL OUTER JOIN to join in_stock and ordered on book_title. Select book_title, quantity_in_stock, and quantity_ordered.
SQL
Hint

Use FULL OUTER JOIN to combine all rows from both tables. Use COALESCE to show the book title from either table.

4
Complete the query with ordering
Add an ORDER BY clause to the query to sort the results by book_title alphabetically.
SQL
Hint

Use ORDER BY book_title at the end of the query to sort the results alphabetically.

Practice

(1/5)
1. What does a FULL OUTER JOIN do in SQL?
easy
A. Returns all rows from the left table and matching rows from the right table.
B. Returns only rows that have matching values in both tables.
C. Returns all rows from both tables, matching where possible and NULLs where no match exists.
D. Returns all rows from the right table and matching rows from the left table.

Solution

  1. Step 1: Understand join types

    INNER JOIN returns only matching rows; LEFT JOIN returns all from left plus matches; RIGHT JOIN returns all from right plus matches.
  2. Step 2: Define FULL OUTER JOIN behavior

    FULL OUTER JOIN returns all rows from both tables, matching where possible, and fills NULLs where no match exists.
  3. Final Answer:

    Returns all rows from both tables, matching where possible and NULLs where no match exists. -> Option C
  4. Quick Check:

    FULL OUTER JOIN = all rows both tables [OK]
Hint: Full outer join keeps all rows from both tables [OK]
Common Mistakes:
  • Confusing FULL OUTER JOIN with INNER JOIN
  • Thinking FULL OUTER JOIN returns only matches
  • Mixing up LEFT and RIGHT JOIN behavior
2. Which of the following is the correct syntax for a FULL OUTER JOIN between tables Employees and Departments on DeptID?
easy
A. SELECT * FROM Employees FULL OUTER JOIN Departments ON Employees.DeptID = Departments.DeptID;
B. SELECT * FROM Employees INNER JOIN Departments ON Employees.DeptID = Departments.DeptID;
C. SELECT * FROM Employees LEFT JOIN Departments ON Employees.DeptID = Departments.DeptID;
D. SELECT * FROM Employees RIGHT JOIN Departments ON Employees.DeptID = Departments.DeptID;

Solution

  1. Step 1: Identify FULL OUTER JOIN syntax

    The correct syntax uses the keywords FULL OUTER JOIN between the two tables with an ON condition.
  2. Step 2: Compare options

    SELECT * FROM Employees FULL OUTER JOIN Departments ON Employees.DeptID = Departments.DeptID; uses FULL OUTER JOIN correctly; others use INNER, LEFT, or RIGHT JOIN which are different join types.
  3. Final Answer:

    SELECT * FROM Employees FULL OUTER JOIN Departments ON Employees.DeptID = Departments.DeptID; -> Option A
  4. Quick Check:

    FULL OUTER JOIN syntax = SELECT * FROM Employees FULL OUTER JOIN Departments ON Employees.DeptID = Departments.DeptID; [OK]
Hint: FULL OUTER JOIN syntax includes FULL OUTER JOIN keywords [OK]
Common Mistakes:
  • Using INNER JOIN instead of FULL OUTER JOIN
  • Omitting FULL keyword and writing only OUTER JOIN
  • Confusing LEFT or RIGHT JOIN with FULL OUTER JOIN
3. Given these tables:

Table A:
ID | Name
1 | Alice
2 | Bob
4 | Dana

Table B:
ID | City
2 | Boston
3 | Chicago
4 | Denver

What is the result of this query?
SELECT A.ID, A.Name, B.City FROM A FULL OUTER JOIN B ON A.ID = B.ID ORDER BY A.ID;
medium
A. [ (1, 'Alice', NULL), (2, 'Bob', NULL), (3, NULL, 'Chicago'), (4, 'Dana', NULL) ]
B. [ (2, 'Bob', 'Boston'), (4, 'Dana', 'Denver') ]
C. [ (1, 'Alice', 'Boston'), (2, 'Bob', 'Chicago'), (3, NULL, 'Denver'), (4, 'Dana', NULL) ]
D. [ (1, 'Alice', NULL), (2, 'Bob', 'Boston'), (4, 'Dana', 'Denver'), (NULL, NULL, 'Chicago') ]

Solution

  1. Step 1: Match rows by ID using FULL OUTER JOIN

    IDs 2 and 4 appear in both tables, so their rows combine. ID 1 is only in A, ID 3 only in B.
  2. Step 2: Fill NULLs for missing matches

    For ID 1 (A only), City is NULL; for ID 3 (B only), A.ID=NULL, A.Name=NULL, City='Chicago'. ORDER BY A.ID ASC places NULL last: rows for 1,2,4 then NULL row.
  3. Final Answer:

    [ (1, 'Alice', NULL), (2, 'Bob', 'Boston'), (4, 'Dana', 'Denver'), (NULL, NULL, 'Chicago') ] -> Option D
  4. Quick Check:

    FULL OUTER JOIN returns all rows with NULLs for missing matches [OK]
Hint: FULL OUTER JOIN shows all rows, NULLs where no match [OK]
Common Mistakes:
  • Ignoring unmatched rows from either table
  • Assuming INNER JOIN behavior returns only matches
  • Misordering results by A.ID when NULLs exist
4. Consider this query:
SELECT * FROM Customers FULL OUTER JOIN Orders ON Customers.CustomerID = Orders.CustomerID WHERE Orders.OrderID IS NULL;

What is the likely purpose of this query?
medium
A. To find orders without customers.
B. To find customers who have no orders.
C. To find all customers and orders regardless of match.
D. To find customers with at least one order.

Solution

  1. Step 1: Understand FULL OUTER JOIN with WHERE filter

    The join returns all customers and orders; filtering WHERE Orders.OrderID IS NULL keeps rows where no matching order exists.
  2. Step 2: Interpret the filter effect

    Rows with NULL in Orders.OrderID mean customers without orders are selected.
  3. Final Answer:

    To find customers who have no orders. -> Option B
  4. Quick Check:

    Filter NULL in Orders = customers without orders [OK]
Hint: Filter NULL in joined table to find unmatched rows [OK]
Common Mistakes:
  • Thinking it finds orders without customers
  • Assuming it returns all rows without filtering
  • Confusing NULL filter with matching rows
5. You have two tables:

Products:
ProductID | Name
1 | Pen
2 | Pencil
3 | Eraser

Sales:
ProductID | Quantity
2 | 100
3 | 50
4 | 10

You want a query to list all products and sales quantities, including products with no sales and sales for unknown products.

Which query correctly achieves this?
hard
A. SELECT Products.ProductID, Products.Name, Sales.Quantity FROM Products FULL OUTER JOIN Sales ON Products.ProductID = Sales.ProductID;
B. SELECT Products.ProductID, Products.Name, Sales.Quantity FROM Products LEFT JOIN Sales ON Products.ProductID = Sales.ProductID;
C. SELECT Products.ProductID, Products.Name, Sales.Quantity FROM Sales RIGHT JOIN Products ON Sales.ProductID = Products.ProductID;
D. SELECT Products.ProductID, Products.Name, Sales.Quantity FROM Products INNER JOIN Sales ON Products.ProductID = Sales.ProductID;

Solution

  1. Step 1: Identify requirement for all products and all sales

    We want all products even if no sales, and all sales even if product unknown.
  2. Step 2: Choose join type

    FULL OUTER JOIN returns all rows from both tables, matching where possible, filling NULLs otherwise.
  3. Step 3: Check options

    SELECT Products.ProductID, Products.Name, Sales.Quantity FROM Products FULL OUTER JOIN Sales ON Products.ProductID = Sales.ProductID; uses FULL OUTER JOIN correctly; others exclude unmatched rows from one side.
  4. Final Answer:

    SELECT Products.ProductID, Products.Name, Sales.Quantity FROM Products FULL OUTER JOIN Sales ON Products.ProductID = Sales.ProductID; -> Option A
  5. Quick Check:

    FULL OUTER JOIN = all products and sales [OK]
Hint: Use FULL OUTER JOIN to include all rows from both tables [OK]
Common Mistakes:
  • Using LEFT JOIN excludes sales without products
  • Using INNER JOIN excludes unmatched rows
  • Confusing RIGHT JOIN direction with LEFT JOIN